Mongoose 如果引用数组中存在匹配项，如何获取父文档

我的猫鼬模式如下：

foodtruckuseratach.js

const mongoose = require('mongoose');
const Schema = mongoose.Schema;
const foodTruck = require('./foodtruck.js');
const foodTruckUser = require('./foodTruckUser.js');


const foodTruckUserAttached = new Schema({
    foodtruck_users: [{
        type: mongoose.Schema.ObjectId,
        ref: 'user',
        required: true
    }],
    foodtruck_id: {
        type: mongoose.Schema.ObjectId,
        ref: 'foodtruck',
        required: true
    }
}, {
    versionKey: false
});



module.exports = mongoose.model('foodtruckRegisteredUsers', foodTruckUserAttached);

现在我想在这里假设foodtruckuseratach的特定文档具有ID为1,2,3的foodtruck\u用户。现在我想要的是，我想要返回那个特定的文档，如果它有id=3的foodtruck\u用户。能做到吗

foodTruckUserAttached.find({foodtruck_users: 3}, function(err, ftua){
    if(!err){
        console.log(ftua)
    }
});