C++ C++；在循环/提示时生成新随机数时出现问题

我几乎完成了这个基本的骰子程序，但很难找出我在srand上做错了什么。它应该为用户随机掷2个骰子，用户可以选择保留他们掷的骰子（K）或再次掷骰子（R）。我想程序输出新的“随机”数字骰子辊每次用户输入“R”时，询问他们是否想再次辊，但相同的数字继续显示

程序的其余部分似乎工作得很好——用户与计算机对抗。当用户被要求保留或重新滚动时输入“R”时，如何为roll1和roll2生成新的数字

#include <stdlib.h> /// need this for srand() -- for random numbers
#include <time.h> /// need this for time() -- time
#include <iostream>  /// need this for cout<< and cin>>
using namespace std; /// need this for cout<< and cin>>

int main()
{
    int iseed = (int)time(0);
    srand(iseed);

    cout << "Beat the computer! \n";

    int roll1 = 1+rand()%6; /// make a random number for die # 1 for user
    int roll2 = 1+rand()%6; /// make a random number for die # 2 for user
    int UserRoll = roll1 + roll2; /// totals the sum of die 1 and die 2 for the user
    char keep;

    do
    {
    cout << "You rolled a " << roll1 << " and a " << roll2 << " for a total of: " << UserRoll << "\n";
    cout << "\n";

        do
        {
        cout << "Would you like to keep this total, or roll again? \n";
        cout << "\n";
        cout << "Enter \"K\" for keep and \"R\" for roll again: \n";
        cin >> keep;

            if (keep != 'K' && keep != 'R')

            {
                cout << "That is not a valid choice. Please choose Y to keep your total or N to roll again. " << endl;
                cout << "\n";
            }

            } while(keep != 'K' && keep != 'R');



            if (keep == 'R')
            {
                cout << "You chose R--let's roll again. \n";
            }


            else
            {
            cout << "Great! Your total is " << UserRoll << "\n";
            }
        } while (keep == 'R');

    int roll3 = 1+rand()%6; /// make a random number for die # 1 for computer
    int roll4 = 1+rand()%6; /// make a random number for die # 2 for computer
    int ComputerRoll = roll3 + roll4; /// totals the sum of die 1 and die 2 for the computer


    cout << "The computer rolled a " << roll3 << " and a " << roll4 << " for a total of: " << ComputerRoll << "\n";
    cout << "\n";

    if (ComputerRoll < UserRoll)
    {
        cout << "Congratulations! You won! \n";
    }

    if (ComputerRoll > UserRoll)
    {
        cout << "Sorry. You lose. \n";
    }

    if (ComputerRoll == UserRoll)
    {
        cout << "It's a tie. \n";
    }

return 0;
}

/*
SAMPLE RUNS:
------------
Beat the computer!
You rolled a 4 and a 6 for a total of: 10

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 4 and a 6 for a total of: 10

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
K
Great! Your total is 10
The computer rolled a 4 and a 6 for a total of: 10

It's a tie.

Process returned 0 (0x0)   execution time : 8.763 s
Press any key to continue.

*/

#include///srand（）需要此选项--用于随机数
#include///需要这个时间（）--时间
#include///需要这张卡吗
使用命名空间std；///cout>
int main（）
{
int iseed=（int）时间（0）；
srand（iseed）；
cout您只滚动了一次，并再次使用滚动的结果。如果用户再次按R，它将再次滚动以更新新的数字。为此，只需添加

void roll(){
    roll1 = 1+rand()%6; /// make a random number for die # 1 for user
   roll2 = 1+rand()%6; /// make a random number for die # 2 for user
UserRoll = roll1 + roll2; /// totals the sum of die 1 and die 2 for the user

}

记住：roll1、roll2和UserRoll应该在roll（）函数之前全局声明

在main（）方法之前，并在用户按R键时调用它，以及
之后

cout太好了！我终于有了一个有效的程序！如果你认为有什么方法可以让这个更整洁、更容易阅读，请告诉我：

#include <stdlib.h> /// need this for srand() -- for random numbers
#include <time.h> /// need this for time() -- time
#include <iostream>  /// need this for cout<< and cin>>
using namespace std; /// need this for cout<< and cin>>


int roll1,roll2,UserRoll;
char keep;

void roll()
    {
        roll1 = 1+rand()%6; /// make a random number for die # 1 for user
        roll2 = 1+rand()%6; /// make a random number for die # 2 for user
        UserRoll = roll1 + roll2; /// totals the sum of die 1 and die 2 for the user
    }

int main()
{
    int iseed = (int)time(0);
    srand(iseed);

    cout << "Beat the computer! \n";

    roll();

    do
    {
    cout << "You rolled a " << roll1 << " and a " << roll2 << " for a total of: " << UserRoll << "\n";
    cout << "\n";

        do
        {
        cout << "Would you like to keep this total, or roll again? \n";
        cout << "\n";
        cout << "Enter \"K\" for keep and \"R\" for roll again: \n";
        cin >> keep;

            if (keep != 'K' && keep != 'R')

            {
                cout << "That is not a valid choice. Please choose Y to keep your total or N to roll again. " << endl;
                cout << "\n";
            }

            } while(keep != 'K' && keep != 'R');



            if (keep == 'R')
            {
                cout << "You chose R--let's roll again. \n";
                roll();
            }


            else
            {
            cout << "Great! Your total is " << UserRoll << "\n";
            }
        } while (keep == 'R');

    int roll3 = 1+rand()%6; /// make a random number for die # 1 for computer
    int roll4 = 1+rand()%6; /// make a random number for die # 2 for computer
    int ComputerRoll = roll3 + roll4; /// totals the sum of die 1 and die 2 for the computer


    cout << "The computer rolled a " << roll3 << " and a " << roll4 << " for a total of: " << ComputerRoll << "\n";
    cout << "\n";

    if (ComputerRoll < UserRoll)
    {
        cout << "Congratulations! You won! \n";
    }

    if (ComputerRoll > UserRoll)
    {
        cout << "Sorry. You lose. \n";
    }

    if (ComputerRoll == UserRoll)
    {
        cout << "It's a tie. \n";
    }

return 0;
}

/*
SAMPLE RUNS:
------------
Beat the computer!
You rolled a 2 and a 4 for a total of: 6

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 4 and a 4 for a total of: 8

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 4 and a 1 for a total of: 5

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 5 and a 5 for a total of: 10

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 6 and a 1 for a total of: 7

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 5 and a 2 for a total of: 7

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 6 and a 6 for a total of: 12

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
K
Great! Your total is 12
The computer rolled a 3 and a 1 for a total of: 4

Congratulations! You won!

Process returned 0 (0x0)   execution time : 19.487 s
Press any key to continue.
*/

#include///srand（）需要此选项--用于随机数
#include///需要这个时间（）--时间
#include///需要这张卡吗
使用名称空间std；///cout>
int roll1、roll2、UserRoll；
炭保持；
无效卷（）
{
roll1=1+rand（）%6；///为用户的die#1创建一个随机数
roll2=1+rand（）%6；///为用户的die#2创建一个随机数
UserRoll=roll1+roll2；///合计用户的骰子1和骰子2之和
}
int main（）
{
int iseed=（int）时间（0）；
srand（iseed）；
您是否尝试通过在循环中调用
srand
来重新为其设定种子？@macroland，这有什么意义？
srand（）
应该只调用一次。@SidS，以保证获得一个新的随机数序列。@macroland——正如Sid S所说，
srand（）
只应调用一次。已对代码进行编辑以使其更清晰。请签出并接受编辑，您可以在返回0；之前将if语句更改为multiple if-else if，从而获得编辑。您可以提高代码的时间效率，因为当任何条件变为真时，它不会检查其余条件。yo你可以读更多关于它的内容
#include <stdlib.h> /// need this for srand() -- for random numbers
#include <time.h> /// need this for time() -- time
#include <iostream>  /// need this for cout<< and cin>>
using namespace std; /// need this for cout<< and cin>>


int roll1,roll2,UserRoll;
char keep;

void roll()
    {
        roll1 = 1+rand()%6; /// make a random number for die # 1 for user
        roll2 = 1+rand()%6; /// make a random number for die # 2 for user
        UserRoll = roll1 + roll2; /// totals the sum of die 1 and die 2 for the user
    }

int main()
{
    int iseed = (int)time(0);
    srand(iseed);

    cout << "Beat the computer! \n";

    roll();

    do
    {
    cout << "You rolled a " << roll1 << " and a " << roll2 << " for a total of: " << UserRoll << "\n";
    cout << "\n";

        do
        {
        cout << "Would you like to keep this total, or roll again? \n";
        cout << "\n";
        cout << "Enter \"K\" for keep and \"R\" for roll again: \n";
        cin >> keep;

            if (keep != 'K' && keep != 'R')

            {
                cout << "That is not a valid choice. Please choose Y to keep your total or N to roll again. " << endl;
                cout << "\n";
            }

            } while(keep != 'K' && keep != 'R');



            if (keep == 'R')
            {
                cout << "You chose R--let's roll again. \n";
                roll();
            }


            else
            {
            cout << "Great! Your total is " << UserRoll << "\n";
            }
        } while (keep == 'R');

    int roll3 = 1+rand()%6; /// make a random number for die # 1 for computer
    int roll4 = 1+rand()%6; /// make a random number for die # 2 for computer
    int ComputerRoll = roll3 + roll4; /// totals the sum of die 1 and die 2 for the computer


    cout << "The computer rolled a " << roll3 << " and a " << roll4 << " for a total of: " << ComputerRoll << "\n";
    cout << "\n";

    if (ComputerRoll < UserRoll)
    {
        cout << "Congratulations! You won! \n";
    }

    if (ComputerRoll > UserRoll)
    {
        cout << "Sorry. You lose. \n";
    }

    if (ComputerRoll == UserRoll)
    {
        cout << "It's a tie. \n";
    }

return 0;
}

/*
SAMPLE RUNS:
------------
Beat the computer!
You rolled a 2 and a 4 for a total of: 6

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 4 and a 4 for a total of: 8

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 4 and a 1 for a total of: 5

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 5 and a 5 for a total of: 10

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 6 and a 1 for a total of: 7

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 5 and a 2 for a total of: 7

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 6 and a 6 for a total of: 12

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
K
Great! Your total is 12
The computer rolled a 3 and a 1 for a total of: 4

Congratulations! You won!

Process returned 0 (0x0)   execution time : 19.487 s
Press any key to continue.
*/