C++ HM编码器16.4模式为2
我想确定CU是否使用HEVC参考软件HM 16.4编码器进行了帧内或帧间编码 在TEncSlice.cpp中,压缩CTU后,使用m_pcCuEncoder->compressCtu pCtu;,我应该能够判断CU是内部编码还是内部编码 因此,我检查了TComDataCU*pCtu的m_pePredMode阵列: 代码的输出首先给出了预期的结果。对于第一帧,我首先只得到一个MODE_intra。但对于某些CTU,我也得到了两个,这对我来说没有意义,因为2不应该描述预测模式 类似地,在帧间p帧中,我主要得到零模式_inter,一些一模式_INTRA,这是正常的。但我也得到了一些二。示例输出的一部分如下所示,每行对应一个64x64 CTU:C++ HM编码器16.4模式为2,c++,hevc,h.265,C++,Hevc,H.265,我想确定CU是否使用HEVC参考软件HM 16.4编码器进行了帧内或帧间编码 在TEncSlice.cpp中,压缩CTU后,使用m_pcCuEncoder->compressCtu pCtu;,我应该能够判断CU是内部编码还是内部编码 因此,我检查了TComDataCU*pCtu的m_pePredMode阵列: 代码的输出首先给出了预期的结果。对于第一帧,我首先只得到一个MODE_intra。但对于某些CTU,我也得到了两个,这对我来说没有意义,因为2不应该描述预测模式 类似地,在帧间p帧中,我
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有人知道这些是什么意思吗?我检查了这是否与跳过模式相对应,但跳过标志和2s之间没有相关性。好吧,我得到了这个问题的答案: 如果CU具有模式2,这意味着CU未编码。这种情况下会发生这种情况,因为CU位于图片的边界之外 编码的序列分辨率为416x240,CTU大小为64x64。所以连续有6.5个CTU 这就解释了为什么每7个CTU,我就有2个模式
enum PredMode
{
MODE_INTER = 0, ///< inter-prediction mode
MODE_INTRA = 1, ///< intra-prediction mode
NUMBER_OF_PREDICTION_MODES = 2,
};
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