C# MVC在一个视图中显示多个模型
我想在一个视图中访问多个模型。我有DAL文件夹和DbContextC# MVC在一个视图中显示多个模型,c#,asp.net,asp.net-mvc,entity-framework,razor,C#,Asp.net,Asp.net Mvc,Entity Framework,Razor,我想在一个视图中访问多个模型。我有DAL文件夹和DbContext class CvContext : DbContext { public CvContext() : base("CvContext") { } public DbSet<LinkModel> Links { get; set; } public DbSet<AboutModel> Abouts { get; set; } public DbSet<Portfo
class CvContext : DbContext
{
public CvContext() : base("CvContext")
{
}
public DbSet<LinkModel> Links { get; set; }
public DbSet<AboutModel> Abouts { get; set; }
public DbSet<PortfolioModel> Portfolios { get; set; }
public DbSet<SkillModel> Skills { get; set; }
protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
modelBuilder.Conventions.Remove<PluralizingTableNameConvention>();
}
}
Index.cshtml
@model IEnumerable<MvcCv.Models.LinkModel>
<ul>
@foreach (var item in Model)
{
<li>
<a href="@Html.DisplayFor(modelItem => item.LinkUrl)">
@Html.DisplayFor(modelItem => item.LinkName)
<span class="icon"></span>
<span class="menu-icon">
<img src="@Url.Content(item.LinkImage)" alt="" />
</span>
</a>
</li>
}
</ul>
@model IEnumerable
@foreach(模型中的var项目)
{
-
}
如何接触所有型号?我将使用foreach作为模型链接中的项。谢谢。您应该创建一个视图模型,如下所示:
public class FooViewModel
{
public IEnumerable<LinkModel> Links { get; set; }
public IEnumerable<AboutModel> Abouts { get; set; }
public IEnumerable<PortfolioModel> Portfolios { get; set; }
public IEnumerable<SkillModel> Skills { get; set; }
}
然后将视图中的模型更改为FooViewModel
,所有属性都将在其中可用
@model FooViewModel
<ul>
@foreach (var item in Model.Links)
{
<li>
@item
</li>
}
</ul>
<ul>
@foreach (var item in Model.Links)
{
<li>
@item
</li>
}
</ul>
// ....etc, obviously change the outputs as needed.
@model FooViewModel
@foreach(Model.Links中的var项)
{
-
@项目
}
@foreach(Model.Links中的var项)
{
-
@项目
}
//…等,根据需要明显改变输出。
以及@Html.DisplayFor helper对于本例来说是个不错的选择?创建一个包装其他模型的ViewModel…比如CvContext?但内部模型不是DAL,对吗?是的,不要传递DAL,创建一个类,它有4个列表。从DAL中填充这些列表(在控制器操作方法中执行此操作),并将此新类传递给视图。。。。这是视图模型的概念。。。这是一个模型,但它只包含特定视图所需的所有信息…谢谢,我将尝试使用此方法。对于每个模型组合,我们必须根据此解决方案创建ViewModel,但这是一个好的选择吗?动态模型呢?
public ActionResult Index()
{
var model = new FooViewModel();
model.Links = db.Links.ToList();
model.Abouts = db.Abouts.ToList();
model.Portfolios = db.Portfolios.ToList();
model.Skills = db.Skills.ToList();
return View(model);
}
@model FooViewModel
<ul>
@foreach (var item in Model.Links)
{
<li>
@item
</li>
}
</ul>
<ul>
@foreach (var item in Model.Links)
{
<li>
@item
</li>
}
</ul>
// ....etc, obviously change the outputs as needed.
//suppose you have two Models
public class student
{
public int Id
public string Name{get;set;}
}
public class class
{
public int Id
public string Name{get;set;}
}
// Now combine these two class Model in single Model for example:
public class Mixmodel
{
public Student student {get;set;}
public Class class {get;set;}
}
//here is the Home controller of the Index view
@model projectName.MixModel
@foreach(var item in Model.class)
{
@html.displayfor(item.class.Name)
}
@foreach(var item in Model.student)
{
@html.displayfor(item.student.Name)
}