C# C-如何将json字符串转换为类

如何将json字符串转换为类

这是我的json

{
    "$id": "1",
    "Result": {
        "$id": "2",
        "dateTime": 23821964,
        "list": [{
            "$id": "3",
            "UserId": 302,
            "UID": "302_UID",
            "Title": "شیدکو",
            "Sender": "شیدکو",
            "Answer": "",
            "Comment": "test 2",
            "ProductTitle": null,
            "CommentId": 77,
            "Logo": "http://example.com/Commercial/User/302/Logo/tmpF0BF.jpg",
            "Date": 24302057,
            "AnswerDate": -2123661683,
            "AnswerEdit": false,
            "CommentEdit": false,
            "ForfeitCount": 0,
            "RewardCount": 0,
            "ThisCountReport": 2,
            "Reported": [{
                "$id": "4",
                "BlockerId": 355,
                "Title": "محتوای غیر اخلاقی",
                "Date": -19527396,
                "ForfeitCount": 0,
                "RewardCount": 0
            }, {
                "$id": "5",
                "BlockerId": 355,
                "Title": "محتوای غیر مرتبط",
                "Date": -19527382,
                "ForfeitCount": 0,
                "RewardCount": 0
            }],
            "Gem": 0
        }, {
            "$id": "6",
            "UserId": 302,
            "UID": "302_UID",
            "Title": "شیدکو",
            "Sender": "شیدکو",
            "Answer": "",
            "Comment": "test 2",
            "ProductTitle": null,
            "CommentId": 77,
            "Logo": "http://example.com/Commercial/User/302/Logo/tmpF0BF.jpg",
            "Date": 24302057,
            "AnswerDate": -2123661683,
            "AnswerEdit": false,
            "CommentEdit": false

        }]

    },
    "StatusCode": "Created",
    "Description": null
}

我做了这些步骤，但什么也没发生

JObject json1 = JObject.Parse(strMyJson);
    _CommentAdmindto flight = Newtonsoft.Json.JsonConvert.DeserializeObject<_CommentAdmindto>(json1.ToString());
    _CommentAdmindto deserializedProduct = JsonConvert.DeserializeObject<_CommentAdmindto>(json);
    _CommentAdmindto deserializedProduct1 = ConvertJsonToClass<_CommentAdmindto>(strMyJson);
    JsonSerializer serializer = new JsonSerializer();
    _CommentAdmindto p = (_CommentAdmindto)serializer.Deserialize(new JTokenReader(strMyJson), typeof(_CommentAdmindto));

下面是我的类和函数：

public static T ConvertJsonToClass<T>( string json)
    {
        System.Web.Script.Serialization.JavaScriptSerializer serializer = new System.Web.Script.Serialization.JavaScriptSerializer();
        return serializer.Deserialize<T>(json);
    }

}

public class _CommentAdmindto
{
    public long dateTime { get; set; }

    public IQueryable<CommentDtoAdmin> list { get; set; }
}

public class CommentDtoAdmin
{
    public long UserId { get; set; }
    public string UID { get; set; }
    public string Title { get; set; }
    public string Sender { get; set; }
    public string Answer { get; set; }
    public string Comment { get; set; }

    public string ProductTitle { get; set; }
    public long CommentId { get; set; }

    public string Logo { get; set; }
    public long Date { get; set; }

    public long AnswerDate { get; set; }

    public bool AnswerEdit { get; set; }

    public bool CommentEdit { get; set; }
}

---

我认为您的json字符串没有正确的语法。它看起来像是数组的']'结尾，缺少最后一个'}'

---

这就是VisualStudio编辑器在删除所有“\”后用字符串生成json文件时告诉我的，您似乎试图以许多不同的方式进行反序列化，但您没有与json真正匹配的完整结构。您缺少表示完整对象的外部类，并且至少Newtonsoft.Json无法反序列化为IQueryable，因此我将其更改为IEnumerable

string strMyJson = "{\"$id\":\"1\",\"Result\":{\"$id\":\"2\",\"dateTime\":23826985,\"list\":[{\"$id\":\"3\",\"UserId\":302,\"UID\":\"302_UID\",\"Title\":\"شیدکو\",\"Sender\":\"شیدکو\",\"Answer\":\"\",\"Comment\":\"test 2\",\"ProductTitle\":null,\"CommentId\":77,\"Logo\":\"http://www.domain.com/Commercial/User/302/Logo/tmpF0BF.jpg\",\"Date\":24307078,\"AnswerDate\":-2123656662,\"AnswerEdit\":false,\"CommentEdit\":false,\"ForfeitCount\":0,\"RewardCount\":0,\"ThisCountReport\":2,\"Reported\":[{\"$id\":\"4\",\"BlockerId\":355,\"Title\":\"محتوای غیر اخلاقی\",\"Date\":-19527396,\"ForfeitCount\":0,\"RewardCount\":0},{\"$id\":\"5\",\"BlockerId\":355,\"Title\":\"محتوای غیر مرتبط\",\"Date\":-19527382,\"ForfeitCount\":0,\"RewardCount\":0}],\"Gem\":0},{\"$id\":\"6\",\"UserId\":302,\"UID\":\"302_UID\",\"Title\":\"شیدکو\",\"Sender\":\"شیدکو\",\"Answer\":\"\",\"Comment\":\"test 2\",\"ProductTitle\":null,\"CommentId\":77,\"Logo\":\"http://www.domain.com/Commercial/User/302/Logo/tmpF0BF.jpg\",\"Date\":24307078,\"AnswerDate\":-2123656662,\"AnswerEdit\":false,\"CommentEdit\":false}],\"StatusCode\":\"Created\",\"Description\":null}}";


var result = JsonConvert.DeserializeObject<Wrapper>(strMyJson);

类的外观如下所示：

public class Wrapper
{
    public _CommentAdmindto Result { get; set; }
}
public class _CommentAdmindto
{
    public long dateTime { get; set; }

    public IEnumerable<CommentDtoAdmin> list { get; set; }
}

CommentDtoAdmin看起来是一样的。

---

尽管我必须说这只对反序列化有帮助。

对于无效的c名称，您的模型应该类似于此，但您可以使用JsonProperty属性：

public class Reported
{
    [JsonProperty("$id")]
    public string id { get; set; }
    public int BlockerId { get; set; }
    public string Title { get; set; }
    public int Date { get; set; }
    public int ForfeitCount { get; set; }
    public int RewardCount { get; set; }
}

public class List
{
    [JsonProperty("$id")]
    public string id { get; set; }
    public int UserId { get; set; }
    public string UID { get; set; }
    public string Title { get; set; }
    public string Sender { get; set; }
    public string Answer { get; set; }
    public string Comment { get; set; }
    public object ProductTitle { get; set; }
    public int CommentId { get; set; }
    public string Logo { get; set; }
    public int Date { get; set; }
    public int AnswerDate { get; set; }
    public bool AnswerEdit { get; set; }
    public bool CommentEdit { get; set; }
    public int ForfeitCount { get; set; }
    public int RewardCount { get; set; }
    public int ThisCountReport { get; set; }
    public List<Reported> Reported { get; set; }
    public int Gem { get; set; }
}

public class Result
{
    [JsonProperty("$id")]
    public string id { get; set; }
    public int dateTime { get; set; }
    public List<List> list { get; set; }
}

public class RootObject
{
    [JsonProperty("$id")]
    public string id { get; set; }
    public Result Result { get; set; }
    public string StatusCode { get; set; }
    public object Description { get; set; }
}

现在可以反序列化为

var result = JsonConvert.DeserializeObject<RootObject>(jsonstring);

顺便说一句：在使用json时，可以帮助猜测您的模型。

首先，$id属性是json.NET添加的合成属性，用于跟踪和保留对同一对象的多个引用。有关详细信息，请参阅

因此，如果临时删除$id属性，则可以将JSON上载到并获取以下数据模型：

public class Reported
{
    public int BlockerId { get; set; }
    public string Title { get; set; }
    public int Date { get; set; }
    public int ForfeitCount { get; set; }
    public int RewardCount { get; set; }
}

public class CommentDtoAdmin
{
    public int UserId { get; set; }
    public string UID { get; set; }
    public string Title { get; set; }
    public string Sender { get; set; }
    public string Answer { get; set; }
    public string Comment { get; set; }
    public object ProductTitle { get; set; }
    public int CommentId { get; set; }
    public string Logo { get; set; }
    public int Date { get; set; }
    public int AnswerDate { get; set; }
    public bool AnswerEdit { get; set; }
    public bool CommentEdit { get; set; }
    public int ForfeitCount { get; set; }
    public int RewardCount { get; set; }
    public int ThisCountReport { get; set; }
    public List<Reported> Reported { get; set; }
    public int Gem { get; set; }
}

public class Result
{
    public int dateTime { get; set; }
    public List<CommentDtoAdmin> list { get; set; }
}

public class RootObject
{
    public Result Result { get; set; }
    public string StatusCode { get; set; }
    public string Description { get; set; }
}

请注意，Json.NET没有将接口IQueryable反序列化为具体类型的内置逻辑，因此我不得不将属性保留为public List{get；set；}。您始终可以使用以下命令从列表生成可查询项：

---

示例。

这不是答案-如果问题有问题，你应该在注释中注明。我编辑它，json现在可以正常工作，但我无法理解我的问题。我想这是一个重复的问题@Hussaintatel在你的链接上，他们没有将其添加到类中，请查看你的json与你的模型不匹配谢谢，这确实更好，但我现在遇到了另一个错误，正在处理新的错误。System.Web.Extensions.dll中发生了类型为“System.ArgumentException”的异常，但未在用户代码中处理其他信息：类型为“System.Collections.Generic.List1[AdminApp.\u CommentReported]”的对象无法转换为类型为“System.Linq.IQueryable1”[AdminApp._CommentReported]”。如果您使用的是Visual Studio 2015，它具有内置的JSON到类功能。只需打开一个新的空类文件并编辑>粘贴特殊>JSON作为类。也适用于XML。并不总是完美的，但非常好。在这种情况下，它唯一缺少的是ID变量上的属性装饰。

var settings = new JsonSerializerSettings
{
    PreserveReferencesHandling = PreserveReferencesHandling.Objects,
};
var root = JsonConvert.DeserializeObject<RootObject>(json1, settings);

var json2 = JsonConvert.SerializeObject(root, Formatting.Indented, settings);

var queryable = root.Result.list.AsQueryable();