C# 读取JSON文件会将项添加到同一类的另一个属性的列表中

我有一系列的课程，如下所示：

public class Class1 : IClass
{
    public List<Class2> Class2List { get { return Class3Instance.Class2List; } }

    public Class3 Class3Instance { get; set; }
}

public class Class2
{
    public string Field1 { get; set; }
    public int Field2 { get; set;}
}

public class Class3
{
    public List<Class2> Class2List { get; set; }
}

然后，如果我立即反序列化JSON并再次序列化它，我会得到以下结果：

{
  "Class3Instance": {
    "Class2List2": [
      {
        "Field1": "Member1",
        "Field2": 1
      },
      {
        "Field1": "Member2",
        "Field2": 2
      },
      {
        "Field1": "Member3",
        "Field2": 3
      },
      {
        "Field1": "Member4",
        "Field2": 4
      },
      {
        "Field1": "Member5",
        "Field2": 5
      },
      {
        "Field1": "Member1",
        "Field2": 1
      },
      {
        "Field1": "Member2",
        "Field2": 2
      },
      {
        "Field1": "Member3",
        "Field2": 3
      },
      {
        "Field1": "Member4",
        "Field2": 4
      },
      {
        "Field1": "Member5",
        "Field2": 5
      }
    ]
  },
  "Class2List": [
    {
      "Field1": "Member1",
      "Field2": 1
    },
    {
      "Field1": "Member2",
      "Field2": 2
    },
    {
      "Field1": "Member3",
      "Field2": 3
    },
    {
      "Field1": "Member4",
      "Field2": 4
    },
    {
      "Field1": "Member5",
      "Field2": 5
    },
    {
      "Field1": "Member1",
      "Field2": 1
    },
    {
      "Field1": "Member2",
      "Field2": 2
    },
    {
      "Field1": "Member3",
      "Field2": 3
    },
    {
      "Field1": "Member4",
      "Field2": 4
    },
    {
      "Field1": "Member5",
      "Field2": 5
    }
  ]
}

如您所见，当我反序列化JSON时，Class2List成员已被复制。

正如@mortb所说：

问题在于Class3Instance.Class2List的快捷方式，在JSON中序列化的所述列表的任何成员将被添加到快捷方式的引用中，除了所述引用以前在同一JSON文件中的成员之外

这是因为反序列化不知道如何区分Class1中的shorcut引用Class3Instance.Class2List和Class3中的Class2List，因此不知道是否应该忽略快捷方式字段上的序列化或反序列化操作

---

为了解决这个问题，无论是合同解析器还是将属性[JsonIgnore]设置为快捷方式引用，都可以解决这个问题。

Class2代码丢失了它与此无关，但我也会添加它，谢谢你的提醒，你能发布一个？@aloisdg吗？我试图将我的应用程序中的类结构简化为只与问题相关的类结构，例如你给我看的示例，我应该提供重现问题的JSON还是按预期重现问题的解决方案？@OscarGuillamon：为什么不运行简化的示例来创建序列化输出，然后反序列化该输出。您可以将这些结果包括在问题中，并告诉我们输出是如何出错的。到目前为止，任何想回答你问题的人都必须自己创建这样一个程序，这将花费太多的时间来回答你的问题。

{
  "Class3Instance": {
    "Class2List2": [
      {
        "Field1": "Member1",
        "Field2": 1
      },
      {
        "Field1": "Member2",
        "Field2": 2
      },
      {
        "Field1": "Member3",
        "Field2": 3
      },
      {
        "Field1": "Member4",
        "Field2": 4
      },
      {
        "Field1": "Member5",
        "Field2": 5
      }
    ]
  },
  "Class2List": [
    {
      "Field1": "Member1",
      "Field2": 1
    },
    {
      "Field1": "Member2",
      "Field2": 2
    },
    {
      "Field1": "Member3",
      "Field2": 3
    },
    {
      "Field1": "Member4",
      "Field2": 4
    },
    {
      "Field1": "Member5",
      "Field2": 5
    }
  ]
}

{
  "Class3Instance": {
    "Class2List2": [
      {
        "Field1": "Member1",
        "Field2": 1
      },
      {
        "Field1": "Member2",
        "Field2": 2
      },
      {
        "Field1": "Member3",
        "Field2": 3
      },
      {
        "Field1": "Member4",
        "Field2": 4
      },
      {
        "Field1": "Member5",
        "Field2": 5
      },
      {
        "Field1": "Member1",
        "Field2": 1
      },
      {
        "Field1": "Member2",
        "Field2": 2
      },
      {
        "Field1": "Member3",
        "Field2": 3
      },
      {
        "Field1": "Member4",
        "Field2": 4
      },
      {
        "Field1": "Member5",
        "Field2": 5
      }
    ]
  },
  "Class2List": [
    {
      "Field1": "Member1",
      "Field2": 1
    },
    {
      "Field1": "Member2",
      "Field2": 2
    },
    {
      "Field1": "Member3",
      "Field2": 3
    },
    {
      "Field1": "Member4",
      "Field2": 4
    },
    {
      "Field1": "Member5",
      "Field2": 5
    },
    {
      "Field1": "Member1",
      "Field2": 1
    },
    {
      "Field1": "Member2",
      "Field2": 2
    },
    {
      "Field1": "Member3",
      "Field2": 3
    },
    {
      "Field1": "Member4",
      "Field2": 4
    },
    {
      "Field1": "Member5",
      "Field2": 5
    }
  ]
}