如何同时启动两个foreach循环c#wpf

是否可以在两个标签中同时使用字符逐个显示字符串 两个不同的Dispatcher.BeginInvoke（新操作（（））

我有两个这样的foreach循环：

        string str1 = "NUMBER OF PASSED:" + "\t\t" + passed1.ToString() + Environment.NewLine + "NUMBER OF FAILED:" + "\t" + failed1.ToString();

        foreach (var ch1 in str1)
        {
            var char_by_char1 = ch1;
            Dispatcher.BeginInvoke(new Action(() =>
            {                    
                first_result.Content += char_by_char1.ToString();
                System.Threading.Thread.Sleep(5);
            }), DispatcherPriority.Background);
        }


        string str2 = "NUMBER OF PASSED:" + "\t\t" + passed2.ToString() + Environment.NewLine + "NUMBER OF FAILED:" + "\t" + failed2.ToString();

        foreach (var ch2 in str2)
        {
            var char_by_char2 = ch2;
            Dispatcher.BeginInvoke(new Action(() =>
            {
                second_result.Content += char_by_char2.ToString();
                System.Threading.Thread.Sleep(5);
            }), DispatcherPriority.Background);
        }

var dispatcherObj = Dispatcher.CurrentDispatcher;

string str1 = "NUMBER OF PASSED:" + "\t\t" + passed1.ToString() + Environment.NewLine + "NUMBER OF FAILED:" + "\t" + failed1.ToString();

var tsk1 = Task.Factory.StartNew(()=>
{
    foreach (var ch1 in str1)
    {
        var char_by_char1 = ch1;
        dispatcherObj.Invoke(new Action(() =>
        {                    
            first_result.Content += char_by_char1.ToString();
            System.Threading.Thread.Sleep(5);
        }), DispatcherPriority.Background);
    }
});


string str2 = "NUMBER OF PASSED:" + "\t\t" + passed2.ToString() + Environment.NewLine + "NUMBER OF FAILED:" + "\t" + failed2.ToString();

var tsk2 = Task.Factory.StartNew(()=>
{
    foreach (var ch2 in str2)
    {
        var char_by_char2 = ch2;
        dispatcherObj.Invoke(new Action(() =>
        {
            second_result.Content += char_by_char2.ToString();
            System.Threading.Thread.Sleep(5);
        }), DispatcherPriority.Background);
    }
});

---

你不能用第三方物流来代替，比如：

        string str1 = "NUMBER OF PASSED:" + "\t\t" + passed1.ToString() + Environment.NewLine + "NUMBER OF FAILED:" + "\t" + failed1.ToString();

        foreach (var ch1 in str1)
        {
            var char_by_char1 = ch1;
            Dispatcher.BeginInvoke(new Action(() =>
            {                    
                first_result.Content += char_by_char1.ToString();
                System.Threading.Thread.Sleep(5);
            }), DispatcherPriority.Background);
        }


        string str2 = "NUMBER OF PASSED:" + "\t\t" + passed2.ToString() + Environment.NewLine + "NUMBER OF FAILED:" + "\t" + failed2.ToString();

        foreach (var ch2 in str2)
        {
            var char_by_char2 = ch2;
            Dispatcher.BeginInvoke(new Action(() =>
            {
                second_result.Content += char_by_char2.ToString();
                System.Threading.Thread.Sleep(5);
            }), DispatcherPriority.Background);
        }

var dispatcherObj = Dispatcher.CurrentDispatcher;

string str1 = "NUMBER OF PASSED:" + "\t\t" + passed1.ToString() + Environment.NewLine + "NUMBER OF FAILED:" + "\t" + failed1.ToString();

var tsk1 = Task.Factory.StartNew(()=>
{
    foreach (var ch1 in str1)
    {
        var char_by_char1 = ch1;
        dispatcherObj.Invoke(new Action(() =>
        {                    
            first_result.Content += char_by_char1.ToString();
            System.Threading.Thread.Sleep(5);
        }), DispatcherPriority.Background);
    }
});


string str2 = "NUMBER OF PASSED:" + "\t\t" + passed2.ToString() + Environment.NewLine + "NUMBER OF FAILED:" + "\t" + failed2.ToString();

var tsk2 = Task.Factory.StartNew(()=>
{
    foreach (var ch2 in str2)
    {
        var char_by_char2 = ch2;
        dispatcherObj.Invoke(new Action(() =>
        {
            second_result.Content += char_by_char2.ToString();
            System.Threading.Thread.Sleep(5);
        }), DispatcherPriority.Background);
    }
});

我正在任务/非UI线程上运行循环，并使用Dispatcher.Invoke发布UI更改。答案是肯定的

但不像你在那里做的那样

Dispatcher begininvoke将在UI线程上运行您的操作

这个线程是用来处理UI的所有事情，包括你可能不想打断的事情，比如显示你的新角色

作为经验法则

永远不要休眠UI线程，因为它会冻结UI

在本例中，“other”调用无法执行任何操作，因为您烧掉了试图在其上运行它的线程。启动的第一个调用是在一段时间内唯一可以执行任何操作的调用，在它完成之前，您将看不到结果

我建议您删除以下行：

  System.Threading.Thread.Sleep(5);

现在不会有延迟，但您的ui不会被冻结

使该操作异步

插入一行：

await Task.Delay(5);

睡觉的地方

你预计会耽搁多久

5是5毫秒

也许你想要500或5000

然后你释放了这个线程，你认为他们应该有机会表现得更像你期望的那样

根据您正试图执行的操作，您可能会更好地附加到操作列表中，每个操作都会更改一个字母

---

然后，您可以使用wait task.delay进行迭代以引入延迟。

您的意思还不完全清楚：该代码可以工作，但将在第一个结果中显示str1，然后在第二个结果中显示str2。您的意思是要交错它们（对于它们，您只需要一个循环，并且在每个循环中调用两次）？为什么你想一个角色一个角色地在事件循环中单独发帖？感谢的Prateek Shrivastava这正是我想要的：D