C# 使用TCP通过网络发送位图时出现问题

C# 使用TCP通过网络发送位图时出现问题,c#,networking,bitmap,C#,Networking,Bitmap,我正在尝试用C#设置一个简单的桌面监控程序。我已经搜索了将近一个小时试图找到一个工作模型,但是我发现的任何东西要么抛出异常,要么太复杂,调用模糊的函数 我能够将屏幕捕获到位图实例,我曾尝试发送它,但目前程序运行正常并关闭。客户端抛出一个异常,因为连接没有正确关闭(懒惰的我!),但没有发生其他任何事情。没有写入输出文件,没有任何内容 这是服务器的代码 using System.IO; using System.Drawing; using System.Drawing.Imaging; using

我正在尝试用C#设置一个简单的桌面监控程序。我已经搜索了将近一个小时试图找到一个工作模型,但是我发现的任何东西要么抛出异常,要么太复杂,调用模糊的函数

我能够将屏幕捕获到位图实例,我曾尝试发送它,但目前程序运行正常并关闭。客户端抛出一个异常,因为连接没有正确关闭(懒惰的我!),但没有发生其他任何事情。没有写入输出文件,没有任何内容

这是服务器的代码

using System.IO;
using System.Drawing;
using System.Drawing.Imaging;
using System.Net;
using System.Net.Sockets;
using System;

class ScreenCapture
{
    public static void Main()
    {
        try
        {
            TcpListener srv = new TcpListener(IPAddress.Any, 51530);
            srv.Start(1);
            TcpClient client = srv.AcceptTcpClient();
            NetworkStream ns = client.GetStream();
            StreamWriter send = new StreamWriter(ns);
            StreamReader read = new StreamReader(ns);

            Rectangle screenshot;
            Bitmap bitmap;
            screenshot = System.Windows.Forms.Screen.PrimaryScreen.WorkingArea;
            bitmap = new Bitmap(screenshot.Width, screenshot.Height, PixelFormat.Format32bppArgb);
            Graphics g = Graphics.FromImage(bitmap);
            g.CopyFromScreen(screenshot.Left, screenshot.Top, 0, 0, screenshot.Size);
            g.Dispose();
            MemoryStream m = new MemoryStream();
            bitmap.Save(m, ImageFormat.Jpeg);

            byte[] data = m.ToArray();
            Console.WriteLine(data.ToString());
            send.Write(m);
        }
        catch (Exception ex)
        {
            Console.WriteLine(ex.ToString());
            Console.ReadKey();
        }
    }
}
以下是客户代码:

using System;
using System.IO;
using System.Net;
using System.Net.Sockets;
using System.Drawing;
using System.Drawing.Imaging;

class RetrieveScreenShot
{
    public static void Main()
    {
        try
        {
            TcpClient client = new TcpClient("127.0.0.1", 51530);
            NetworkStream ns = client.GetStream();
            Image receivedImage = Image.FromStream(ns);
            receivedImage.Save("output.bmp");
            ns.Close();
            client.Close();
        }
        catch (Exception ex)
        {
            Console.WriteLine(ex.ToString());
            Console.ReadLine();
        }
    }
}
接收器端的代码没有太大变化,只是文件扩展名

以下答案有助于解释这些变化:


首先,即使它工作正常,您的文件扩展名也是错误的<对我来说,code>ImageFormat.Jpeg意味着
output.jpg
。除此之外,我看到的另一件事是
send.Write(m)
可能更好,因为
发送.写入(数据)目前这并不重要,因为我还在测试。我仍然可以查看照片,无论它有什么扩展。给出发送、写入(数据);现在就试试。我想试着正确地关闭连接,并将
TcpClient
包装到一个using块中,至少在服务器端(以消除该异常)。尝试发送“data”而不是“m”,但它仍然做了同样的事情。我将把TcpClient更改为using
try
{
   TcpListener srv = new TcpListener(IPAddress.Any, 51530);
   srv.Start(1);
   TcpClient client = srv.AcceptTcpClient();
   NetworkStream ns = client.GetStream();

   Rectangle screenshot;
   Bitmap bitmap;
   screenshot = System.Windows.Forms.Screen.PrimaryScreen.WorkingArea;
   bitmap = new Bitmap(screenshot.Width, screenshot.Height, PixelFormat.Format32bppArgb);
   Graphics g = Graphics.FromImage(bitmap);
   g.CopyFromScreen(screenshot.Left, screenshot.Top, 0, 0, screenshot.Size);
   g.Dispose();

   MemoryStream m = new MemoryStream();

   //you can also just save to network stream and skip the copy but i kept it for demo
   bitmap.Save(m, ImageFormat.Jpeg);

   //reset the memory stream to start of stream
   m.Position = 0;
   //copy memory stream to network stream
   m.CopyTo(ns);
   //make sure copy is completed
   m.Flush();
   m.Close();

   //Makes sure everything is sent before closing it
   ns.Flush();

   //The Image.FromStream() seems to wait for the stream to be finished/closed.
   client.Close();

}
catch (Exception ex)
{
   Console.WriteLine(ex.ToString());
   Console.ReadKey();
}