C# 代码为'；t从函数返回字符串

我有以下问题：我想检查gameName是否包含函数中可用的预定义字符串，但不知何故他没有将它们传输回来。我真的不知道为什么，因为它们是在函数中声明的，应该传输回主要部分。顺便说一下，OpenFileDialog1的输入是一个名为：hl1-sp-the-infinite-shift.7z的文件

    using System;
    using System.Collections.Generic;
    using System.ComponentModel;
    using System.Data;
    using System.Drawing;
    using System.Linq;
    using System.Text;
    using System.Windows.Forms;
    using System.Diagnostics;
    using System.IO;

    namespace MapTap2
    {
        public partial class Form1 : Form
        {
            public Form1()
            {
                InitializeComponent();
    }
    public string CheckGame(string sourceName, string gamename)
    { 
        string hl1 = "hl1";
        string hl2 = "hl2";
        string hl2ep2 = "hl2-ep2";
        string hl2ep1 = "hl2-ep1";
        string bs = "bs";
        string prtl = "prtl";
        string prtl2 = "prtl";
        string op = "op";
        bool gamebool;



        gamebool = sourceName.Contains(hl1);
        if (gamebool == true)
        {
            gamename = "hl1";
            return gamename;
        }
            gamebool = sourceName.Contains(hl2);
        if (gamebool == true)
        {
            gamename = "hl2";
            return gamename;
        }
        gamebool = sourceName.Contains(hl2ep2);
        if (gamebool == true)
        {
            gamename = "hl2-ep2";
            return gamename;
        }
        gamebool = sourceName.Contains(hl2ep1);
        if (gamebool == true)
        {
            gamename = "hl2-ep1";
            return gamename;
        }

        gamebool = sourceName.Contains(bs);
        if (gamebool == true)
        {
            gamename = "bs";
            return gamename;
        }
        gamebool = sourceName.Contains(prtl);
        if (gamebool == true)
        {
            gamename = "prtl";
            return gamename;
        }
        gamebool = sourceName.Contains(prtl2);
        if (gamebool == true)
        {
            gamename = "prtl2";
            return gamename;
        }
        gamebool = sourceName.Contains(op);
        if (gamebool == true)
        {
            gamename = "op";
            return gamename;
        }
        else
        {
            gamename = "You sure that this file is from PP?";
            return gamename;
        }

    }

    private void Form1_Load(object sender, EventArgs e)
    {
        openFileDialog1.InitialDirectory = @"C:\Users\";
        openFileDialog1.Filter = "7zip archives|*.7z|All files (*.*)|*.*";
        openFileDialog1.FilterIndex = 2;
        openFileDialog1.RestoreDirectory = true;
    }

    private void cmdCompress_Click(object sender, EventArgs e)
    {
        string sourceName = "";
        string targetFolderName = "testy";


        Stream myStream;
        OpenFileDialog openFileDialog1 = new OpenFileDialog();

        if(openFileDialog1.ShowDialog() == DialogResult.OK)
        {
            if ((myStream = openFileDialog1.OpenFile()) != null )
            {
                sourceName = openFileDialog1.FileName;
                lblconsole.Text = sourceName;


                ProcessStartInfo p = new ProcessStartInfo();
                p.FileName = "7za.exe";

                p.Arguments = " e " + sourceName + " -o" + targetFolderName;

                Process x = Process.Start(p);
                x.WaitForExit(); 

                //Check the Game Version of the archive (line 20)
                string gamename = "If you see this in Debug you failed.\n Y U NO MAKE WORKING CODE?";
                CheckGame(sourceName, gamename);
                lblconsole.Text = gamename;
                }                    

        }



    }


}

---

}调用函数时，实际上并没有将返回值设置为任何值。试着做

string gamename = "If you see this in Debug you failed.\n Y U NO MAKE WORKING CODE?";
gamename = CheckGame(sourceName, gamename);
lblconsole.Text = gamename;

作为补充说明，这里有很多优化。其中一个正在更改

if

s和

return

s的外观：

    if (sourceName.Contains(hl1))
        return = hl1;

---

快乐编码

这是演示问题所需的最少代码量吗？如果没有，请编辑您的问题。在旁注上。。。了解如何使用switch语句！每当你有长if-else语句时，这是一个很好的指示器，这是一个很好的迹象，表明你应该使用switch@詹维德补充说。如果这解决了您的问题，请随意标记为已接受的答案。谢谢，欢迎光临。下一次的提示是，只需发布与手头问题相关的代码，这样其他人就不必过多筛选：）