C# 连接4中的对角线匹配
嘿，伙计们，我正在用C语言开发一个Windows窗体应用程序中的Connect 4游戏，一切都很好，我只是被困在对角线部分。这是我为左下对角线检查开发的，但我不确定它是否完美工作。它是从第一块瓷砖开始工作的，它是1，1，但是我不能告诉你其他的瓷砖。我还想知道如何为另一边的对角线比赛创建另一种方法。gameButtons是我的2D数组，我的表单是6行7列这是我的方法：C# 连接4中的对角线匹配,c#,forms,C#,Forms,嘿，伙计们，我正在用C语言开发一个Windows窗体应用程序中的Connect 4游戏，一切都很好，我只是被困在对角线部分。这是我为左下对角线检查开发的，但我不确定它是否完美工作。它是从第一块瓷砖开始工作的，它是1，1，但是我不能告诉你其他的瓷砖。我还想知道如何为另一边的对角线比赛创建另一种方法。gameButtons是我的2D数组，我的表单是6行7列这是我的方法： private void checkForDiaMatch() { int countBlue = 0;
private void checkForDiaMatch()
{
int countBlue = 0;
int countRed = 0;
for (int i = 0; i < 6; i++)
{
if (gameButtons[i, i].BackColor == Color.Blue)
{
countBlue++;
}
else
{
countBlue = 0;
}
if (gameButtons[i, i].BackColor == Color.Red)
{
countRed++;
}
else
{
countRed = 0;
}
if (countBlue >= 4)
{
MessageBox.Show("There is a blue diagonal match");
MessageBox.Show("Blue wins!");
}
else if (countRed >= 4)
{
MessageBox.Show("There is a red diagonal match");
MessageBox.Show("Red wins!");
}
}
}
也许最有用的方法是在纸上画出你的图板和索引，然后写下任意对角线连接的索引4：
------------------------------- -------------------------------
5 | | | | | | |5,6| 5 | | | | | | | |
--+---+---+---+---+---+---+---+ --+---+---+---+---+---+---+---+
4 | | | | | |4,5| | 4 | |4,1| | | | | |
--+---+---+---+---+---+---+---+ --+---+---+---+---+---+---+---+
3 | | | | |3,4| | | 3 | | |3,2| | | | |
--+---+---+---+---+---+---+---+ --+---+---+---+---+---+---+---+
2 | | | |2,3| | | | 2 | | | |2,3| | | |
--+---+---+---+---+---+---+---+ --+---+---+---+---+---+---+---+
1 | | | | | | | | 1 | | | | |1,4| | |
--+---+---+---+---+---+---+---+ --+---+---+---+---+---+---+---+
0 | | | | | | | | 0 | | | | | | | |
--+---+---+---+---+---+---+---+ --+---+---+---+---+---+---+---+
| 0 | 1 | 2 | 3 | 4 | 5 | 6 | | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
private bool CompletesDiagonal(int pieceRow, int pieceCol)
{
var colorToMatch = Board[pieceRow, pieceCol]; // Board is a ConsoleColor[7,6] array
var matchingPieces = 1; // We will count the original piece as a match
// Check forward slash direction '/'
// First check down/left (decrement both row and column up to 3 times)
for (int counter = 1; counter < 4; counter++)
{
var row = pieceRow - counter;
var col = pieceCol - counter;
// Make sure we stay within our board
if (row < Board.GetLowerBound(0) || col < Board.GetLowerBound(1)) { break; }
if (Board[row, col] == colorToMatch)
{
matchingPieces++;
if (matchingPieces == 4) return true;
}
else { break; }
}
// Next check up/right (increment both row and column up to 3 times)
for (int counter = 1; counter < 4; counter++)
{
var row = pieceRow + counter;
var col = pieceCol + counter;
// Make sure we stay within our board
if (row > Board.GetUpperBound(0) || col > Board.GetUpperBound(1)) { break; }
// Check for a match
if (Board[row, col] == colorToMatch)
{
matchingPieces++;
if (matchingPieces == 4) return true;
}
else { break; }
}
// If we got this far, no match was found in forward slash direction,
// so reset our counter and check the back slash direction '\'
matchingPieces = 1;
// First check down/right (decrement row and increment column)
for (int counter = 1; counter < 4; counter++)
{
var row = pieceRow - counter;
var col = pieceCol + counter;
// Make sure we stay within our board
if (row < Board.GetLowerBound(0) || col > Board.GetUpperBound(1)) { break; }
// Check for a match
if (Board[row, col] == colorToMatch)
{
matchingPieces++;
if (matchingPieces == 4) return true;
}
else { break; }
}
// Next check up/left (increment row and decrement column)
for (int counter = 1; counter < 4; counter++)
{
var row = pieceRow + counter;
var col = pieceCol - counter;
// Make sure we stay within our board
if (row > Board.GetUpperBound(0) || col < Board.GetLowerBound(1)) { break; }
// Check for a match
if (Board[row, col] == colorToMatch)
{
matchingPieces++;
if (matchingPieces == 4) return true;
}
else { break; }
}
// If we've gotten this far, then we haven't found a match
return false;
}
我会考虑两件事：1。如何手动检测对角线？2.你什么时候调用这个方法，在那个时候，你有什么信息？你不应该每次都要分析整个电路板。我的猜测是，每次有人放置一个片段时，你都会调用它，并且你知道该片段的位置。从那个位置，你会如何检测对角线？但我不能告诉其他瓷砖-为什么不？你用其他瓷砖测试过这个方法吗？您应该有，并且让这样的测试看到单元测试可用将帮助您编写和调试代码。对于有关堆栈溢出的问题，您需要提供一个可靠地再现您遇到的任何问题的好方法，详细解释该代码的作用和您想要的内容，并详细解释您迄今为止尝试解决该问题的方法，还有一个详细的解释，说明什么是你无法理解的。@RufusL所以，当用户在某处放置一个平铺时，就会调用这个方法。我得到的唯一信息是用户点击了某个地方，这就是为什么我创建了检查整个电路板的方法。我还有两个方法检查垂直和水平，我计划稍后在创建所有需要的方法时将它们放在一个方法中。该块已存储在变量中，但仅存储用户单击的块，而不是块的结束位置。@PeterDuniho我测试了其他块，但它似乎不起作用。它只从左上角的瓷砖开始，沿对角线向下，直到没有更多的瓷砖为止。@jk485921这样你就知道他们点击的位置，大概你也知道他们刚刚放在黑板上的那块瓷砖落在哪里了，对吧？如果你只是从放置的棋子上检查对角线，你应该是好的。为你制作实际游戏的道具，只是为了能够写出答案！：D@RufusL嘿，谢谢你详尽的回答和帮助。我已经尝试了你的方法，在改变了一些之后，比如我从0到3的计数器和类。不过，我仍然得到一个错误，在某些情况下我超出了数组的界限。@RufusL说实话，我真的不知道为什么我得到的索引超出了范围，因为编译器返回给我的每个值对于我的信息都是正确的。例如，我得到的索引超出了数组的范围，因为列变量是4。@jk485921抱歉，您仍然有问题。如果您使用winform，我建议您添加一些日志记录，您可以只记录到多行文本框或其他内容，或者在调试器中单步执行代码。如果您在测试时注意到只有某些模式触发了异常，那么在您知道要触发它之前设置一个断点，这样您就不必单步执行太多的循环。祝你好运@哈哈！谢谢有时候，别人的问题变成了一个有趣的挑战。当我完成游戏时，我真的玩得很开心！！：
private bool CompletesDiagonal(int pieceRow, int pieceCol)
{
var colorToMatch = Board[pieceRow, pieceCol]; // Board is a ConsoleColor[7,6] array
var matchingPieces = 1; // We will count the original piece as a match
// Check forward slash direction '/'
// First check down/left (decrement both row and column up to 3 times)
for (int counter = 1; counter < 4; counter++)
{
var row = pieceRow - counter;
var col = pieceCol - counter;
// Make sure we stay within our board
if (row < Board.GetLowerBound(0) || col < Board.GetLowerBound(1)) { break; }
if (Board[row, col] == colorToMatch)
{
matchingPieces++;
if (matchingPieces == 4) return true;
}
else { break; }
}
// Next check up/right (increment both row and column up to 3 times)
for (int counter = 1; counter < 4; counter++)
{
var row = pieceRow + counter;
var col = pieceCol + counter;
// Make sure we stay within our board
if (row > Board.GetUpperBound(0) || col > Board.GetUpperBound(1)) { break; }
// Check for a match
if (Board[row, col] == colorToMatch)
{
matchingPieces++;
if (matchingPieces == 4) return true;
}
else { break; }
}
// If we got this far, no match was found in forward slash direction,
// so reset our counter and check the back slash direction '\'
matchingPieces = 1;
// First check down/right (decrement row and increment column)
for (int counter = 1; counter < 4; counter++)
{
var row = pieceRow - counter;
var col = pieceCol + counter;
// Make sure we stay within our board
if (row < Board.GetLowerBound(0) || col > Board.GetUpperBound(1)) { break; }
// Check for a match
if (Board[row, col] == colorToMatch)
{
matchingPieces++;
if (matchingPieces == 4) return true;
}
else { break; }
}
// Next check up/left (increment row and decrement column)
for (int counter = 1; counter < 4; counter++)
{
var row = pieceRow + counter;
var col = pieceCol - counter;
// Make sure we stay within our board
if (row > Board.GetUpperBound(0) || col < Board.GetLowerBound(1)) { break; }
// Check for a match
if (Board[row, col] == colorToMatch)
{
matchingPieces++;
if (matchingPieces == 4) return true;
}
else { break; }
}
// If we've gotten this far, then we haven't found a match
return false;
}