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C# 在二维锯齿阵列中查找元素计数的标准方法是什么?_C#_Arrays_Multidimensional Array_Jagged Arrays - Fatal编程技术网

C# 在二维锯齿阵列中查找元素计数的标准方法是什么?

C# 在二维锯齿阵列中查找元素计数的标准方法是什么?,c#,arrays,multidimensional-array,jagged-arrays,C#,Arrays,Multidimensional Array,Jagged Arrays,我可以在这里写什么? public static double PrazenWindowDensity(double [][] Xn, double x, double sigma2) { double gauss = 0; foreach(double [] arr in Xn) { foreach (double item in arr) { do

我可以在这里写什么?

    public static double PrazenWindowDensity(double [][] Xn, double x, double sigma2)
    {
        double gauss = 0;

        foreach(double [] arr in Xn)
        {
            foreach (double item in arr)
            {
                double xx = GausianFunction(item, x, sigma2);
                gauss += xx;
            }
        }

        return gauss / Xn.Length; //this is surely incorrect. Isn't it?
    }

这似乎是一个令人满意的答案,所以我将继续并将其作为一个帖子发布

return gauss / Xn.Length;

我认为最快、最简单的方法是

return gauss / Xn.Sum(x => x.Length);
public static double PrazenWindowDensity(double[][]Xn,double x,double sigma2)
{
双高斯=0;
整数计数=0;
对于(int i=0;i高斯函数(项,x,sigma2));
计数+=Xn[i]。长度;
}
返回高斯/计数;
}

因为您已经在执行循环,所以不知道linq是否更快,或者只是在内部foreach中添加
count++
@埃里克,嗯……你说得对!
public static double PrazenWindowDensity(double[][] Xn, double x, double sigma2)
{
    double gauss=0;
    int count=0;
    for (int i=0; i<Xn.Length; i++)
    {
        gauss+=Xn[i].Sum((item) => GausianFunction(item, x, sigma2));
        count+=Xn[i].Length;
    }
    return gauss/count;
}