C# 保存和加载列表

我正在做一个项目，我有这个清单

List<Vara> minaVaror = new List<Vara>();

以下是我如何将项目添加到列表中：

minaVaror.Add(new Vara() {streckKod = inputBox1, artNamn = textBox2.Text });

好的，这个列表将不时地添加项目，所以我需要能够保存和加载列表的内容/项目，这样当程序关闭和重新打开时，您就不会丢失数据

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去年我们在课堂上做了类似的事情，我们使用XmlSerializer将数据保存到一个XML文件中，但是这只适用于1 int，我真的不知道如何对整个列表执行此操作。

根据定义，XmlSerializer无法反序列化列表或数组列表

XmlSerializer无法反序列化以下内容：ArrayList数组和List数组

所以您可以序列化列表，但不能反序列化列表

因此，您可以使用此代码在XML中序列化并反序列化XML文件

namespace DataContractSerializerExample
{
    using System;
    using System.Collections;
    using System.Collections.Generic;
    using System.IO;
    using System.Runtime.Serialization;
    using System.Xml;

    // You must apply a DataContractAttribute or SerializableAttribute
    // to a class to have it serialized by the DataContractSerializer.
    [DataContract(Name = "Vara", Namespace = "http://www.contoso.com")]
    public class Vara
    {
        [DataMember()]
        public double streckKod { get; set; }
        [DataMember]
        public string artNamn { get; set; }
    }

    public sealed class Test
    {
        private Test() { }

        public static void Main()
        {
            List<Vara> minaVaror = new List<Vara>() { new Vara() { streckKod = 5.0, artNamn = "test1" }, new Vara() { streckKod = 5.0, artNamn = "test2" }, new Vara() { streckKod = 5.0, artNamn = "test3" } };
            string fileName = "test.xml";
            Serialize<List<Vara>>(fileName, minaVaror);
            List<Vara> listDes = Deserialize<List<Vara>>(fileName);
        }

        public static void Serialize<T>(string fileName, T obj)
        {
            FileStream writer = new FileStream(fileName, FileMode.Create);
            DataContractSerializer ser =
                new DataContractSerializer(typeof(T));
            ser.WriteObject(writer, obj);
            writer.Close();
        }

        public static T Deserialize<T>(string fileName)
        {
            FileStream fs = new FileStream(fileName,
            FileMode.Open);
            XmlDictionaryReader reader =
                XmlDictionaryReader.CreateTextReader(fs, new XmlDictionaryReaderQuotas());
            DataContractSerializer ser = new DataContractSerializer(typeof(T));
            T  des  =
                (T)ser.ReadObject(reader, true);
            reader.Close();
            fs.Close();
            return des;
        }
    }
}

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注意：您应该添加对C:\Program Files x86\reference Assembly\Microsoft\Framework.NETFramework\v4.0\System.Runtime.Serialization.dll的引用。

如何调用SerializedXML？我已经在Form1.cs中将主代码添加到它自己的类中，但是我无法调用它进行序列化，因为它找不到SerializeToXmlyou不应该使用类实例调用静态方法尝试类似于Form1.Serialize的操作

namespace DataContractSerializerExample
{
    using System;
    using System.Collections;
    using System.Collections.Generic;
    using System.IO;
    using System.Runtime.Serialization;
    using System.Xml;

    // You must apply a DataContractAttribute or SerializableAttribute
    // to a class to have it serialized by the DataContractSerializer.
    [DataContract(Name = "Vara", Namespace = "http://www.contoso.com")]
    public class Vara
    {
        [DataMember()]
        public double streckKod { get; set; }
        [DataMember]
        public string artNamn { get; set; }
    }

    public sealed class Test
    {
        private Test() { }

        public static void Main()
        {
            List<Vara> minaVaror = new List<Vara>() { new Vara() { streckKod = 5.0, artNamn = "test1" }, new Vara() { streckKod = 5.0, artNamn = "test2" }, new Vara() { streckKod = 5.0, artNamn = "test3" } };
            string fileName = "test.xml";
            Serialize<List<Vara>>(fileName, minaVaror);
            List<Vara> listDes = Deserialize<List<Vara>>(fileName);
        }

        public static void Serialize<T>(string fileName, T obj)
        {
            FileStream writer = new FileStream(fileName, FileMode.Create);
            DataContractSerializer ser =
                new DataContractSerializer(typeof(T));
            ser.WriteObject(writer, obj);
            writer.Close();
        }

        public static T Deserialize<T>(string fileName)
        {
            FileStream fs = new FileStream(fileName,
            FileMode.Open);
            XmlDictionaryReader reader =
                XmlDictionaryReader.CreateTextReader(fs, new XmlDictionaryReaderQuotas());
            DataContractSerializer ser = new DataContractSerializer(typeof(T));
            T  des  =
                (T)ser.ReadObject(reader, true);
            reader.Close();
            fs.Close();
            return des;
        }
    }
}