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C# 类型应为预期标识符_C# - Fatal编程技术网

C# 类型应为预期标识符

C# 类型应为预期标识符,c#,C#,我为大学做这个项目。 我有一个错误,我不知道如何修复。 谢谢你的帮助 public async Task<IActionResult> Create([Bind("EmployeeID,TitleOfCourtesy,FirstName,LastName,Title,BirthDate,HireDate,Address,City,Region,PostalCode,Country,HomePhone,Extension,ReportsTo,Notes")]) { va

我为大学做这个项目。 我有一个错误,我不知道如何修复。 谢谢你的帮助

public async Task<IActionResult> Create([Bind("EmployeeID,TitleOfCourtesy,FirstName,LastName,Title,BirthDate,HireDate,Address,City,Region,PostalCode,Country,HomePhone,Extension,ReportsTo,Notes")]) {
        var employee = _context.Employees.ToList();
        if (ModelState.IsValid) {
            _context.Add(employee);
            await _context.SaveChangesAsync();
            return RedirectToAction(nameof(Index));
        }
        return View(employee);
    }
public async Task Create([Bind(“EmployeeID,titleof courtey,FirstName,LastName,Title,BirthDate,HireDate,Address,City,Region,PostalCode,Country,HomePhone,Extension,ReportsTo,Notes”)){
var employee=_context.Employees.ToList();
if(ModelState.IsValid){
_上下文。添加(员工);
wait_context.SaveChangesAsync();
返回重定向到操作(名称(索引));
}
返回视图(员工);
}
错误:


您需要声明要传递给
Create
的参数的类型和名称。例如,
Create(string id)
。更具体地说,
Create(Bind(…)]Employee-Employee)
好的,谢谢:您需要声明要传递给
Create
的参数的类型和名称。例如,
Create(stringid)
。更具体地说,
Create(Bind(…)]Employee-Employee)
好的,谢谢:D