C# 如何组合对象,以便将所有对象同时显示为JSON?
在下面的代码中,选中以下行:C# 如何组合对象,以便将所有对象同时显示为JSON?,c#,C#,在下面的代码中,选中以下行: //here I need to put the object "nd" into a "bucket" so that I can finish the loop and then return EVERYTHING together. 我的问题是,如何组合对象以作为JSON返回?我之所以需要“合并”,是因为循环将值分配给这个类的特定属性。一旦每个类都完成了属性值的获取,我需要将所有内容作为JSON返回 namespace X { public clas
//here I need to put the object "nd" into a "bucket" so that I can finish the loop and then return EVERYTHING together.
我的问题是,如何组合对象以作为JSON返回?我之所以需要“合并”,是因为循环将值分配给这个类的特定属性。一旦每个类都完成了属性值的获取,我需要将所有内容作为JSON返回
namespace X
{
public class NotificationsController : ApiController
{
public List<NotificationTreeNode> getNotifications(int id)
{
var bo = new HomeBO();
var list = bo.GetNotificationsForUser(id);
var notificationTreeNodes = (from GBLNotifications n in list
where n.NotificationCount != 0
select new NotificationTreeNode(n)).ToList();
foreach (var notificationTreeNode in notificationTreeNodes)
{
Node nd = new Node();
nd.notificationType = notificationTreeNode.NotificationNode.NotificationType;
var notificationList = bo.GetNotificationsForUser(id, notificationTreeNode.NotificationNode.NotificationTypeId).Cast<GBLNotifications>().ToList();
List<string> notificationDescriptions = new List<string>();
foreach (var item in notificationList)
{
notificationDescriptions.Add(item.NotificationDescription);
}
nd.notifications = notificationDescriptions;
//here I need to put the object "nd" into a "bucket" so that I can finish the loop and then return EVERYTHING together.
}
return bucket;
}
}
public class Node
{
public string notificationType
{
get;
set;
}
public List<string> notifications
{
get;
set;
}
}
}
名称空间X
{
公共类通知控制器:ApiController
{
公共列表getNotifications(int-id)
{
var bo=新的HomeBO();
var list=bo.getnotificationsfourser(id);
var notificationTreeNodes=(来自列表中的GBLNotifications n
其中n.NotificationCount!=0
选择new NotificationTreeNode(n)).ToList();
foreach(notificationTreeNodes中的var notificationTreeNode)
{
Node nd=新节点();
nd.notificationType=notificationTreeNode.NotificationNode.notificationType;
var notificationList=bo.getnotificationsfourser(id,notificationTreeNode.NotificationNode.NotificationTypeId.Cast().ToList();
List notificationDescriptions=新列表();
foreach(通知列表中的var项)
{
NotificationDescription.Add(item.NotificationDescription);
}
通知=通知说明;
//在这里,我需要将对象“nd”放入一个“bucket”中,以便完成循环,然后一起返回所有内容。
}
返回铲斗;
}
}
公共类节点
{
公共字符串notificationType
{
得到;
设置
}
公开名单通知
{
得到;
设置
}
}
}
在迭代源集合时,只需将每个项添加到列表中即可:
public List<Node> getNotifications(int id)
{
var bucket = new List<Node>(notificationTreeNodes.Count);
foreach (var notificationTreeNode in notificationTreeNodes)
{
Node nd = new Node();
...
bucket.Add(nd);
}
return bucket;
}
public List getNotifications(int-id)
{
var bucket=新列表(notificationTreeNodes.Count);
foreach(notificationTreeNodes中的var notificationTreeNode)
{
Node nd=新节点();
...
桶。添加(nd);
}
返回铲斗;
}
在迭代源集合时,只需将每个项添加到列表中即可:
public List<Node> getNotifications(int id)
{
var bucket = new List<Node>(notificationTreeNodes.Count);
foreach (var notificationTreeNode in notificationTreeNodes)
{
Node nd = new Node();
...
bucket.Add(nd);
}
return bucket;
}
public List getNotifications(int-id)
{
var bucket=新列表(notificationTreeNodes.Count);
foreach(notificationTreeNodes中的var notificationTreeNode)
{
Node nd=新节点();
...
桶。添加(nd);
}
返回铲斗;
}