C# 从JSON属性中删除，但保留其值

我有：

[
  {
    "Position": "ProjectManager",
    "Salary": 2000
  },
  {
    "Position": "BusinessAnalyst",
    "Salary": 2001
  },
  {
    "Position": "TechnicalLead",
    "Salary": 2002
  },
  {
    "Position": "SeniorSoftwareEngineer",
    "Salary": 2003
  },
  {
    "Position": "SoftwareEngineer",
    "Salary": 2004
  },
  {
    "Position": "JuniorSoftwareEngineer",
    "Salary": 2005
  },
  {
    "Position": "UIUXEngineer",
    "Salary": 2006
  },
  {
    "Position": "QALead",
    "Salary": 2007
  },
  {
    "Position": "SeniorQAEngineer",
    "Salary": 2008
  },
  {
    "Position": "QAEngineer",
    "Salary": 2009
  },
  {
    "Position": "JuniorQAEngineer",
    "Salary": 2010
  },
  {
    "Position": "SeniorAutomationEngineer",
    "Salary": 2011
  },
  {
    "Position": "AutomationEngineer",
    "Salary": 2012
  },
  {
    "Position": "JuniorAutomationEngineer",
    "Salary": 2013
  }
]

但我需要将其转换为以下示例：

{
  "ProjectManager": "2000",
    "BusinessAnalyst": "2001",
    "TechnicalLead": "2002",
    "SeniorSoftwareEngineer": "2003",
    "SoftwareEngineer": "2004",
    "JuniorSoftwareEngineer": "2005",
    "UIUXEngineer": "2006",
    "QALead": "2007",
    "SeniorQAEngineer": "2008",
    "QAEngineer": "2009",
    "JuniorQAEngineer": "2010",
    "SeniorAutomationEngineer": "2011",
    "AutomationEngineer": "2012",
    "JuniorAutomationEngineer": "2013"
}

---

正如您在第二个示例中看到的，我只有值，没有属性。我该怎么做？（目前我的想法是将Json解析为字符串，并删除与“Position:”或“Salary:”匹配的所有标记）

一种方法是迭代数组中的每个对象并填充字典：

// Using JSON.NET you can deserialize the JSON array as an enumerable 
// of dynamically-typed objects (i.e. your array)
IEnumerable<dynamic> employees = JsonConvert
                                   .DeserializeObject<IEnumerable<dynamic>>
                                   (
                                       jsonText
                                   );

Dictionary<string, object> values = new Dictionary<string, object>();

foreach(dynamic employee in employees) 
{
    values.Add((string)employee.Position, (object)employee.Salary);
}

// .NET dictionaries are deserialized into JSON objects!
string convertedJson = JsonConvert.SerializeObject(values);

//使用JSON.NET可以将JSON数组反序列化为可枚举数组
//动态类型化对象（即数组）的数量
IEnumerable employees=JsonConvert
.反序列化对象
(
jsonText
);
字典值=新字典（）；
foreach（员工中的动态员工）
{
添加（（字符串）employee.Position，（对象）employee.Salary）；
}
//.NET字典被反序列化为JSON对象！
string convertedJson=JsonConvert.SerializeObject（值）；

更新 如果您想要基于单行LINQ扩展方法的解决方案，那么：

string convertedJson = JsonConvert.SerializeObject
(
    JsonConvert.DeserializeObject<IEnumerable<dynamic>>(jsonText)
        .ToDictionary(employee => employee.Position, employee => employee.Salary)
);

string convertedJson=JsonConvert.SerializeObject
(
JsonConvert.DeserializeObject（jsonText）
.ToDictionary（employee=>employee.Position，employee=>employee.Salary）
);

你不需要做那么多事情。 我能想出一个办法

让您的json为probjson，结果为resJSON

var arr=new [];
var res=new { arr }
    for(var i in probjson.length){

var position=probjson[i].Position;
var salary=probjson[i].Salary;

var v = new { position=salary  }
res.arr.add(V);

}

这不是一个完整的

请试着想出一个主意。

---

谢谢

@user3770925没问题。查看我的更新，您可能可以进一步简化解决方案！；）