C# 如何在c中创建类的对象时提高性能#
我知道我将要问一个愚蠢的问题，但我只想知道以下陈述的区别：C# 如何在c中创建类的对象时提高性能#,c#,performance,instantiation,C#,Performance,Instantiation,我知道我将要问一个愚蠢的问题，但我只想知道以下陈述的区别： Abc object= new ABC(); object.Age=obj1.Age; object.Place=obj1.Place; object.Street=obj1.Street; object.Number=obj1.Number; object.POBox=obj1.POBox; 及 上述编写的代码是否有助于提高性能？我只是想知道，在创建一个类的对象并为该类对象赋值时，是否有任何方法可以提高性能？否。这些语句被编译为同一
Abc object= new ABC();
object.Age=obj1.Age;
object.Place=obj1.Place;
object.Street=obj1.Street;
object.Number=obj1.Number;
object.POBox=obj1.POBox;
上述编写的代码是否有助于提高性能？我只是想知道，在创建一个类的对象并为该类对象赋值时，是否有任何方法可以提高性能？否。这些语句被编译为同一个IL，因此没有性能改进 第一个：
IL_0031: newobj instance void TestApplication.ABC::.ctor()
IL_0036: stloc.1
IL_0037: ldloc.1
IL_0038: ldc.i4.1
IL_0039: callvirt instance void TestApplication.ABC::set_Age(int32)
IL_003e: nop
IL_003f: ldloc.1
IL_0040: ldc.i4.1
IL_0041: callvirt instance void TestApplication.ABC::set_Place(int32)
IL_0046: nop
IL_0047: ldloc.1
IL_0048: ldc.i4.1
IL_0049: callvirt instance void TestApplication.ABC::set_Street(int32)
IL_004e: nop
IL_004f: ldloc.1
IL_0050: ldc.i4.1
IL_0051: callvirt instance void TestApplication.ABC::set_Number(int32)
IL_0056: nop
IL_0057: ldloc.1
IL_0058: ldc.i4.1
IL_0059: callvirt instance void TestApplication.ABC::set_POBox(int32)
IL_0001: newobj instance void TestApplication.ABC::.ctor()
IL_0006: stloc.2
IL_0007: ldloc.2
IL_0008: ldc.i4.1
IL_0009: callvirt instance void TestApplication.ABC::set_Age(int32)
IL_000e: nop
IL_000f: ldloc.2
IL_0010: ldc.i4.1
IL_0011: callvirt instance void TestApplication.ABC::set_Place(int32)
IL_0016: nop
IL_0017: ldloc.2
IL_0018: ldc.i4.1
IL_0019: callvirt instance void TestApplication.ABC::set_Street(int32)
IL_001e: nop
IL_001f: ldloc.2
IL_0020: ldc.i4.1
IL_0021: callvirt instance void TestApplication.ABC::set_Number(int32)
IL_0026: nop
IL_0027: ldloc.2
IL_0028: ldc.i4.1
IL_0029: callvirt instance void TestApplication.ABC::set_POBox(int32)
不会。这些语句被编译为相同的IL，因此没有性能改进 第一个：
IL_0031: newobj instance void TestApplication.ABC::.ctor()
IL_0036: stloc.1
IL_0037: ldloc.1
IL_0038: ldc.i4.1
IL_0039: callvirt instance void TestApplication.ABC::set_Age(int32)
IL_003e: nop
IL_003f: ldloc.1
IL_0040: ldc.i4.1
IL_0041: callvirt instance void TestApplication.ABC::set_Place(int32)
IL_0046: nop
IL_0047: ldloc.1
IL_0048: ldc.i4.1
IL_0049: callvirt instance void TestApplication.ABC::set_Street(int32)
IL_004e: nop
IL_004f: ldloc.1
IL_0050: ldc.i4.1
IL_0051: callvirt instance void TestApplication.ABC::set_Number(int32)
IL_0056: nop
IL_0057: ldloc.1
IL_0058: ldc.i4.1
IL_0059: callvirt instance void TestApplication.ABC::set_POBox(int32)
IL_0001: newobj instance void TestApplication.ABC::.ctor()
IL_0006: stloc.2
IL_0007: ldloc.2
IL_0008: ldc.i4.1
IL_0009: callvirt instance void TestApplication.ABC::set_Age(int32)
IL_000e: nop
IL_000f: ldloc.2
IL_0010: ldc.i4.1
IL_0011: callvirt instance void TestApplication.ABC::set_Place(int32)
IL_0016: nop
IL_0017: ldloc.2
IL_0018: ldc.i4.1
IL_0019: callvirt instance void TestApplication.ABC::set_Street(int32)
IL_001e: nop
IL_001f: ldloc.2
IL_0020: ldc.i4.1
IL_0021: callvirt instance void TestApplication.ABC::set_Number(int32)
IL_0026: nop
IL_0027: ldloc.2
IL_0028: ldc.i4.1
IL_0029: callvirt instance void TestApplication.ABC::set_POBox(int32)
我认为有一个微妙的区别：第二个语句是原子的；当没有合适的构造函数时，可以使用它来确保对象在正确的状态下初始化
mote info:我认为有一个微妙的区别：第二个语句是原子的；当没有合适的构造函数时，可以使用它来确保对象在正确的状态下初始化
远程信息：IL代码将相同。这只是语法。从技术上讲，这是一个编译器错误。只是说…@SimonWhitehead是的。Abc！=ABC和您不能声明一个
对象对象