C# 从包含多个不必要字符的字符串创建列表

我拿着这根绳子：

{"0":{"title":"iPhone"},"1":{"title":"iPod"},"2":{"title":"iPad"},"length":3,"prevObject":{"0":{},"1":{},"2":{},"length":3,"prevObject":{"0":{},"length":1,"context":{"location":{},"jQuery18308480830912211994":1},"selector":"#mycart"},"context":{"location":{},"jQuery18308480830912211994":1},"selector":"#mycart li"},"context":{"location":{},"jQuery18308480830912211994":1}}

我希望清除此字符串，并生成一个或数组，其中包含相应的3项： Iphone iPod Ipad 我的生成上述内容的代码是：

$("#btngetCart").live("click", function () {

            var items = $('#mycart').find('li').map(function () {
                var item = {};


                item.title = $(this).text();

                return item;
            });
            var json = JSON.stringify(items);

            $.ajax({

                type: 'POST',

                url: "WebForm5.aspx/GetCart",

                data: "{item:" + JSON.stringify(json) + "}",

                contentType: 'application/json; charset=utf-8',

                dataType: 'json',

                success: function (r) {



                }

            });

        });

关于背后的代码：

[WebMethod(EnableSession = true)]
        public static string GetCart(string item)
        {

            HttpContext.Current.Session["f"] = item;
            return item;


        }

---

别忘了添加Json.Net nuget:

这里有一个更具.Net风格的方法：

使用NuGet安装Json.Net。然后使用类似的方法：

var json = @"{""0"":{""title"":""iPhone""},""1"":{""title"":""iPod""},""2"":{""title"":""iPad""},""length"":3,""prevObject"":{""0"":{},""1"":{},""2"":{},""length"":3,""prevObject"":{""0"":{},""length"":1,""context"":{""location"":{},""jQuery18308480830912211994"":1},""selector"":""#mycart""},""context"":{""location"":{},""jQuery18308480830912211994"":1},""selector"":""#mycart li""},""context"":{""location"":{},""jQuery18308480830912211994"":1}}";
var @object = JObject.Parse(json);

var length = (int)@object["length"];
var indices = Enumerable.Range(0, length);
var titles = indices.Select(index => @object[index.ToString()]["title"]).ToList();

---

到目前为止，你试过什么吗？我已经得出结论，这将是一个正则表达式函数，将有帮助。但是我不知道从哪里开始你试过这个吗：var l=新列表{Iphone，iPod，Ipad}？但很严重，不是吗？请尝试使用json.net，您希望保留这些对象中的哪3项？列表中的内容以友好方式提供。。。这只是一个例子，我应该用什么程序集来处理JObject？我正在接受当前上下文中不存在的JObject

var json = @"{""0"":{""title"":""iPhone""},""1"":{""title"":""iPod""},""2"":{""title"":""iPad""},""length"":3,""prevObject"":{""0"":{},""1"":{},""2"":{},""length"":3,""prevObject"":{""0"":{},""length"":1,""context"":{""location"":{},""jQuery18308480830912211994"":1},""selector"":""#mycart""},""context"":{""location"":{},""jQuery18308480830912211994"":1},""selector"":""#mycart li""},""context"":{""location"":{},""jQuery18308480830912211994"":1}}";
var @object = JObject.Parse(json);

var length = (int)@object["length"];
var indices = Enumerable.Range(0, length);
var titles = indices.Select(index => @object[index.ToString()]["title"]).ToList();