C# 初始化具有必须存在的属性的类的最佳方法
示例类C# 初始化具有必须存在的属性的类的最佳方法,c#,software-design,C#,Software Design,示例类 public class Company { public Details Details { get; set; } public List<Employeee> Employees { get; set; } public Company() { } } public class Details { public string Name { get; set; } public string Url { get; se
public class Company {
public Details Details { get; set; }
public List<Employeee> Employees { get; set; }
public Company() {
}
}
public class Details {
public string Name { get; set; }
public string Url { get; set; }
public Details() {
}
}
没有细节的公司是没有意义的
我的一个想法是
更改公司构造函数以自动创建新的详细信息
更改详细信息集以确保其未设置为null
这似乎是一个常见的问题,我想知道是否有一个标准的方法来处理它,这将导致可测试类。我不确定要搜索什么。如果我理解正确,我认为最好的方法是只创建一个以细节作为参数的构造函数 例如:
public class Company
{
public Details Details { get; set; }
public List<Employeee> Employees { get; set; }
public Company(string Name, string Url)
{
this.Details = new Details(Name, Url);
}
public Company(Details Details)
{
this.Details = Details;
}
}
public class Details
{
public string Name { get; set; }
public string Url { get; set; }
public Details(string Name, string Url)
{
// If the validation fails, throw an error
if (string.IsNullOrWhiteSpace(Name))
throw new ArgumentException($"'{nameof(Name)}' cannot be null or empty", nameof(Name));
if (string.IsNullOrWhiteSpace(Url))
throw new ArgumentException($"'{nameof(Url)}' cannot be null or empty", nameof(Url));
this.Name = Name;
this.Url = Url;
}
}
为什么不让Company对象的唯一构造函数期望一个Details对象作为参数?这样你就不能在不声明细节的情况下创建一个公司。我认为仍然需要添加一个限制,以防止构造函数和setter中的细节都为空?@Aligma是的,因此//@Aligma添加了一个基本的验证
public class Company
{
public Details Details { get; set; }
public List<Employeee> Employees { get; set; }
public Company(string Name, string Url)
{
this.Details = new Details(Name, Url);
}
public Company(Details Details)
{
this.Details = Details;
}
}
public class Details
{
public string Name { get; set; }
public string Url { get; set; }
public Details(string Name, string Url)
{
// If the validation fails, throw an error
if (string.IsNullOrWhiteSpace(Name))
throw new ArgumentException($"'{nameof(Name)}' cannot be null or empty", nameof(Name));
if (string.IsNullOrWhiteSpace(Url))
throw new ArgumentException($"'{nameof(Url)}' cannot be null or empty", nameof(Url));
this.Name = Name;
this.Url = Url;
}
}