C# 按特定条件连接两个复杂SQL查询的结果

有两个查询，下面是一个案例中的查询和结果

在第一个查询结果中，5行，从南到北，有5辆半卡车，第7行有22辆卡车。

在第二次查询中，有两种对象类型。如果我们考虑第四行，该行说，<强>从南行到北行，有3辆半卡车和3辆卡车< /强>

我们需要做的是，从第二个结果得到3个半卡车，它们将与第一个查询的第五行相加。因此，半卡车总数将为8辆，同样，卡车总数将为25辆（第7排）

此外，如果没有公共行，则该行将作为新行添加到结果中

1st:

select 
    count(v.ObjectType) o, 
    v.ObjectType, v.EnterDirection, v.Direction 
from 
    validobjects v 
where 
    processinfoid = 1 
    and Isactive = 1 
    and v.ObjectType <> 'None' 
    and (v.EnterDirection = 'SouthBound' OR 
         v.EnterDirection = 'EastBound' OR 
         v.EnterDirection = 'NorthBound' OR 
         v.EnterDirection = 'WestBound' OR 
         v.EnterDirection = 'SouthEastBound' OR 
         v.EnterDirection = 'SouthWestBound' OR 
         v.EnterDirection = 'NorthEastBound' OR 
         v.EnterDirection = 'NorthWestBound')
group by 
    v.ObjectType, v.EnterDirection, v.Direction

select 
    count(v.objecttype1) o1,
    count(v.ObjectType2) o2, 
    v.ObjectType1, v.ObjectType2, 
    v.EnterDirection, v.Direction 
from 
    ValidObjects v 
where 
    v.ValidObjectID in (select ValidObjectID 
                        from validobjects v 
                        where processinfoid = 1 
                          and Isactive = 1 
                          and ObjectType = 'None' )
group by 
    v.ObjectType1, v.ObjectType2, v.EnterDirection, v.Direction

结果

试试这个

SELECT
    * -- Your operation
FROM
(
    SELECT * FROM FirstQuery
) FQ LEFT JOIN 
(
    SELECT * FROM SecondQuery
) SQS ON FQ.ObjectType = SQS.ObjectType1 AND 
         FQ.EnterDirection = SQS.EnterDirection AND 
         FQ.Direction = SQS.Direction -- SemiTruck
LEFT JOIN 
(
    SELECT * FROM SecondQuery
) SQT ON 
        FQ.ObjectType = SQT.ObjectType2 AND 
        FQ.EnterDirection = SQT.EnterDirection AND 
        FQ.Direction = SQT.Direction -- Truck

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只需

左连接

两个查询？