C# 将矩阵乘以用户输入
这是一个代码示例,它将一个矩阵乘以多个用户输入。该操作应按用户输入的数量重复。例如,如果我放一个数字3,我得到3个相同的打印矩阵。相反,我希望矩阵与数字3相乘3次(每个新矩阵都与数字3相乘)。有人知道我怎么做吗?多谢各位C# 将矩阵乘以用户输入,c#,multidimensional-array,visual-studio-2015,user-input,C#,Multidimensional Array,Visual Studio 2015,User Input,这是一个代码示例,它将一个矩阵乘以多个用户输入。该操作应按用户输入的数量重复。例如,如果我放一个数字3,我得到3个相同的打印矩阵。相反,我希望矩阵与数字3相乘3次(每个新矩阵都与数字3相乘)。有人知道我怎么做吗?多谢各位 *using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; namespace user_input {
*using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace user_input
{
class Program
{
static void Main(string[] args)
{
string[] nodes = { "1", "2", "3", "4", "5", "6" };
int[,] adjmatrix = new int[,]
{{2,7,3,8,4},
{7,0,8,2,6},
{6,8,4,9,7},
{8,5,9,8,8},
{4,9,7,8,1}
};
int[,] newmatrix = new int[adjmatrix.GetLength(0), adjmatrix.GetLength(1)];
Printmatrix(adjmatrix, nodes, nodes, "Input Matrix");
Newline();
int n = 0;
System.Console.WriteLine("Please enter a number");
n = Convert.ToInt32(Console.ReadLine());
for (int i = 0; i < n; i++)
{
MultipliedMatrix(ref newmatrix, adjmatrix, n);
Newline();
Printmatrix(newmatrix, nodes, nodes, "Multiplied Matrix");
}
Console.ReadKey();
}
private static void Newline()
{
Console.Write("\n");
}
private static void MultipliedMatrix(ref int[,] newmatrix, int[,] adjmatrix, int n)
{
for (int i = 0; i < adjmatrix.GetLength(0); i++)
{
for (int j = 0; j < adjmatrix.GetLength(1); j++)
{
newmatrix[i, j] = adjmatrix[i, j] * n;
}
}
}
private static void Printmatrix(int[,] adjmatrix, string[] nodes_h, string[] nodes_v, string title)
{
if (adjmatrix.GetLength(0) != 0)
{
Console.ForegroundColor = ConsoleColor.White;
Console.Write("{0}\n", title);
Console.ForegroundColor = ConsoleColor.DarkGreen;
Console.Write("\t");
for (int i = 0; i < adjmatrix.GetLength(0); i++)
Console.Write("{0}\t", nodes_v[i]);
for (int i = 0; i < adjmatrix.GetLength(0); i++)
{
Newline();
Console.ForegroundColor = ConsoleColor.DarkGreen;
Console.Write("{0}\t", nodes_h[i]);
for (int j = 0; j < adjmatrix.GetLength(1); j++)
{
Console.ForegroundColor = ConsoleColor.DarkGray;
if (adjmatrix[i, j] < 500) Console.Write("{0}\t", adjmatrix[i, j]);
else
{
Console.ForegroundColor = ConsoleColor.Red;
Console.Write("-\t", adjmatrix[i, j]);
}
}
Console.ForegroundColor = ConsoleColor.White;
}
Newline();
}
}
}
}*
*使用系统;
使用System.Collections.Generic;
使用System.Linq;
使用系统文本;
使用System.Threading.Tasks;
名称空间用户输入
{
班级计划
{
静态void Main(字符串[]参数)
{
字符串[]节点={“1”、“2”、“3”、“4”、“5”、“6”};
int[,]调整矩阵=新int[,]
{{2,7,3,8,4},
{7,0,8,2,6},
{6,8,4,9,7},
{8,5,9,8,8},
{4,9,7,8,1}
};
int[,]newmatrix=newint[adjmatrix.GetLength(0),adjmatrix.GetLength(1)];
打印矩阵(adjmatrix,节点,节点,“输入矩阵”);
换行符();
int n=0;
System.Console.WriteLine(“请输入一个数字”);
n=Convert.ToInt32(Console.ReadLine());
对于(int i=0;i
*您一直将相同的矩阵作为输入传递给
multipledMatrix()
,因此它一直在做相同的事情
要使其在新矩阵上运行,请在循环中调用Printmatrix()
后立即添加以下行:
adjmatrix = newmatrix;
或者(在IMO中更好的做法是)更改multipledMatrix()
以返回新矩阵,如下所示:
private static int[,] MultipliedMatrix(int[,] adjmatrix, int n)
{
int[,] newmatrix = new int[adjmatrix.GetLength(0), adjmatrix.GetLength(1)];
for (int i = 0; i < adjmatrix.GetLength(0); i++)
for (int j = 0; j < adjmatrix.GetLength(1); j++)
newmatrix[i, j] = adjmatrix[i, j] * n;
return newmatrix;
}
您一直将相同的矩阵作为输入传递给
MultipleedMatrix()
,因此它一直在做相同的事情
要使其在新矩阵上运行,请在循环中调用Printmatrix()
后立即添加以下行:
adjmatrix = newmatrix;
或者(在IMO中更好的做法是)更改multipledMatrix()
以返回新矩阵,如下所示:
private static int[,] MultipliedMatrix(int[,] adjmatrix, int n)
{
int[,] newmatrix = new int[adjmatrix.GetLength(0), adjmatrix.GetLength(1)];
for (int i = 0; i < adjmatrix.GetLength(0); i++)
for (int j = 0; j < adjmatrix.GetLength(1); j++)
newmatrix[i, j] = adjmatrix[i, j] * n;
return newmatrix;
}
首先,我将把multiply改为函数,而不是void方法调用,这样看起来更好 这将是伪代码:
n = userinput;
i=0;
int[,] result;
do
i+=1;
result = MultiplyMatrix(result, n);
while i<n
int[,] MultiplyMatrix(adjmatrix, n){
(multiply)
return resultMatrix };
n=用户输入;
i=0;
int[,]结果;
做
i+=1;
结果=多矩阵(结果,n);
当我开始时,我会将乘法改为函数,而不是void方法调用,这样看起来更好
这将是伪代码:
n = userinput;
i=0;
int[,] result;
do
i+=1;
result = MultiplyMatrix(result, n);
while i<n
int[,] MultiplyMatrix(adjmatrix, n){
(multiply)
return resultMatrix };
n=用户输入;
i=0;
int[,]结果;
做
i+=1;
结果=多矩阵(结果,n);
而我