C# XmlSerializer-将属性成员序列化为属性

我正在尝试将内验证属性的所有成员序列化为属性（

XmlSerializer

）

两个类：

public class Tree
{
    public Point Location { get; set; }
}

public class AppleTree : Tree
{
    [XmlAttribute]
    public int FruitCount { get; set; }
}

AppleTree appleTree = new AppleTree
{
    Location = new Point(10, 20),
    FruitCount = 69
};
// Serialize ...

<?xml version="1.0"?>
<AppleTree FruitCount="69">
  <Location>
    <X>10</X>
    <Y>20</Y>
  </Location>
</AppleTree>

<?xml version="1.0"?>
<AppleTree FruitCount="69" X="10" Y="20" />

public class Tree
{
    [XmlIgnore]
    public Point Location { get; set; }
}

public class AppleTree : Tree
{
    [XmlAttribute]
    public int FruitCount { get; set; }

    [XmlAttribute]
    public int X
    {
        get { return Location.X; }
        set { Location = new Point(value, Location.Y); }
    }

    [XmlAttribute]
    public int Y
    {
        get { return Location.Y; }
        set { Location = new Point(Location.X, value); }
    }
}

主程序：

public class Tree
{
    public Point Location { get; set; }
}

public class AppleTree : Tree
{
    [XmlAttribute]
    public int FruitCount { get; set; }
}

AppleTree appleTree = new AppleTree
{
    Location = new Point(10, 20),
    FruitCount = 69
};
// Serialize ...

<?xml version="1.0"?>
<AppleTree FruitCount="69">
  <Location>
    <X>10</X>
    <Y>20</Y>
  </Location>
</AppleTree>

<?xml version="1.0"?>
<AppleTree FruitCount="69" X="10" Y="20" />

public class Tree
{
    [XmlIgnore]
    public Point Location { get; set; }
}

public class AppleTree : Tree
{
    [XmlAttribute]
    public int FruitCount { get; set; }

    [XmlAttribute]
    public int X
    {
        get { return Location.X; }
        set { Location = new Point(value, Location.Y); }
    }

    [XmlAttribute]
    public int Y
    {
        get { return Location.Y; }
        set { Location = new Point(Location.X, value); }
    }
}

现在我明白了：

public class Tree
{
    public Point Location { get; set; }
}

public class AppleTree : Tree
{
    [XmlAttribute]
    public int FruitCount { get; set; }
}

AppleTree appleTree = new AppleTree
{
    Location = new Point(10, 20),
    FruitCount = 69
};
// Serialize ...

<?xml version="1.0"?>
<AppleTree FruitCount="69">
  <Location>
    <X>10</X>
    <Y>20</Y>
  </Location>
</AppleTree>

<?xml version="1.0"?>
<AppleTree FruitCount="69" X="10" Y="20" />

public class Tree
{
    [XmlIgnore]
    public Point Location { get; set; }
}

public class AppleTree : Tree
{
    [XmlAttribute]
    public int FruitCount { get; set; }

    [XmlAttribute]
    public int X
    {
        get { return Location.X; }
        set { Location = new Point(value, Location.Y); }
    }

    [XmlAttribute]
    public int Y
    {
        get { return Location.Y; }
        set { Location = new Point(Location.X, value); }
    }
}

我知道，我可以这样说：

public class Tree
{
    public Point Location { get; set; }
}

public class AppleTree : Tree
{
    [XmlAttribute]
    public int FruitCount { get; set; }
}

AppleTree appleTree = new AppleTree
{
    Location = new Point(10, 20),
    FruitCount = 69
};
// Serialize ...

<?xml version="1.0"?>
<AppleTree FruitCount="69">
  <Location>
    <X>10</X>
    <Y>20</Y>
  </Location>
</AppleTree>

<?xml version="1.0"?>
<AppleTree FruitCount="69" X="10" Y="20" />

public class Tree
{
    [XmlIgnore]
    public Point Location { get; set; }
}

public class AppleTree : Tree
{
    [XmlAttribute]
    public int FruitCount { get; set; }

    [XmlAttribute]
    public int X
    {
        get { return Location.X; }
        set { Location = new Point(value, Location.Y); }
    }

    [XmlAttribute]
    public int Y
    {
        get { return Location.Y; }
        set { Location = new Point(Location.X, value); }
    }
}

但我不希望所有属性都重复（这只是一个简单的示例）

---

那么还有别的解决办法吗？如果使用

XmlSerializer

？

的属性，将X和Y作为属性带到基类中，则可以获得所需的行为：

public class Tree
{

    [XmlIgnore]
    public Point Location { get; set;}

    [XmlAttribute]
    public double X { 
        get { return Location.X;} 
        set { Location = new Point(value, Location.Y); }
    }

    [XmlAttribute]
    public double Y { 
        get { return Location.Y;} 
        set { Location = new Point(Location.X, value); }
    }
}

public class AppleTree : Tree
{
    [XmlAttribute]
    public int FruitCount { get; set; }
}

为我序列化如下：