如何组合两个字符串并创建4个字符集，其中两个来自一个字符串，另两个来自另一个字符串？c#

我被困在创建一个算法中，该算法从两个字符串创建4个字符集，从一个字符串创建两个字符集，从另一个字符串创建两个字符集。 例如：

• 字符串一：

  FIRSTNAME

• 字符串二：

  LASTNAME

我期望的结果是得到

10

组

4

字符，如：

FILA、RSST、TNNA、AMME、EFLA

等等，直到我们得到这样的

10

组合

这是我写的代码

using System;

public class Program
{
    public static void Main()
    {
        Console.WriteLine("Name");
        string name = Console.ReadLine();
        Console.WriteLine("Lastname");

        string lastname = Console.ReadLine();

        int i;

        var nchars = name.ToCharArray();
        var pchars = lastname.ToCharArray();

        for (i = 0; i <= 10; i++){
            int ctr0;
            int ctr;
            int ctr2;

            for (ctr = 0, ctr2 = 1, ctr0 = 1; 
                 ctr < 10; 
                 ctr0++, ctr = ctr + 2, ctr2 = ctr2 + 2) {
              Console.WriteLine("{0}{1}{2}{3}{4}",
                  ctr0,
                  nchars[ctr],
                  nchars[ctr2],
                  pchars[ctr],
                  pchars[ctr2]);
            }
        }
    }
}

但是它在字符串结束时停止，而不是得到10个组合，我只得到

4

。。我能做什么？

---

我做错了吗？

试图纠正你的冷漠嗯，我认为这是你应该尝试的：

public class Program
{
    public static void Main(string[] args)
    {
        Console.WriteLine("Name");
        string name = "FIRSTNAME";
        Console.WriteLine("Lastname");
        string lastname = "LASTNAME";
        int i;
        var nchars = name.ToCharArray();
        var pchars = lastname.ToCharArray();
        var ncharsCount = nchars.Length;
        var pcharsCount = pchars.Length;
        //for (i=0;i<=10;i++){
            int ctr0;
            int ctr;
            int ctr2;
            for (ctr = 0, ctr2 = 1, ctr0=1; ctr0 < 10 ;ctr0++, ctr++,ctr2++){
                Console.WriteLine("{0}{1}{2}{3}{4}", ctr0,nchars[ctr%ncharsCount],nchars[ctr2%ncharsCount],pchars[ctr%pcharsCount],pchars[ctr2%pcharsCount]);
            }
        //}
    }
}

公共类程序
{
公共静态void Main（字符串[]args）
{
Console.WriteLine（“名称”）；
string name=“FIRSTNAME”；
Console.WriteLine（“姓氏”）；
字符串lastname=“lastname”；
int i；
var nchars=name.ToCharArray（）；
var pchars=lastname.ToCharArray（）；
var ncharscont=nchars.Length；
var pcharsCount=pchars.长度；
//对于（i=0；i让我们将初始问题分成几个简单的问题：

CircularSubstring
，例如，对于
value=“12345”，index=4，length=3，我们得到
“512”

MyGemerator
生成
“FILA”、“RSST”
等
所需格式的最终输出
代码：

private static String CircularSubstring(string value, int index, int length) {
  StringBuilder sb = new StringBuilder(length);

  // + + value.Length) % value.Length - 
  // .Net can return negative remainder when we want it to be in [0..value.Length) 
  for (int i = 0; i < length; ++i)
    sb.Append(value[((index + value.Length + i) % value.Length + value.Length) % value.Length]);

  return sb.ToString();
}

private static IEnumerable<string> MyGenerator(string left, string right, int size) {
  for (int i = 0; ; i += size) 
    yield return CircularSubstring(left, i, size) + CircularSubstring(right, i, size);
}

1FILA
2RSST
3TNNA
4AMME
5EFLA
6IRST
7STNA
8NAME
9MELA
10FIST

Console.Write(string.Join(Environment.NewLine, MyGenerator("Stack", "Overflow", 3)
  .Take(12)
  .Select((item, index) => $"{index + 1,2}. {item}")
));

 1. StaOve
 2. ckSrfl
 3. tacowO
 4. kStver
 5. ackflo
 6. StawOv
 7. ckSerf
 8. taclow
 9. kStOve
10. ackrfl
11. StaowO
12. ckSver

结果：

private static String CircularSubstring(string value, int index, int length) {
  StringBuilder sb = new StringBuilder(length);

  // + + value.Length) % value.Length - 
  // .Net can return negative remainder when we want it to be in [0..value.Length) 
  for (int i = 0; i < length; ++i)
    sb.Append(value[((index + value.Length + i) % value.Length + value.Length) % value.Length]);

  return sb.ToString();
}

private static IEnumerable<string> MyGenerator(string left, string right, int size) {
  for (int i = 0; ; i += size) 
    yield return CircularSubstring(left, i, size) + CircularSubstring(right, i, size);
}

1FILA
2RSST
3TNNA
4AMME
5EFLA
6IRST
7STNA
8NAME
9MELA
10FIST

Console.Write(string.Join(Environment.NewLine, MyGenerator("Stack", "Overflow", 3)
  .Take(12)
  .Select((item, index) => $"{index + 1,2}. {item}")
));

 1. StaOve
 2. ckSrfl
 3. tacowO
 4. kStver
 5. ackflo
 6. StawOv
 7. ckSerf
 8. taclow
 9. kStOve
10. ackrfl
11. StaowO
12. ckSver

更多演示：

private static String CircularSubstring(string value, int index, int length) {
  StringBuilder sb = new StringBuilder(length);

  // + + value.Length) % value.Length - 
  // .Net can return negative remainder when we want it to be in [0..value.Length) 
  for (int i = 0; i < length; ++i)
    sb.Append(value[((index + value.Length + i) % value.Length + value.Length) % value.Length]);

  return sb.ToString();
}

private static IEnumerable<string> MyGenerator(string left, string right, int size) {
  for (int i = 0; ; i += size) 
    yield return CircularSubstring(left, i, size) + CircularSubstring(right, i, size);
}

1FILA
2RSST
3TNNA
4AMME
5EFLA
6IRST
7STNA
8NAME
9MELA
10FIST

Console.Write(string.Join(Environment.NewLine, MyGenerator("Stack", "Overflow", 3)
  .Take(12)
  .Select((item, index) => $"{index + 1,2}. {item}")
));

 1. StaOve
 2. ckSrfl
 3. tacowO
 4. kStver
 5. ackflo
 6. StawOv
 7. ckSerf
 8. taclow
 9. kStOve
10. ackrfl
11. StaowO
12. ckSver

结果：

private static String CircularSubstring(string value, int index, int length) {
  StringBuilder sb = new StringBuilder(length);

  // + + value.Length) % value.Length - 
  // .Net can return negative remainder when we want it to be in [0..value.Length) 
  for (int i = 0; i < length; ++i)
    sb.Append(value[((index + value.Length + i) % value.Length + value.Length) % value.Length]);

  return sb.ToString();
}

private static IEnumerable<string> MyGenerator(string left, string right, int size) {
  for (int i = 0; ; i += size) 
    yield return CircularSubstring(left, i, size) + CircularSubstring(right, i, size);
}

1FILA
2RSST
3TNNA
4AMME
5EFLA
6IRST
7STNA
8NAME
9MELA
10FIST

Console.Write(string.Join(Environment.NewLine, MyGenerator("Stack", "Overflow", 3)
  .Take(12)
  .Select((item, index) => $"{index + 1,2}. {item}")
));

 1. StaOve
 2. ckSrfl
 3. tacowO
 4. kStver
 5. ackflo
 6. StawOv
 7. ckSerf
 8. taclow
 9. kStOve
10. ackrfl
11. StaowO
12. ckSver

或者加上一些数不清的爱

public class Program
{
    public static void Main(string[] args)
    {
        Console.WriteLine("Name");
        string name = Console.ReadLine();
        Console.WriteLine("Lastname");
        string lastname = Console.ReadLine();

        // set the number of required sets and size
        const int sets = 10;
        const int size = 2;

        // make both inputs long enough
        var input1 = string.Concat(Enumerable.Repeat(name, (Math.Abs((sets * size) / name.Length) + 1)));
        var input2 = string.Concat(Enumerable.Repeat(lastname, (Math.Abs((sets * size) / lastname.Length) + 1)));

        // enumerate the index so we can substring the inputs.    
        var results = Enumerable.Range(0, sets)
            .Select(x => $"{x + 1}{input1.Substring(x * size, size)}{input2.Substring(x * size, size)}");

        // optional write to console
        foreach(var result in results)
        {
            Console.WriteLine(result);
        }
    }
}

在
for
循环中，您将
ctr
增加2，您的条件为
ctr<10
，因此它只给出4个结果。您期望的10个结果是什么？我得到一个索引越界错误。我想您可能需要设置每个字符串的长度（FIRSTNAME=9，LASTNAME=8）。并在每个循环中检查您是否没有超过该长度。当您确实超过该长度时，您需要将ctr变量滚动到超出长度的字符串的开头。@OlivierRogier我期望的十个结果是FILA、RSST、TNNA、AMME、EFLA、IRST、STNA、NAME、MELA、FIST.Lovely。谢谢很多。这正是我所需要的。谢谢，非常有帮助，而且确实有效，但我希望保持它尽可能简单。接近，但输出不是预期的