如何用xml序列化包含c#中其他类对象的对象?

如何用xml序列化包含c#中其他类对象的对象?,c#,xml,serialization,C#,Xml,Serialization,我想用xml序列化包含其他自定义对象的自定义对象。我像下面那样做,但不起作用 class A() { public B b; } class B() { public int a; } System.Xml.Serialization.XmlSerializer writer = new System.Xml.Serialization.XmlSerializer(typeof(A)); XmlAttributes xmlAttributes = new XmlAttributes();

我想用xml序列化包含其他自定义对象的自定义对象。我像下面那样做,但不起作用

class A()
{
public B b;
}

class B()
{
public int a;
}

System.Xml.Serialization.XmlSerializer writer = new System.Xml.Serialization.XmlSerializer(typeof(A));  
XmlAttributes xmlAttributes = new XmlAttributes();   
System.IO.StreamWriter file = new System.IO.StreamWriter(   @"d:\SerializationOverview.xml");
writer.Serialize(file, new A());  
file.Close();
结果是:

<A>
</A>

首先,
A
B
都需要标记为
public

newa()
b
中没有要序列化的值;它不会序列化空值。给它一个值:

writer.Serialize(file, new A { b = new B { a = 123 } });
另外:尽量选择属性而不是公共字段

例如:

using System.IO;
using System.Xml.Serialization;
public class A
{
    public B B { get; set; }
}
public class B
{
    public int A {get;set;}
}
static class Program
{
    static void Main()
    {
        var writer = new XmlSerializer(typeof(A));
        using (var file = File.Create(@"SerializationOverview.xml"))
        {
            writer.Serialize(file, new A { B = new B { A = 123 } });
        }
    }
}