C# 新行参数问题中的Visual studio和string.format

我重写了我的ToString（）方法，我的类包含许多字段。
我只能在最后一个字符串后有新行，并且只能将变量放在下一行。
注-这只是为了视觉目的，我不希望打印之间有一条线分开。。只看到我的21英寸屏幕上的整行而不滚动

这项工作：

    public override string ToString()
    {
        return String.Format("{0}, IsAccessible = {1}, NetworkAddress = {2}, Manufacturer = {3}, Model = {4}, Firmware = {5}, Driver = {6}, MacAddress = {7}, Scenes count = {8}",
            base.ToString(), IsAccessible, NetworkAddress, Manufacturer, Model, Firmware, Driver, MacAddress, Scenes.Count);
    }

但这不起作用（相同代码，仅在第四个参数后按enter键）：

---

我唯一能想到的是：

public override string ToString()
{
    return String.Format(
        "{0}, IsAccessible = {1}, NetworkAddress = {2}, Manufacturer = {3},"
        + " Model = {4}, Firmware = {5}, Driver = {6}, MacAddress = {7},"
        + " Scenes count = {8}",
        base.ToString(), IsAccessible, NetworkAddress, Manufacturer, Model, Firmware, Driver, MacAddress, Scenes.Count);
}

---

我唯一能想到的是：

public override string ToString()
{
    return String.Format(
        "{0}, IsAccessible = {1}, NetworkAddress = {2}, Manufacturer = {3},"
        + " Model = {4}, Firmware = {5}, Driver = {6}, MacAddress = {7},"
        + " Scenes count = {8}",
        base.ToString(), IsAccessible, NetworkAddress, Manufacturer, Model, Firmware, Driver, MacAddress, Scenes.Count);
}

---

String

是引号之间一行中的符号序列

"one two" - is string.
"one
  two" - is an error.

通过连接有效字符串，可以在c#中创建多行字符串：

String s = "one" + Environment.NewLine + 
           " two";

或者在字符串之前添加

@

String s = @"one
             two";

---

String

是引号之间一行中的符号序列

"one two" - is string.
"one
  two" - is an error.

通过连接有效字符串，可以在c#中创建多行字符串：

String s = "one" + Environment.NewLine + 
           " two";

或者在字符串之前添加

@

String s = @"one
             two";

---

使用逐字字符串，该字符串以@字符开头：

public override string ToString()
{
    return String.Format(@"{0}, IsAccessible = {1}, NetworkAddress = {2}, Manufacturer = {3}, Model = {4},
    Firmware = {5}, Driver = {6}, MacAddress = {7}, Scenes count = {8}",
        base.ToString(), IsAccessible, NetworkAddress, Manufacturer, Model, Firmware, Driver, MacAddress, Scenes.Count);
}

---

使用逐字字符串，该字符串以@字符开头：

public override string ToString()
{
    return String.Format(@"{0}, IsAccessible = {1}, NetworkAddress = {2}, Manufacturer = {3}, Model = {4},
    Firmware = {5}, Driver = {6}, MacAddress = {7}, Scenes count = {8}",
        base.ToString(), IsAccessible, NetworkAddress, Manufacturer, Model, Firmware, Driver, MacAddress, Scenes.Count);
}

试试这个：

string temp_var = @"{0}, IsAccessible = {1}, NetworkAddress = {2}, Manufacturer = {3}, Model = {4},
          Firmware = {5}, Driver = {6}, MacAddress = {7}, Scenes count = {8}";
temp_var = string.Format(base.ToString(), IsAccessible, NetworkAddress, Manufacturer, Model, Firmware, Driver, MacAddress, Scenes.Count);
return temp_var;

只需将值分配给字符串变量。

尝试以下操作：

string temp_var = @"{0}, IsAccessible = {1}, NetworkAddress = {2}, Manufacturer = {3}, Model = {4},
          Firmware = {5}, Driver = {6}, MacAddress = {7}, Scenes count = {8}";
temp_var = string.Format(base.ToString(), IsAccessible, NetworkAddress, Manufacturer, Model, Firmware, Driver, MacAddress, Scenes.Count);
return temp_var;

---

仅将值分配给字符串变量。

您不能将字符串分成两段。我不希望剪切任何内容，我只想在Format语句之后，继续在editorPut@的新行上写入变量。然后，它将被解释为字符串。返回字符串。Format（@{0}，…您不能将字符串分为两段。我不希望剪切任何内容，我只想在您的Format语句之后，继续在editorPut@中的新行上写入变量。然后它将被解释为字符串。返回字符串。Format（@{0}，…）。。。