C# UIAutomation在不使窗口聚焦的情况下单击按钮，GetCurrentPattern（）返回不支持的模式

我有一个窗口的句柄，我想做的是点击它的按钮“加载设置”。我有两个问题

• 我的第一个问题是，当我对某个InvokePattern调用Invoke时，它会使窗口聚焦，这对我的应用程序来说是不可取的
• 我的第二个问题可见，并记录在我下面代码末尾的注释中：

  AutomationElement aeBot = AutomationElement.FromHandle(mbotSettingList.ElementAt(i).getWindowHandle());
  AutomationElement aeButtonLoadSettings = aeBot.FindFirst(TreeScope.Children, new PropertyCondition(AutomationElement.NameProperty, "Load Settings"));
  InvokePattern ipClickLoadSettings = (InvokePattern)aeButtonLoadSettings.GetCurrentPattern(InvokePattern.Pattern);
  Thread invokeLoadSettingsThread = new Thread(ipClickLoadSettings.Invoke);
  InvokePattern ipClickOpen = null;
  AutomationElement aeOpenDialogEdit = null;
  AutomationElement aeButtonOpen = null;
  AutomationElementCollection aeDialogs = null;
  AutomationElement aeOpenDialog = null;
  ValuePattern vpOpenDialogEdit = null;
  
  //Using a thread to invoke the Load Settings button click because as a result of clicking Load Settings a dialog is opened and invoke doesnt return for nealy 10 seconds
  invokeLoadSettingsThread.Start();
  //We probably wont join() this thread because it goes on for far longer than we expect to be in this function
  
  //Get a collection of the Dialog windows that are direct children of the main window we have a handle to
  aeDialogs = aeBot.FindAll(TreeScope.Children, new PropertyCondition(AutomationElement.ClassNameProperty, "#32770"));
  
  while (aeDialogs.Count == 0)
  {
      //This while loop is to continue to check for the Open file dialog as it may take a little time to open
      aeDialogs = aeBot.FindAll(TreeScope.Children, new PropertyCondition(AutomationElement.ClassNameProperty, "#32770"));
      Thread.Sleep(250);
  }
  
  for (int j = 0; j < aeDialogs.Count; j++)
  {
      //There is usually only 1 child dialog window, but just make sure we have the correct one
      if (aeDialogs[j].Current.Name == "Open")
      {
          Debug.WriteLine("Found open dialog!");
          aeOpenDialog = aeDialogs[j];
          break;
      }
  }
  
  //Inside the Open window, the first Edit window is the one where the file name/path should be entered
  aeOpenDialogEdit = aeOpenDialog.FindFirst(TreeScope.Descendants, new PropertyCondition(AutomationElement.ClassNameProperty, "Edit"));
  
  //Set the value of the file name/path to the string variable "loadSettingsString"
  vpOpenDialogEdit = (ValuePattern)aeOpenDialogEdit.GetCurrentPattern(ValuePattern.Pattern); 
  vpOpenDialogEdit.SetValue(loadSettingsString);
  
  //******************************************PROBLEM BEGINING BELOW******************************************
  
  //Using multiple methods, we can successfully get a successful AutomationElement for the "Open" button in the Open file dialog
  aeButtonOpen = aeOpenDialog.FindFirst(TreeScope.Subtree, new PropertyCondition(AutomationElement.NameProperty, "Open"));
  
  //aeButtonOpen = aeOpenDialog.FindFirst(TreeScope.Subtree, new PropertyCondition(AutomationElement.NameProperty, "Cancel"));
  //Something to consider: If we assigned aeButtonOpen to the AutomationElement we find be looking for "Cancel" rather than "Open"
  
  Debug.WriteLine(aeButtonOpen.Current.Name + " button found!");
  //Prints "Open button found!"
  //If aeButtonOpen were assigned to "Cancel", this would print "Cancel button found!"
  
  ipClickOpen = (InvokePattern)aeButtonOpen.GetCurrentPattern(InvokePattern.Pattern);
  //GetCurrentPattern has returned null
  //If aeButtonOpen were assigned to "Cancel", this would NOT be null
  
  ipClickOpen.Invoke();
  //Invoke() on a null results in "Unsupported Pattern" exception
  //If aeButtonOpen were assigned to "Cancel", this would work and the Open file dialog would then be exited just as if cancel were clicked
  

  AutomationElement aeBot=AutomationElement.FromHandle（mbotSettingList.ElementAt（i）.getWindowHandle（））；
  AutomationElement aeButtonLoadSettings=aeBot.FindFirst（TreeScope.Children，新属性条件（AutomationElement.NameProperty，“加载设置”）；
  InvokePattern ipClickLoadSettings=（InvokePattern）aeButtonLoadSettings.GetCurrentPattern（InvokePattern.Pattern）；
  Thread invokeLoadSettingsThread=新线程（ipClickLoadSettings.Invoke）；
  InvokePattern ipClickOpen=null；
  AutomationElement aeOpenDialogEdit=null；
  AutomationElement aeButtonOpen=null；
  AutomationElementCollection aeDialogs=null；
  AutomationElement aeOpenDialog=null；
  ValuePattern vpOpenDialogEdit=null；
  //使用线程调用Load Settings按钮单击，因为单击Load Settings会打开一个对话框，并且invoke在短短10秒钟内不会返回
  invokeLoadSettingsThread.Start（）；
  //我们可能不会加入（）这个线程，因为它持续的时间比我们预期的要长得多
  //获取对话框窗口的集合，这些窗口是我们拥有句柄的主窗口的直接子窗口
  aeDialogs=aeBot.FindAll（TreeScope.Children，新属性条件（AutomationElement.ClassNameProperty，“#32770”）；
  而（aeDialogs.Count==0）
  {
  //此while循环将继续检查“打开文件”对话框，因为打开该对话框可能需要一点时间
  aeDialogs=aeBot.FindAll（TreeScope.Children，新属性条件（AutomationElement.ClassNameProperty，“#32770”）；
  睡眠（250）；
  }
  对于（int j=0；j

用于查看应用程序的UIA树。查看您的代码，我怀疑您没有检索到您认为是的元素。如果“Open”元素是一个按钮，那么它应该支持Invoke模式

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或者，打开一个对话框，然后立即搜索该对话框的子元素。您可能在此处遇到了可靠性问题，此时仍在为该对话框创建UIA树。要检查这一点，请添加一秒钟的睡眠，看看这是否解决了您的问题。如果是这种情况，请查看UIA结构更改事件。这些事件将允许您根据UIA树中的更改同步UIA测试代码。

可能的问题是，我现在看到“打开”按钮实际上是一个拆分按钮，我不确定这是如何导致我的问题的，如果是这样的话。您真的需要使用UIA验证来查看您正在查找的元素。详细说明拆分按钮在树中的外观。您可能需要选择菜单项（请参阅SelectionItem模式），然后在button元素上使用Invoke模式。除非您定义自己的可访问对等方并实现其调用模式，这样您就不可能在调用invoke时设置焦点，否则无法阻止设置焦点。我建议在调用invoke之前找到具有焦点的元素，并在调用invoke之后再次赋予它焦点。如果您能告诉我为什么不希望被测应用程序接收焦点，我可能会想出一个更好的主意。不希望被测应用程序接收焦点的目的是，该应用程序的典型用户将在某个游戏中处于全屏模式，并且一旦他们按下某个键盘按键我正在创建的应用程序应该去“点击”另一个“正在测试”的应用程序上的某些按钮。这另一个应用程序是做什么的？保存游戏重播？它控制游戏中的角色，它是一个机器人。