返回字符串的c#方法?
这个方法应该有一个循环并返回一个字符串。我该怎么做?这就是我目前所拥有的。我是C#的新手返回字符串的c#方法?,c#,loops,C#,Loops,这个方法应该有一个循环并返回一个字符串。我该怎么做?这就是我目前所拥有的。我是C#的新手 ++我尝试了您建议的所有方法,但我认为应该重新表述该方法应该返回一个由main打印的字符串。如果要返回字符串,而不仅仅是添加一个return语句 public string BLoop() { for (int i = 99; i > 0; i--) { Console.WriteLine(string.Format("{0} bottles o
++我尝试了您建议的所有方法,但我认为应该重新表述该方法应该返回一个由main打印的字符串。如果要返回字符串,而不仅仅是添加一个
return
语句
public string BLoop()
{
for (int i = 99; i > 0; i--)
{
Console.WriteLine(string.Format("{0} bottles of beer on the wall, {0} bottles of beer.", i));
Console.WriteLine(string.Format("Take one down, pass it around, {1} bottles of beer on the wall.", i, i - 1));
Console.WriteLine();
}
return "a string";
}
您可以使用
return
关键字:
public string BLoop()
{
for (int i = 99; i > 0; i--)
{
Console.WriteLine(string.Format("{0} bottles of beer on the wall, {0} bottles of beer.", i));
Console.WriteLine(string.Format("Take one down, pass it around, {1} bottles of beer on the wall.", i, i - 1));
Console.WriteLine();
}
return "this is some string to return";
}
我假设您需要返回在循环中构造的字符串(而不是像其他答案中那样返回任意字符串)。您需要构建一个字符串,而不仅仅是写出字符串,然后返回该字符串:
public string BLoop()
{
var builder = new StringBuilder();
for (int i = 99; i > 0; i--)
{
builder.AppendLine(string.Format("{0} bottles of beer on the wall, {0} bottles of beer.", i));
builder.AppendLine(string.Format("Take one down, pass it around, {0} bottles of beer on the wall.", i-1));
}
return builder.ToString();
}
请注意,我还修改了循环的第二行,以消除多余的字符串。Format
参数。用于在循环中构建字符串,然后返回其字符串值
public string BLoop()
{
StringBuilder sb = new StringBuilder();
for (int i = 99; i > 0; i--)
{
sb.AppendLine(string.Format("{0} bottles of beer on the wall, {0} bottles of beer.", i));
sb.AppendLine(string.Format("Take one down, pass it around, {1} bottles of beer on the wall.", i, i - 1));
sb.AppendLine(Environment.NewLine);
}
return sb.ToString();
}
不知道你到底想要什么,但是如果你想把整首歌作为一个大字符串返回,那么就这样做:
public string BLoop()
{
var song = new System.Text.StringBuilder();
for (int i = 99; i > 0; i--)
{
song.AppendLine(string.Format("{0} bottles of beer on the wall, {0} bottles of beer.", i));
song.AppendLine(string.Format("Take one down, pass it around, {1} bottles of beer on the wall.", i, i - 1));
song.AppendLine();
}
return song.ToString();
}
希望这有帮助…祝你好运 这只是一个最简单问题的另一个答案。在循环后使用“return”语句
public string BLoop()
{
string sStatus = "Process Started";
Console.WriteLine(sStatus);
for (int i = 99; i > 0; i--)
{
Console.WriteLine(string.Format("{0} bottles of beer on the wall, {0} bottles of beer.", i));
Console.WriteLine(string.Format("Take one down, pass it around, {1} bottles of beer on the wall.", i, i - 1));
Console.WriteLine();
}
sStatus = "Process Completed";
return sStatus;
}
请首先……这是c#and development的基础。请在要求我们做家庭作业或做任何你正在做的事情之前先学一点。我尝试了你建议的所有方法,但我认为我应该重新表述这个方法,它应该返回一个由main打印的字符串。-这正是我的答案。我在这篇帖子上窃笑。不错,而且它确实回答了这个问题^
public string BLoop()
{
string sStatus = "Process Started";
Console.WriteLine(sStatus);
for (int i = 99; i > 0; i--)
{
Console.WriteLine(string.Format("{0} bottles of beer on the wall, {0} bottles of beer.", i));
Console.WriteLine(string.Format("Take one down, pass it around, {1} bottles of beer on the wall.", i, i - 1));
Console.WriteLine();
}
sStatus = "Process Completed";
return sStatus;
}