C# C在长字符串上每隔一个逗号拆分字符串

我有一个字符串，看起来像这样：

string  a =  "Stuff, another thing, random stuff, snuff, Pigs are wierd, sick, Cats are dangerous, they will kill you, Cows produce milk, but horses don't"

我的目标是检索一个如下所示的字符串

string output =  "Stuff, another thing
                  Random stuff, snuff
                  Pigs are wierd, sick
                  Cats are dangerous, they will kill you
                  Cows produce milk, but horses don't"

试图用正则表达式来实现这一点，但如果字符串以一种好的方式变长的话，就无法真正让它正确分组

string[] output = Regex.Split(a, "^([^,]+(?:,[^,]+){1})");

---

有什么建议吗

将其沿所有逗号拆分，然后重新组合成逗号分隔的对

using System;

public class Program
{
    public static void Main()
    {
        string  a =  "Stuff, another thing, random stuff, snuff, Pigs are wierd, sick, Cats are dangerous, they will kill you, Cows produce milk, but horses don't";
        string[] splittedStrings = a.Split(new[]{", "}, StringSplitOptions.None);
        for (var i = 0; i < splittedStrings.Length / 2; i++)
        {
            Console.WriteLine(splittedStrings[i*2] + ", " + splittedStrings[i*2 + 1]);
        }

        if(splittedStrings.Length % 2 == 1)
        {
            Console.WriteLine(splittedStrings[splittedStrings.Length-1]);
        }
    }
}

---

将其沿所有逗号拆分，然后重新组合成逗号分隔的对

using System;

public class Program
{
    public static void Main()
    {
        string  a =  "Stuff, another thing, random stuff, snuff, Pigs are wierd, sick, Cats are dangerous, they will kill you, Cows produce milk, but horses don't";
        string[] splittedStrings = a.Split(new[]{", "}, StringSplitOptions.None);
        for (var i = 0; i < splittedStrings.Length / 2; i++)
        {
            Console.WriteLine(splittedStrings[i*2] + ", " + splittedStrings[i*2 + 1]);
        }

        if(splittedStrings.Length % 2 == 1)
        {
            Console.WriteLine(splittedStrings[splittedStrings.Length-1]);
        }
    }
}

---

这里有一种通过c实现的方法

拆分字符串并将“，”保留在偶数idex上，以便0 2 4仍包含逗号

var SplittedWithComAsonevenIndex=a.Split'，'。选择值，索引=>value+索引%2==0？，：

把绳子连接起来

var result=string.Join，用comasonevenindex拆分

结果如下 **

东西，另一件随机的东西，鼻烟猪很瘦，病猫很瘦 危险的是，他们会杀了你奶牛会产奶，但马不会

---

**这里有一种通过c实现的方法

拆分字符串并将“，”保留在偶数idex上，以便0 2 4仍包含逗号

var SplittedWithComAsonevenIndex=a.Split'，'。选择值，索引=>value+索引%2==0？，：

把绳子连接起来

var result=string.Join，用comasonevenindex拆分

结果如下 **

东西，另一件随机的东西，鼻烟猪很瘦，病猫很瘦 危险的是，他们会杀了你奶牛会产奶，但马不会

---

**请尝试此代码。您不应该使用正则表达式的Split函数。你应该使用火柴

        string a = "Stuff, another thing, random stuff, snuff, Pigs are wierd, sick, Cats are dangerous, they will kill you, Cows produce milk, but horses don't";
        var output = Regex.Matches(a, "[^,]+,[^,]+,*");
        StringBuilder sb = new StringBuilder();
        foreach(Match item in output)
        {
            sb.AppendLine(item.Value.Trim(','));
        }
        Console.WriteLine(sb.ToString());

---

请尝试此代码。您不应该使用正则表达式的Split函数。你应该使用火柴

        string a = "Stuff, another thing, random stuff, snuff, Pigs are wierd, sick, Cats are dangerous, they will kill you, Cows produce milk, but horses don't";
        var output = Regex.Matches(a, "[^,]+,[^,]+,*");
        StringBuilder sb = new StringBuilder();
        foreach(Match item in output)
        {
            sb.AppendLine(item.Value.Trim(','));
        }
        Console.WriteLine(sb.ToString());

---

我也会拆分和重新组装，但我会制作一个更健壮的解决方案来处理无逗号和奇数对

    public static IEnumerable<string> SplitGroup(this string input, char delimiter)
    {
        var fields = input.Split(delimiter);
        var items = new List<string>();
        var enumerator = fields.GetEnumerator();

        //this will handle no commas, and not and even number of pairs
        while (enumerator.MoveNext())
        {
            var first = enumerator.Current;
            var hasNext = enumerator.MoveNext();
            var second = hasNext ? enumerator.Current : "";

            items.Add(String.Format("{0}{1}{2}", first, hasNext ? "," : "", second));
        }

        return items;
    }

---

我也会拆分和重新组装，但我会制作一个更健壮的解决方案来处理无逗号和奇数对

    public static IEnumerable<string> SplitGroup(this string input, char delimiter)
    {
        var fields = input.Split(delimiter);
        var items = new List<string>();
        var enumerator = fields.GetEnumerator();

        //this will handle no commas, and not and even number of pairs
        while (enumerator.MoveNext())
        {
            var first = enumerator.Current;
            var hasNext = enumerator.MoveNext();
            var second = hasNext ? enumerator.Current : "";

            items.Add(String.Format("{0}{1}{2}", first, hasNext ? "," : "", second));
        }

        return items;
    }

---

如果插入System.Interactive NuGet软件包，则可以执行以下操作：

var result =
    String.Join(
        Environment.NewLine,
        a.Split(',').Buffer(2).Select(x => String.Join(",", x)));

---

如果插入System.Interactive NuGet软件包，则可以执行以下操作：

var result =
    String.Join(
        Environment.NewLine,
        a.Split(',').Buffer(2).Select(x => String.Join(",", x)));

---

问题提到，他们需要每隔一个逗号，因此偶数indexomma分隔对的所有逗号=item1，item2。作为旁注，问题没有指定如果最后一个索引为偶数，是否需要逗号。问题提到，他们需要每隔一个逗号，因此偶数索引的所有逗号逗号分隔对=item1，item2。作为旁注，该问题没有指定如果最后一个索引为偶数，是否需要逗号。