编译调用Surface低级CUDA API的代码时出现奇怪的错误
这是一个最简单的例子:编译调用Surface低级CUDA API的代码时出现奇怪的错误,cuda,nvcc,Cuda,Nvcc,这是一个最简单的例子: int main() { struct surfaceReference* surfaceReferencePointer; cudaGetSurfaceReference(&surfaceReferencePointer, "surfaceReference"); } 按如下方式编译时失败: nvcc -g -arch=sm_20 -o foo.out foo.cu 显示以下错误消息: foo.cu(4): warning: argume
int main()
{
struct surfaceReference* surfaceReferencePointer;
cudaGetSurfaceReference(&surfaceReferencePointer, "surfaceReference");
}
按如下方式编译时失败:
nvcc -g -arch=sm_20 -o foo.out foo.cu
显示以下错误消息:
foo.cu(4): warning: argument of type "surfaceReference **" is incompatible with parameter of type "const surfaceReference **"
foo.cu(4): warning: argument of type "surfaceReference **" is incompatible with parameter of type "const surfaceReference **"
foo.cu: In function ‘int main()’:
foo.cu:4: error: invalid conversion from ‘surfaceReference**’ to ‘const surfaceReference**’
foo.cu:4: error: initializing argument 1 of ‘cudaError_t cudaGetSurfaceReference(const surfaceReference**, const char*)’
我无法理解我做错了什么。我在Linux Ubuntu 64位机器上编译,使用CUDA3.2 应将
struct surfaceReference*
指针定义为const
:
int main()
{
const struct surfaceReference* surfaceReferencePointer;
cudaGetSurfaceReference(&surfaceReferencePointer, "surfaceReference");
}
感谢,他在评论中提供了正确的答案。您应该将指针定义为您是对的!请将您的评论作为答案发布,以便我可以接受。谢谢