如何在不必提及的情况下将成员添加到角色中？[Discord.JS]

目前，我正试图为我的机器人制作一个角色命令。例如：

t！角色添加@person

。但是我不知道如何获得角色，因为人们有不同长度的用户名，所以我无法使用

.slice

创建角色

目前我的机器人说它找不到那个角色

我的代码：

const config = require("../../config.json");

module.exports = {
    name: "role",
    description: "Creates/removes roles from server and adds/removes roles from members",
    category: "utility",
    run: async (client, message, args) => {
        const mentionedMember = message.mentions.members.first();
        let messageRole = message.content.slice(config.prefix.length + 12).trim();
        const findRole = message.guild.roles.cache.find(r => r.name === messageRole);

        if (!message.member.permissions.has("MANAGE_ROLES")) return message.channel.send("You do not have permission to use this command");

        if (args[0].toLowerCase() == "create") {
            let roleName = message.content.slice(config.prefix.length + 12);
            if (!roleName) return message.channel.send("You need to specify a name for the role");
            let newRole = await message.guild.roles.create({ data: { name: roleName, permissions: false } });
            message.channel.send(`**${roleName}** has been created`);

        } else if (args[0].toLowerCase() === "delete") {
            if (!findRole) return message.channel.send("You need to specify a role to be deleted\n\n" + messageRole);
            findRole.delete();
            message.channel.send(`${findRole.name} has been deleted`);

        } else if (args[0].toLowerCase() === "add") {
            if (!args[1]) return message.channel.send("You need to mention the member you want to give the role to");
            if (!mentionedMember) return message.channel.send("I can't find that member");
            if (!args[2]) return message.channel.send("You need to specify a role I have to give");
            if (!findRole) return message.channel.send("I can't find that role");

            if (mentionedMember.roles.cache.has(findRole)) return message.channel.send(`${mentionedMember.name} already has that role`);
            mentionedMember.addRole(findRole);
            message.channel.send(`${mentionedMember.name} has been given the role ${findRole.name}`)
            return undefined

        } else if (args[0].toLowerCase() === "remove") {
            if (!args[1]) return message.channel.send("You need to mention the member you want to remove the role from");
            if (!mentionedMember) return message.channel.send("I can't find that member");
            if (!args[2]) return message.channel.send("You need to specify a role I have to remove");
            if (!mentionedRole) return message.channel.send("I can't find that role");

            if (!mentionedMember.roles.cache.has(mentionedRole.id)) return message.channel.send(`${mentionedMember} doesnt have that role`);
            mentionedMember.roles.remove(mentionedRole.id);
            message.channel.send(`**${mentionedRole.name}** has been removed from ${mentionedMember}`);
            return undefined
        }
    }
}

---

切片

参数的数量

。如果对数组进行切片，它将从中删除一个整数值

[1,2,3]。切片（2）
//结果：[3]

---

由于

args

是一个数组，您所要做的就是

args.slice（2）

，假设

args

不包含命令消息。

您好，谢谢您的回复！我已经尝试过了，但是当我尝试

args.slice（2）

或者对于这个问题，机器人回答说：“add@Dennis a”不是一个角色，虽然args.shift似乎有帮助，但我还没有找到如何转换2个参数的方法。为什么不使用

message.indications.roles

？