Django 用户没有配置文件

这是我在这个网站上的第一个问题，如果有错误的地方，请原谅。如果有更具体的东西要展示，请与我联系，谢谢。我刚刚运行了Django程序，有错误。我已经搜索了很长时间，但我无法修复它。当我转到详细信息页面时，错误发生了

型号.py

class UserProfile(models.Model):
    belong_to = models.OneToOneField(to=User, related_name='profile',on_delete = models.CASCADE)
    profile_image = models.FileField(upload_to='profile_image')

def detail(request, id):
    context = {}
    vid_info = Video.objects.get(id=id)
    voter_id = request.user.profile.id
    like_counts = Ticket.objects.filter(choice='like', video_id=id).count()
    try:
        user_ticket_for_this_video = Ticket.objects.get(voter_id=voter_id, video_id=id)
        context['user_ticket'] = user_ticket_for_this_video
    except:
        pass
    context['vid_info'] = vid_info
    context['like_counts'] = like_counts
    return render(request, 'detail.html', context)

view.py

class UserProfile(models.Model):
    belong_to = models.OneToOneField(to=User, related_name='profile',on_delete = models.CASCADE)
    profile_image = models.FileField(upload_to='profile_image')

def detail(request, id):
    context = {}
    vid_info = Video.objects.get(id=id)
    voter_id = request.user.profile.id
    like_counts = Ticket.objects.filter(choice='like', video_id=id).count()
    try:
        user_ticket_for_this_video = Ticket.objects.get(voter_id=voter_id, video_id=id)
        context['user_ticket'] = user_ticket_for_this_video
    except:
        pass
    context['vid_info'] = vid_info
    context['like_counts'] = like_counts
    return render(request, 'detail.html', context)

---

问题来自这一行

voter\u id=request.user.profile.id

当前用户没有任何附加的UserProfile实例，请尝试将UserProfile添加到

request.user

中，您能告诉我如何创建附加的配置文件实例吗？在此之前，您能告诉我您是如何处理模型

UserProfile

，如何创建

UserProfile

？以及在视图中执行此操作的位置。。