Django 限制从多个ForeignKey显示的选项

如何限制通过ManyToMany关系返回的值，从而将其显示在表单的

字段中，以仅显示当前登录用户创建的点

models.py

class Project(models.Model):
    owner = models.ForeignKey(User, editable=False)
    ...
    spots = models.ManyToManyField(to='Spot', blank=True, )

    class Spot(models.Model):
        owner = models.ForeignKey(User, editable=False)
        spot_name = models.CharField(max_length=80, blank=False)

forms.py

from django import forms
from .models import Project, Spot


class ProjectForm(forms.ModelForm):
    class Meta:
        model = Project
        exclude = ('owner', )


class SpotForm(forms.ModelForm):
    class Meta:
        model = Spot
        exclude = ('owner', )

class ProjectForm(forms.ModelForm):
    class Meta:
        model = Project
        exclude = ('owner', 'whispir_id')

    def __init__(self, *args, **kwargs):
        user_id = kwargs.pop('user')
        super(ProjectForm, self).__init__(*args, **kwargs)
        self.fields['spots'] = forms.ModelMultipleChoiceField(queryset=Spot.objects.filter(owner=user_id))


class SpotForm(forms.ModelForm):
    class Meta:
        model = Spot
        exclude = ('owner', )

    def __init__(self, *args, **kwargs):
        user_id = kwargs.pop('user')
        super(SpotForm, self).__init__(*args, **kwargs)
        self.fields['spot_name'] = forms.ModelMultipleChoiceField(queryset=Spot.objects.filter(owner=user_id))

我正在使用GenericView进行更新和创建，在更新或创建项目时，当前可以看到每个人在Spot中创建的所有条目。我只想看到登录用户输入的条目。为完整起见，是的，

project.owner

和

spot.owner

在创建时被设置为User

我在forms.py中尝试了defINIT，并在模型中的manytoman字段上使用了limit_choices_to。要么我都做错了，要么那不是正确的方法

谢谢大家!

在您的表单中。py

class ProjectForm(forms.ModelForm):
    class Meta:
        model = Project
        exclude = ('owner', )

    def __init__(self, user_id, *args, **kwargs):
        self.fields['spots'] = forms.ModelChoiceField(widget=forms.Select, queryset=Project.objects.filter(owner=user_id))


class SpotForm(forms.ModelForm):
    class Meta:
        model = Spot
        exclude = ('owner', )

    def __init__(self, user_id, *args, **kwargs):
        self.fields['spot_name'] = forms.ModelChoiceField(widget=forms.Select, queryset=Spot.objects.filter(owner=user_id))

在您的视图中.py

user_id = Project.objects.get(owner=request.user).owner
project_form = ProjectForm(user_id)
spot_form = SpotForm(user_id)

---

正如我上面提到的，迪恩的回答非常接近，但对我来说并不奏效。主要是因为请求不能在视图中直接访问。也许是Django的旧版本？我在1点9分。谢谢你，迪恩，你帮我渡过了难关

其要点是将用户添加到视图中的kwargs中，将其传递到ModelForm，从kwargs中删除用户，并在显示表单之前使用它过滤斑点

这是为我的项目工作的代码：

views.py

class ProjectUpdate(UpdateView):
    model = Project
    success_url = reverse_lazy('projects-mine')
    form_class = ProjectForm

def dispatch(self, *args, **kwargs):
    return super(ProjectUpdate, self).dispatch(*args, **kwargs)

def get_form_kwargs(self):
    kwargs = super(ProjectUpdate, self).get_form_kwargs()
    kwargs.update({'user': self.request.user})
    return kwargs

forms.py

from django import forms
from .models import Project, Spot


class ProjectForm(forms.ModelForm):
    class Meta:
        model = Project
        exclude = ('owner', )


class SpotForm(forms.ModelForm):
    class Meta:
        model = Spot
        exclude = ('owner', )

class ProjectForm(forms.ModelForm):
    class Meta:
        model = Project
        exclude = ('owner', 'whispir_id')

    def __init__(self, *args, **kwargs):
        user_id = kwargs.pop('user')
        super(ProjectForm, self).__init__(*args, **kwargs)
        self.fields['spots'] = forms.ModelMultipleChoiceField(queryset=Spot.objects.filter(owner=user_id))


class SpotForm(forms.ModelForm):
    class Meta:
        model = Spot
        exclude = ('owner', )

    def __init__(self, *args, **kwargs):
        user_id = kwargs.pop('user')
        super(SpotForm, self).__init__(*args, **kwargs)
        self.fields['spot_name'] = forms.ModelMultipleChoiceField(queryset=Spot.objects.filter(owner=user_id))

---

我想我们有不同的版本，因为你的答案不适合我，但它非常接近，逻辑是我需要看到的。主要问题是您不能像在genric视图中那样访问请求对象。您必须重写一个方法或其他东西，然后可以通过self.request访问它。我马上发布答案。我使用的是1.8，你使用的是基于类的视图，这就是为什么我在views.py中的方法与你的方法不一样。但很高兴看到你解决了这个问题。