Django 模型管理员搜索-覆盖搜索字符串

我在ModelForm中有一个电话号码字段，用户可以在admin中搜索该字段。问题是他们很懒，不想在电话号码中输入破折号

def get_changelist(self, request, **kwargs):                                 
    # Allow users to not have to enter in '-' when searching by phone #      
    from django.contrib.admin.views.main import ChangeList                   

    class NewChangeList(ChangeList):                                         
        def get_query_set(self, *args, **kwargs):                            
            query = self.query                                               
            if query.isdigit() and len(query) == 10:                         
                self.query = '-'.join((query[:3], query[3:6], query[6:]))    

            return super(NewChangeList, self).get_query_set(*args, **kwargs) 

    return NewChangeList                                                     

如果我搜索“555-555-5555”，所有带有该电话号码的对象都将返回

def get_changelist(self, request, **kwargs):                                 
    # Allow users to not have to enter in '-' when searching by phone #      
    from django.contrib.admin.views.main import ChangeList                   

    class NewChangeList(ChangeList):                                         
        def get_query_set(self, *args, **kwargs):                            
            query = self.query                                               
            if query.isdigit() and len(query) == 10:                         
                self.query = '-'.join((query[:3], query[3:6], query[6:]))    

            return super(NewChangeList, self).get_query_set(*args, **kwargs) 

    return NewChangeList                                                     

如果我搜索“5555”，我得到的结果为零

def get_changelist(self, request, **kwargs):                                 
    # Allow users to not have to enter in '-' when searching by phone #      
    from django.contrib.admin.views.main import ChangeList                   

    class NewChangeList(ChangeList):                                         
        def get_query_set(self, *args, **kwargs):                            
            query = self.query                                               
            if query.isdigit() and len(query) == 10:                         
                self.query = '-'.join((query[:3], query[3:6], query[6:]))    

            return super(NewChangeList, self).get_query_set(*args, **kwargs) 

    return NewChangeList                                                     

是否要重写或只是更改提交的搜索字符串？如果是这样的话，我打算做类似的事情

if search_string.isdigit() and len(search_string) == 10:
    search_string = '-'.join(
        (search_string[:3],search_string[3:6],search_string[6:])
    )  

def get_changelist(self, request, **kwargs):                                 
    # Allow users to not have to enter in '-' when searching by phone #      
    from django.contrib.admin.views.main import ChangeList                   

    class NewChangeList(ChangeList):                                         
        def get_query_set(self, *args, **kwargs):                            
            query = self.query                                               
            if query.isdigit() and len(query) == 10:                         
                self.query = '-'.join((query[:3], query[3:6], query[6:]))    

            return super(NewChangeList, self).get_query_set(*args, **kwargs) 

    return NewChangeList                                                     

---

我在Django 1.6中看到了一个可能有用的方法，但我运行的是1.4

能够通过在我的ModelAdmin中重写

get\u changelist

来实现这一点。找到一篇有用的博客文章，让我找到了答案：

def get_changelist(self, request, **kwargs):                                 
    # Allow users to not have to enter in '-' when searching by phone #      
    from django.contrib.admin.views.main import ChangeList                   

    class NewChangeList(ChangeList):                                         
        def get_query_set(self, *args, **kwargs):                            
            query = self.query                                               
            if query.isdigit() and len(query) == 10:                         
                self.query = '-'.join((query[:3], query[3:6], query[6:]))    

            return super(NewChangeList, self).get_query_set(*args, **kwargs) 

    return NewChangeList