Django从相关表查询和值

我有两张桌子：

售票处

id  paid_with_tax
1   5
2   6
3   7

票证调整表

id  ticket_id  value_with_tax
1   1          2
2   1          1
3   1          2
4   1          3
5   2          5

我使用的查询：

use = 0

Ticket.objects.all().annotate(
   paid_amount=Sum(
        F('paid_with_tax') +
        Coalesce(F('ticketadjustment__value_with_tax'), 0) * use
    )
)

查询将返回以下内容：

[
    {id: 1, paid_amount: 7},
    {id: 1, paid_amount: 6},
    {id: 1, paid_amount: 7},
    {id: 1, paid_amount: 8},
    {id: 2, paid_amount: 11},
    {id: 3, paid_amount: 7},
]

[
    {id: 1, paid_amount: 13},
    {id: 2, paid_amount: 11},
    {id: 3, paid_amount: 7},
]

但上述内容不正确，因为票证表id=1的值与票证调整表的值重复

如何使查询对TicketAdjustment表的值求和并返回以下值：

[
    {id: 1, paid_amount: 7},
    {id: 1, paid_amount: 6},
    {id: 1, paid_amount: 7},
    {id: 1, paid_amount: 8},
    {id: 2, paid_amount: 11},
    {id: 3, paid_amount: 7},
]

[
    {id: 1, paid_amount: 13},
    {id: 2, paid_amount: 11},
    {id: 3, paid_amount: 7},
]

---

以下是您问题的解决方案：

Ticket.objects.all().annotate(
   paid_amount=(F('paid_with_tax') +
        Sum(Coalesce(F('ticketadjustment__value_with_tax'), 0))
    )
).values_list('id', 'paid_amount')

值\u列表

选择结果中所需的字段

在您的主要请求中存在一个大问题

Sum(F('paid_with_tax') + Coalesce(F('ticketadjustment__value_with_tax'), 0) * use)

这条直线的最小值为零。所以给你零分。就像：

Sum(F('paid_with_tax'))

您需要每张票的

value\u和\u tax

之和，这就是为什么我在上面移动

sum

：

Sum(Coalesce(F('ticketadjustment__value_with_tax'), 0)) 

加上

已缴纳税费的价值后

注意：我删除了变量

use

，因为我不知道目标是什么