如何在Django 2中合并两个原始查询？

我试图将两个查询返回数据合并到一个对象中，如

viewAllUq = Uqmain.objects.raw('''
                select *, uqmain.id as uqmainID, company.name as companyName, uqmain.created_by as uqMainCreated_by, 
                    company.slug as companySlug, uqmain.slug as uqmainSlug from uqmain 
                Left join company ON company.id = uqmain.company_id 
                Left join user ON user.id = uqmain.created_by 
                where uqmain.deleted = 0''')  

doneBids = Uqbids.objects.raw('''
                    select DISTINCT uq_main_id as bidDoneUqmain, id  from 
                      uqbids  where created_by = %s''',[request.user.id])

这里的viewallq和doneBids是两个原始查询，我想将此查询合并为一个查询，如

merged = viewAllUq + doneBids   #I want something like this to merge them

    for data in merged:
        print(data.companyName)  # Access viewAllUq object data 
        print(data.bidDoneUqmain) # Access doneBids object data

---

我做了一些谷歌搜索，但没有帮助我。

使用dict进行数据库查询可能更好。比如：

merged_dict ={"viewAllUq":viewAllUq, 
"doneBids": doneBids
}
view_all_uq = merged_dict.get("viewAllUq")

---

如果需要，您可以通过dict进行迭代。

谢谢您的回答。如果我做了

view\u all\u uq=merged\u dict.get（“viewallq”）

，那么我只能访问viewallq数据，但我想同时访问donebid。您的表uqmain和uqbids有关系吗？不，它们通过其他表没有关系吗？我用来充当外键概念。所以基本上他们没有关系。如果您打印view\u all\u uq，那么它只返回viewallq full query，而不返回doneBids