如何在django中将文件流式传输到客户端

我想知道如何使用django将数据流传输到客户端

目标

用户提交一个表单，表单数据被传递到一个返回字符串的web服务。字符串被涂上焦油（

tar.gz

）并将焦油球发送回用户

我不知道怎么走。我搜索并找到了，但我只有一个字符串，我不知道它是否是我想要的东西，我不知道用什么来代替

filename=\uuuuu file\uuuu

，因为我没有文件-只有一个字符串。如果我为每个用户创建一个新文件，这将不是一个好方法。所以请帮帮我。（对不起，我是网络编程新手）

编辑：

我想使用ajax，那么在ajac函数成功和视图返回时应该做些什么呢。真的谢谢

my view.py：

def idsBackup(request):
    if request.is_ajax():        
        if request.method == 'POST':
           result = ""
           form = mainForm(request.POST)
           if form.is_valid():
               form = mainForm(request.POST)
               //do form processing and call web service               

                    string_to_return = webserviceString._result 
                    ???
           to_json = {}
           to_json['form'] = render_to_string('main.html', {'form': form}, context_instance=RequestContext(request))
           to_json['result'] = result
           ???return HttpResponse(json.dumps(to_json), mimetype='application/json')
        else:
            form = mainForm()
        return render_to_response('main.html', RequestContext(request, {'form':form}))
    else:
        return render_to_response("ajax.html", {}, context_instance=RequestContext(request))

---

您可以使用字符串内容而不是实际文件创建django文件实例，然后将其作为响应发送

示例代码：

from django.core.files.base import ContentFile
def your_view(request):
    #your view code
    string_to_return = get_the_string() # get the string you want to return.
    file_to_send = ContentFile(string_to_return)
    response     = HttpResponse(file_to_send,'application/x-gzip')
    response['Content-Length']      = file_to_send.size    
    response['Content-Disposition'] = 'attachment; filename="somefile.tar.gz"'
    return response   

---

您可以修改代码段中的send_zipfile以满足您的需要。只需使用StringIO将字符串转换为类似文件的对象，该对象可以传递给FileWrapper

import StringIO, tempfile, zipfile
...
# get your string from the webservice
string = webservice.get_response() 
...
temp = tempfile.TemporaryFile()

# this creates a zip, not a tarball
archive = zipfile.ZipFile(temp, 'w', zipfile.ZIP_DEFLATED)

# this converts your string into a filelike object
fstring = StringIO.StringIO(string)   

# writes the "file" to the zip archive
archive.write(fstring)
archive.close()

wrapper = FileWrapper(temp)
response = HttpResponse(wrapper, content_type='application/zip')
response['Content-Disposition'] = 'attachment; filename=test.zip'
response['Content-Length'] = temp.tell()
temp.seek(0)
return response

---

从web服务返回的字符串是否已经是tar.gz文件？或者你想把字符串涂上焦油并发送结果吗？不，不是。我收到字符串并将其编码到base64，然后我想对其进行tarball并发送结果。显然，啊哈，它似乎不适用于ajax，我需要这样做。我不知道如何欣赏你。如果我找不到解决方案，也许我会创建一个新帖子，如果你知道该怎么做，我会很高兴你的帮助：）

import StringIO, tempfile, zipfile
...
# get your string from the webservice
string = webservice.get_response() 
...
temp = tempfile.TemporaryFile()

# this creates a zip, not a tarball
archive = zipfile.ZipFile(temp, 'w', zipfile.ZIP_DEFLATED)

# this converts your string into a filelike object
fstring = StringIO.StringIO(string)   

# writes the "file" to the zip archive
archive.write(fstring)
archive.close()

wrapper = FileWrapper(temp)
response = HttpResponse(wrapper, content_type='application/zip')
response['Content-Disposition'] = 'attachment; filename=test.zip'
response['Content-Length'] = temp.tell()
temp.seek(0)
return response