Can';t使用Pulumi创建dockerfile
我正试图和Pulumi建立一个docker文件。我有下面的Pulumi代码Can';t使用Pulumi创建dockerfile,docker,go,dockerfile,pulumi,Docker,Go,Dockerfile,Pulumi,我正试图和Pulumi建立一个docker文件。我有下面的Pulumi代码 func main(){ pulumi.Run(func(ctx*pulumi.Context)错误{ imageName:=“服务器” _,err=docker.NewImage(ctx、imageName和docker.ImageArgs{ 图像名称:pulumi.Sprintf(“gcr.io/gadic-310112/%s:latest”,图像名称), 斯基普什:普卢米。布尔(真), 生成:&docker.Doc
func main(){
pulumi.Run(func(ctx*pulumi.Context)错误{
imageName:=“服务器”
_,err=docker.NewImage(ctx、imageName和docker.ImageArgs{
图像名称:pulumi.Sprintf(“gcr.io/gadic-310112/%s:latest”,图像名称),
斯基普什:普卢米。布尔(真),
生成:&docker.DockerBuildArgs{
Dockerfile:pulumi.String(“Dockerfile”),
},
})
如果错误!=零{
返回错误
}
}
}
但是,当我运行pulumi preview
时,出现以下错误:
Diagnostics:
pulumi:pulumi:Stack (server-prod):
error: program failed: docker build -f Dockerfile . -t gcr.io/gadic-310112/server:latest failed with error: exit status 1
exit status 1
error: an unhandled error occurred: program exited with non-zero exit code: 1
docker:image:Image (server):
error: #1 [internal] load build definition from Dockerfile
#1 sha256:921a08a3c227abd8c3811effc689fa5319db237c32a4adf2b255007a51af9ef8
#1 transferring dockerfile: 2B 0.0s done
#1 DONE 0.0s
failed to solve with frontend dockerfile.v0: failed to read dockerfile: open /var/lib/docker/tmp/buildkit-mount052159980/Dockerfile: no such file or directory
有趣的是,Pulumi似乎正在运行docker build-f Dockerfile.-t gcr.io/gadic-310112/server:latest
。当我从终端运行时,它成功了,没有任何错误
❯❯❯ docker build -f Dockerfile . -t gcr.io/gadic-310112/server:latest
[+] Building 11.3s (16/18)
=> [internal] load build definition from Dockerfile 0.0s
=> => transferring dockerfile: 1.87kB 0.0s
=> [internal] load .dockerignore 0.0s
=> => transferring context: 34B 0.0s
....
看起来Pulumi使用的工作目录可能与调用它的位置不同。这可能吗?可能还有其他原因吗
我注意到,如果我没有在DockerBuildArgs
中包含Dockerfile
,那么pulumi生成的命令是docker build-f.-t gcr.io/gadic-310112/server:latest
,这肯定是错误的。如果我在本地执行该命令,我会得到以下结果:
❮❮❮ docker build -f . -t gcr.io/gadic-310112/server:latest
"docker build" requires exactly 1 argument.
See 'docker build --help'.
Usage: docker build [OPTIONS] PATH | URL | -
Build an image from a Dockerfile
编辑:我还尝试将包含Dockerfile的文件夹的绝对路径作为BuildArgs的Context
传递
Build:&docker.DockerBuildArgs{
Dockerfile:pulumi.String(“Dockerfile”),
上下文:pulumi.String(“/Users/paymahn/gadic/server”),
},
尽管底层的docker build
命令有一个绝对路径,但仍然会得到与以前相同的错误:
Diagnostics:
docker:image:Image (server):
error: #1 [internal] load build definition from Dockerfile
#1 sha256:16f11ab26c775f06385c0fde07864ed70b428d13662aa2be42823751fb5143f4
#1 transferring dockerfile: 2B 0.0s done
#1 DONE 0.1s
failed to solve with frontend dockerfile.v0: failed to read dockerfile: open /var/lib/docker/tmp/buildkit-mount684750851/Dockerfile: no such file or directory
pulumi:pulumi:Stack (server-prod):
error: program failed: docker build -f Dockerfile /Users/paymahn/gadic/server -t gcr.io/gadic-310112/server:latest failed with error: exit status 1
exit status 1
error: an unhandled error occurred: program exited with non-zero exit code: 1
编辑2:这是我的文件布局
/Users/paymahn/gadic/server/
infra/
main.go # this is the go program that pulumi runs
src/ # this is where the source code for my server lives
Dockerfile
Pulumi.yaml
Pulumi.prod.yaml # the pulumi stack config
go.sum
go.mod
.git/ # this is the root of my git repository
Pulumi项目构建在infra
目录中,而不是Pulumi.yaml
所在的文件夹中
Pulumi提供程序需要使用docker构建上下文知道Dockerfile
的路径(关于这些的更多信息)
添加上下文可以解决以下问题:
func main() {
pulumi.Run(func(ctx *pulumi.Context) error {
imageName := "server"
_, err = docker.NewImage(ctx, imageName, &docker.ImageArgs{
ImageName: pulumi.Sprintf("gcr.io/gadic-310112/%s:latest", imageName),
SkipPush: pulumi.Bool(true),
Build: &docker.DockerBuildArgs{
Dockerfile: pulumi.String("Dockerfile"),
Context: "../", # note I'm adding the context here
},
})
if err != nil {
return err
}
}
}
你也可以分享你的目录布局,比如你的Dockerfile在哪里,你的文件在哪里。总之,我现在就把它作为编辑添加。编辑:doneAh,这很有意义,谢谢!你有没有直觉来解释为什么将上下文设置为包含我的Dockerfile的文件夹的绝对路径不起作用?