Doctrine 计算原则中的外键数

以下是这个问题的后续行动：

我使用的是原则1.2，我想计算属于子类别的业务数量

以下是mysql表

1.

fi\u类别

+----+-----------------+-----------------+
| id | name            | slug            |
+----+-----------------+-----------------+

+----+-----------------+-----------------+-------------+
| id | name            | slug            | category_id |
+----+-----------------+-----------------+-------------+

+----+-------------+----------------+
| id | business_id | subcategory_id |
+----+-------------+----------------+

2.

fi_子类别

+----+-----------------+-----------------+
| id | name            | slug            |
+----+-----------------+-----------------+

+----+-----------------+-----------------+-------------+
| id | name            | slug            | category_id |
+----+-----------------+-----------------+-------------+

+----+-------------+----------------+
| id | business_id | subcategory_id |
+----+-------------+----------------+

3.

fi\u business\u子类别

+----+-----------------+-----------------+
| id | name            | slug            |
+----+-----------------+-----------------+

+----+-----------------+-----------------+-------------+
| id | name            | slug            | category_id |
+----+-----------------+-----------------+-------------+

+----+-------------+----------------+
| id | business_id | subcategory_id |
+----+-------------+----------------+

我正在使用这个DQL

$q = Doctrine_Query::create()
    ->select('c.name, c.slug, sc.name, sc.slug')
    ->from('Model_Category c')
    ->leftJoin('c.Subcategory sc')
    ->leftJoin('sc.BusinessSubcategory bsc');

这给了我类似的东西

Array
(
    [0] => Array
    (
        [id] => 1
        [name] => Entertainment & Lifestyle
        [slug] => entertainment-lifestyle
        [Subcategory] => Array
        (
            [0] => Array
            (
                [id] => 1
                [name] => Arts and Crafts
                [slug] => arts-and-crafts
            )
            [1] => Array
            (
                [id] => 2
                [name] => Family
                [slug] => family
            )
            [2] => Array
            (
                [id] => 3
                [name] => Fashion
                [slug] => fashion
            )
        )
    )
)

我希望获取业务的数量，即返回的结果应该是这样的，这取决于它所属的业务

Array
(
    [0] => Array
    (
        [id] => 1
        [name] => Entertainment & Lifestyle
        [slug] => entertainment-lifestyle
        [Subcategory] => Array
        (
            [0] => Array
            (
                [id] => 1
                [name] => Arts and Crafts
                [slug] => arts-and-crafts
                [business_count] => 35
            )
            [1] => Array
            (
                [id] => 2
                [name] => Family
                [slug] => family
                [business_count] => 10
            )
            [2] => Array
            (
                [id] => 3
                [name] => Fashion
                [slug] => fashion
                [business_count] => 27
            )
        )
    )
)

尝试了使用DQL的各种方法，但似乎没有任何效果。你知道我该如何满足自己的需求吗？

你试过：

$q = Doctrine_Query::create()
     ->select('c.name, c.slug, sc.name, sc.slug, COUNT(sc.BusinessSubcategory.id) AS business_count')
     ->from('Model_Category c')
     ->leftJoin('c.Subcategory sc')
     ->groupBy('c.id, sc.id');

使用水合物阵列

您是否尝试过：

$q = Doctrine_Query::create()
     ->select('c.name, c.slug, sc.name, sc.slug, COUNT(sc.BusinessSubcategory.id) AS business_count')
     ->from('Model_Category c')
     ->leftJoin('c.Subcategory sc')
     ->groupBy('c.id, sc.id');

---

使用

hydrome\u ARRAY

这很有效，非常感谢您，不知道DQL允许您执行此类查询。：）这是可行的，非常感谢，从来都不知道DQL允许您执行此类查询。：）