Warning: file_get_contents(/data/phpspider/zhask/data//catemap/2/facebook/8.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181

Warning: file_get_contents(/data/phpspider/zhask/data//catemap/4/sql-server-2008/3.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Facebook 将访问令牌添加到FB.Data.query()调用_Facebook_Facebook Fql - Fatal编程技术网

Facebook 将访问令牌添加到FB.Data.query()调用

Facebook 将访问令牌添加到FB.Data.query()调用,facebook,facebook-fql,Facebook,Facebook Fql,只要不需要访问代码,我就可以毫无问题地运行一些FQL语句 var query = FB.Data.query('SELECT eid, uid FROM event_member WHERE uid = 104821622923594'); 我想运行以下FQL,但根据文档,它至少需要一个通用访问代码 var query = FB.Data.query('SELECT eid, uid FROM event_member WHERE uid = 104821622923594'); 我能够使用

只要不需要访问代码,我就可以毫无问题地运行一些FQL语句

var query = FB.Data.query('SELECT eid, uid FROM event_member WHERE uid = 104821622923594');
我想运行以下FQL,但根据文档,它至少需要一个通用访问代码

var query = FB.Data.query('SELECT eid, uid FROM event_member WHERE uid = 104821622923594');
我能够使用php成功创建访问令牌,并通过在浏览器中导航到该页面来访问该页面:

https://graph.facebook.com/104821622923594/events?access_token=ACCESS_TOKEN
我希望实际使用Javascript SDK,那么如何将生成的访问令牌添加到此FB.Data.query请求中?

改用FB.api:

FB.api(
{
    method: 'fql.query',
    query: 'SELECT name FROM user WHERE uid=me()',
    access_token: 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx',
},
function(response) {
    alert('Your name is ' + response[0].name);
}
);
详情: