File 使用awk（或grep）统计文件中不同数字的出现次数

我有一个文件，在每一行中包含不同的值，我想计算出现在特定关键字之后的数字。比如,

  "fields" : {
    "referer" : [ "-" ],
    "@timestamp" : [ "2017-01-08T19:50:19.000Z" ],
    "uri_path" : [ "test" ],
    "method" : [ "GET" ],
    "servername" : [ "INMESPWEB03" ],
    "useragent" : [ "Mediapartners-Google" ],
    "querystring" : [ "test" ],
    "bytes-sent" : [ "227905" ],
    "cshost" : [ "www.test.com" ],
    "scstatus" : [ "200" ],
    "time-taken" : [ "15468" ]
  }
  "fields" : {
    "referer" : [ "-" ],
    "@timestamp" : [ "2017-01-08T19:50:19.000Z" ],
    "uri_path" : [ "test" ],
    "method" : [ "GET" ],
    "servername" : [ "INMESPWEB03" ],
    "useragent" : [ "Mediapartners-Google" ],
    "querystring" : [ "test" ],
    "bytes-sent" : [ "227905" ],
    "cshost" : [ "www.test.com" ],
    "scstatus" : [ "300" ],
    "time-taken" : [ "15468" ]
  }
  "fields" : {
    "referer" : [ "-" ],
    "@timestamp" : [ "2017-01-08T19:50:19.000Z" ],
    "uri_path" : [ "test" ],
    "method" : [ "GET" ],
    "servername" : [ "INMESPWEB03" ],
    "useragent" : [ "Mediapartners-Google" ],
    "querystring" : [ "test" ],
    "bytes-sent" : [ "227905" ],
    "cshost" : [ "www.test.com" ],
    "scstatus" : [ "200" ],
    "time-taken" : [ "15468" ]
  }

所以结果应该是这样的

• 200:2
• 300:1
• …：

事情是这样的

我想检查“scstatus”之后的每个数字，然后计数并按升序或降序打印。这是我到目前为止写的代码，这个脚本提供了上面的数据

curl -XPOST 'webpage.name.abc' -d { "query": { "filtered": { "query": { "query_string": {
     "analyze_wildcard": true,
     "query": "useragent: \"googlebot\"|\"mediapartners-google\"|\"adsbot-google\""}
 }}},"size": 4000000, "fields": ["@timestamp","servername","uri_path","scstatus","method","cshost","useragent","time-taken","referer","bytes-sent","querystring"]} 

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如果您的文件格式是固定的，此awk one liner可能会有帮助：

awk -F'"' '$2=="scstatus"{a[$4]++}END{for(x in a)print x,a[x]}' file
200 2
300 1

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“我想要X”不是一个问题，更不用说编程问题了。你想雇一个程序员吗？不，很抱歉解释错了，对我来说，用c#或java很容易，但我需要创建一个脚本，生成一个包含这些信息的文件，计算数字的出现次数并通过邮件发送，所有这些都在unix服务器上运行的脚本中。这仍然是“我需要X”，不是问题，更不用说编程问题了。@iondevx，单击问题下的“编辑”链接，然后添加到目前为止您编写的需要帮助的代码。@ghoti我添加了我编写的代码谢谢@Kent提供解决方案！