Flask 运行直接使用shell python中的uwsgidecorators的uWSGI应用程序
您可能知道,uwsgidecorators仅在您的应用程序在uwsgi上下文中运行时才起作用,这在文档中并不清楚: 我的代码使用这些装饰器,例如用于锁定:Flask 运行直接使用shell python中的uwsgidecorators的uWSGI应用程序,flask,uwsgi,pythoninterpreter,Flask,Uwsgi,Pythoninterpreter,您可能知道,uwsgidecorators仅在您的应用程序在uwsgi上下文中运行时才起作用,这在文档中并不清楚: 我的代码使用这些装饰器,例如用于锁定: @uwsgidecorators.lock def critical_func(): ... 当我使用uwsgi部署我的应用程序时,这很好,但是,当直接从Python shell启动它时,我得到了一个预期的错误: File ".../venv/lib/python3.6/site-packages/uwsgidecorators.py"
@uwsgidecorators.lock
def critical_func():
...
当我使用uwsgi部署我的应用程序时,这很好,但是,当直接从Python shell启动它时,我得到了一个预期的错误:
File ".../venv/lib/python3.6/site-packages/uwsgidecorators.py", line 10, in <module>
import uwsgi
ModuleNotFoundError: No module named 'uwsgi'
是否有任何已知的解决方案可以在两种模式下运行我的应用程序?显然,在使用简单解释器时,我不需要同步和其他功能来工作,但除了导入之外,做一些尝试似乎真的是很糟糕的编码。在此期间,我做了以下实现,我很高兴知道有更简单的东西:
class _dummy_lock():
"""Implement the uwsgi lock decorator without actually doing any locking"""
def __init__(self, f):
self.f = f
def __call__(self, *args, **kwargs):
return self.f(*args, **kwargs)
class uwsgi_lock():
"""
This is a lock decorator that wraps the uwsgi decorator to allow it to work outside of a uwsgi environment as well.
ONLY STATIC METHODS can be locked using this functionality
"""
def __init__(self, f):
try:
import uwsgidecorators
self.lock = uwsgidecorators.lock(f) # the real uwsgi lock class
except ModuleNotFoundError:
self.lock = _dummy_lock(f)
def __call__(self, *args, **kwargs):
return self.lock(*args, **kwargs)
@staticmethod
@uwsgi_lock
def critical_func():
...