Flutter Dart-如何在外部应用程序中打开文件

我试图让一个应用程序能够在另一个外部应用程序中打开某个文件。例如，如果用户试图打开“我的应用程序”中列出的.pdf文件，他们将被重定向到设备上安装的应用程序。我怎样才能做到这一点？是否有一个库赋予我这种能力，或者这是我必须自己解决的问题？

您可以使用这个包 并指定路径

OpenFile.open("/sdcard/example.pdf");

支持的路径

{
            {".3gp",    "video/3gpp"},
            {".apk",    "application/vnd.android.package-archive"},
            {".asf",    "video/x-ms-asf"},
            {".avi",    "video/x-msvideo"},
            {".bin",    "application/octet-stream"},
            {".bmp",    "image/bmp"},
            {".c",      "text/plain"},
            {".class",  "application/octet-stream"},
            {".conf",   "text/plain"},
            {".cpp",    "text/plain"},
            {".doc",    "application/msword"},
            {".docx",   "application/vnd.openxmlformats-officedocument.wordprocessingml.document"},
            {".xls",    "application/vnd.ms-excel"},
            {".xlsx",   "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet"},
            {".exe",    "application/octet-stream"},
            {".gif",    "image/gif"},
            {".gtar",   "application/x-gtar"},
            {".gz",     "application/x-gzip"},
            {".h",      "text/plain"},
            {".htm",    "text/html"},
            {".html",   "text/html"},
            {".jar",    "application/java-archive"},
            {".java",   "text/plain"},
            {".jpeg",   "image/jpeg"},
            {".jpg",    "image/jpeg"},
            {".js",     "application/x-javascript"},
            {".log",    "text/plain"},
            {".m3u",    "audio/x-mpegurl"},
            {".m4a",    "audio/mp4a-latm"},
            {".m4b",    "audio/mp4a-latm"},
            {".m4p",    "audio/mp4a-latm"},
            {".m4u",    "video/vnd.mpegurl"},
            {".m4v",    "video/x-m4v"},
            {".mov",    "video/quicktime"},
            {".mp2",    "audio/x-mpeg"},
            {".mp3",    "audio/x-mpeg"},
            {".mp4",    "video/mp4"},
            {".mpc",    "application/vnd.mpohun.certificate"},
            {".mpe",    "video/mpeg"},
            {".mpeg",   "video/mpeg"},
            {".mpg",    "video/mpeg"},
            {".mpg4",   "video/mp4"},
            {".mpga",   "audio/mpeg"},
            {".msg",    "application/vnd.ms-outlook"},
            {".ogg",    "audio/ogg"},
            {".pdf",    "application/pdf"},
            {".png",    "image/png"},
            {".pps",    "application/vnd.ms-powerpoint"},
            {".ppt",    "application/vnd.ms-powerpoint"},
            {".pptx",   "application/vnd.openxmlformats-officedocument.presentationml.presentation"},
            {".prop",   "text/plain"},
            {".rc",     "text/plain"},
            {".rmvb",   "audio/x-pn-realaudio"},
            {".rtf",    "application/rtf"},
            {".sh",     "text/plain"},
            {".tar",    "application/x-tar"},
            {".tgz",    "application/x-compressed"},
            {".txt",    "text/plain"},
            {".wav",    "audio/x-wav"},
            {".wma",    "audio/x-ms-wma"},
            {".wmv",    "audio/x-ms-wmv"},
            {".wps",    "application/vnd.ms-works"},
            {".xml",    "text/plain"},
            {".z",      "application/x-compress"},
            {".zip",    "application/x-zip-compressed"},
            {"",        "*/*"}
}

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这不是一个重复的问题，而是一个与

引用以下的答案：

打开文件插件对我不起作用。而这正是安卓意欲拯救的地方。在我的例子中，模因类型是视频。这就是为什么下面的代码片段似乎是有效的

String path = "your_local_file_path";

final AndroidIntent intent = AndroidIntent(
        action: 'action_view',
        data: Uri.encodeFull(path),
        type: "video/*");
intent.launch();