Flutter 如何用颤振检查输入的电话号码是否有效？

我正在检查输入的电话号码是否有效。 意思是，如果我输入了世界上不存在的错误号码，那么它会向我显示一个祝酒词，内容是“请输入一个有效的号码”

请检查这张单据

代码段TextFormField验证程序

Widget FormUI() {
    return new Column(
      children: <Widget>[
        new TextFormField(
          decoration: const InputDecoration(labelText: 'Name'),
          keyboardType: TextInputType.text,
          validator: validateName,
          onSaved: (String val) {
            _name = val;
          },
        ),
        new TextFormField(
          decoration: const InputDecoration(labelText: 'Mobile'),
          keyboardType: TextInputType.phone,
          validator: validateMobile,
          onSaved: (String val) {
            _mobile = val;
          },
        ),
        new TextFormField(
          decoration: const InputDecoration(labelText: 'Email'),
          keyboardType: TextInputType.emailAddress,
          validator: validateEmail,
          onSaved: (String val) {
            _email = val;
          },
        ),
        new SizedBox(
          height: 10.0,
        ),
        new RaisedButton(
          onPressed: _validateInputs,
          child: new Text('Validate'),
        )
      ],
    );
  }

  String validateName(String value) {
    if (value.length < 3)
      return 'Name must be more than 2 charater';
    else
      return null;
  }

  String validateMobile(String value) {
// Indian Mobile number are of 10 digit only
    if (value.length != 10)
      return 'Mobile Number must be of 10 digit';
    else
      return null;
  }

  String validateEmail(String value) {
    Pattern pattern =
        r'^(([^<>()[\]\\.,;:\s@\"]+(\.[^<>()[\]\\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$';
    RegExp regex = new RegExp(pattern);
    if (!regex.hasMatch(value))
      return 'Enter Valid Email';
    else
      return null;
  }

FormBuilderTextField(
            attribute: "age",
            decoration: InputDecoration(labelText: "Age"),
            validators: [
              FormBuilderValidators.numeric(),
              FormBuilderValidators.max(70),
            ],
          ),

FormBuilderTextField(
attribute: "over_18",
decoration: InputDecoration(labelText: "Are you over 18?"),
validators: [
    FormBuilderValidators.required(),
    (val){
        if(val.toLowerCase() != "yes")
            return "The answer must be Yes";
    },
],
),

带包装 支持内置和自定义验证程序

Widget FormUI() {
    return new Column(
      children: <Widget>[
        new TextFormField(
          decoration: const InputDecoration(labelText: 'Name'),
          keyboardType: TextInputType.text,
          validator: validateName,
          onSaved: (String val) {
            _name = val;
          },
        ),
        new TextFormField(
          decoration: const InputDecoration(labelText: 'Mobile'),
          keyboardType: TextInputType.phone,
          validator: validateMobile,
          onSaved: (String val) {
            _mobile = val;
          },
        ),
        new TextFormField(
          decoration: const InputDecoration(labelText: 'Email'),
          keyboardType: TextInputType.emailAddress,
          validator: validateEmail,
          onSaved: (String val) {
            _email = val;
          },
        ),
        new SizedBox(
          height: 10.0,
        ),
        new RaisedButton(
          onPressed: _validateInputs,
          child: new Text('Validate'),
        )
      ],
    );
  }

  String validateName(String value) {
    if (value.length < 3)
      return 'Name must be more than 2 charater';
    else
      return null;
  }

  String validateMobile(String value) {
// Indian Mobile number are of 10 digit only
    if (value.length != 10)
      return 'Mobile Number must be of 10 digit';
    else
      return null;
  }

  String validateEmail(String value) {
    Pattern pattern =
        r'^(([^<>()[\]\\.,;:\s@\"]+(\.[^<>()[\]\\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$';
    RegExp regex = new RegExp(pattern);
    if (!regex.hasMatch(value))
      return 'Enter Valid Email';
    else
      return null;
  }

FormBuilderTextField(
            attribute: "age",
            decoration: InputDecoration(labelText: "Age"),
            validators: [
              FormBuilderValidators.numeric(),
              FormBuilderValidators.max(70),
            ],
          ),

FormBuilderTextField(
attribute: "over_18",
decoration: InputDecoration(labelText: "Are you over 18?"),
validators: [
    FormBuilderValidators.required(),
    (val){
        if(val.toLowerCase() != "yes")
            return "The answer must be Yes";
    },
],
),

您可以将自己的电话号码验证逻辑放入验证器中，用于基于国家/地区的电话号码格式检查。

我认为， 解决方案在我的代码和 我太笨了，都认不出来了

请看代码中的注释

    final PhoneCodeAutoRetrievalTimeout autoRetrieval=(String verId){
      this.verificationId=verId;
    };

    final PhoneCodeSent smsCodeSent=(String verId, [int forceCodeResend]){
      this.verificationId=verId;    
      smsCodeDialog(context).then((value){        
      }).catchError((onError){
         print(onError);    
      });
    };


//This will verified you number

    final PhoneVerificationCompleted verificationCompleted = (AuthCredential credential) {
     print("verified");
    };

// and if your number doesn't exist or doesn't match with your country code,Then this will show you an error message

    final PhoneVerificationFailed verfifailed=(AuthException exception){
      print("${exception.message}");
       Fluttertoast.showToast(msg: "The number is invalid", backgroundColor: Colors.red); 
       //Fluttertoast.showToast(msg: "${exception.message}"); //
    };

    if(phoneNo !=null){
      await firebaseAuth.verifyPhoneNumber(
        phoneNumber: this.phoneNo,
        codeAutoRetrievalTimeout: autoRetrieval,
        codeSent: smsCodeSent,
        timeout: const Duration(seconds: 10),
        verificationCompleted: verificationCompleted,
        verificationFailed: verfifailed
      );
    } 
  }

---

你们试过了吗？是的，但我不需要验证器，因为我已经验证过了。只想检查输入的电话号码是否存在？@ShrutiRamnandanSharma您需要拨打该号码我想您应该解释一下什么是“有效号码”？在前端，我们使用正则表达式作为Samcom的答案。在后端，我们不知道存在或不存在哪个号码，但请调用api，或者如果您是ISP，您可以知道世界上是否存在该号码。@ShrutiRamnandanSharma找到任何解决方案了吗？谢谢，但此解决方案无法解决我的问题。请你重新阅读我的帖子好吗？在写作时不支持Dart

    final PhoneCodeAutoRetrievalTimeout autoRetrieval=(String verId){
      this.verificationId=verId;
    };

    final PhoneCodeSent smsCodeSent=(String verId, [int forceCodeResend]){
      this.verificationId=verId;    
      smsCodeDialog(context).then((value){        
      }).catchError((onError){
         print(onError);    
      });
    };


//This will verified you number

    final PhoneVerificationCompleted verificationCompleted = (AuthCredential credential) {
     print("verified");
    };

// and if your number doesn't exist or doesn't match with your country code,Then this will show you an error message

    final PhoneVerificationFailed verfifailed=(AuthException exception){
      print("${exception.message}");
       Fluttertoast.showToast(msg: "The number is invalid", backgroundColor: Colors.red); 
       //Fluttertoast.showToast(msg: "${exception.message}"); //
    };

    if(phoneNo !=null){
      await firebaseAuth.verifyPhoneNumber(
        phoneNumber: this.phoneNo,
        codeAutoRetrievalTimeout: autoRetrieval,
        codeSent: smsCodeSent,
        timeout: const Duration(seconds: 10),
        verificationCompleted: verificationCompleted,
        verificationFailed: verfifailed
      );
    } 
  }