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Flutter 颤振:迭代列表时对null调用了方法“[]”_Flutter - Fatal编程技术网

Flutter 颤振:迭代列表时对null调用了方法“[]”

Flutter 颤振:迭代列表时对null调用了方法“[]”,flutter,Flutter,这是我到现在为止的源代码。你能告诉我出了什么问题,为什么我会犯这个错误吗 任何帮助都将不胜感激。谢谢 错误是: 数据[0]中出现错误,显示颤振:迭代列表导入“package:flatter/material.dart”时调用了null方法“[]” class MyGetHttpDataState extends State<MyGetHttpData> { final String url = "*******"; List data, a; int index;

这是我到现在为止的源代码。你能告诉我出了什么问题,为什么我会犯这个错误吗

任何帮助都将不胜感激。谢谢

错误是:


数据[0]中出现错误,显示颤振:迭代列表导入“package:flatter/material.dart”时调用了null方法“[]”

class MyGetHttpDataState extends State<MyGetHttpData> { 

    final String url = "*******";
    List data, a; int index; // Function to get the JSON data 

    Future<String> getJSONData() async {
        var response = await http.get(url);
        print(response.body);
        setState(() {
           json.decode(response.body);
           data = dataConvertedToJSON['data']; index = 0;
        });
        return "Successfull";
    }

    @override
    Widget build(BuildContext context) {
        return new MaterialApp( 
          home: new Scaffold( 
            appBar: new AppBar( title: new Text('List Test'), ), 
            body: new Center( 
              child: Column( 
                mainAxisAlignment: MainAxisAlignment.center, 
                children: <Widget>[
                  for (var name in data[0]['INCI']) Text(name)
                ], ), ), )); 
    } 

    @override
    void initState() {
      super.initState();
      this.getJSONData(); 
    }
}

把你的代码改成这个

Future<String> getJSONData() async {
    var response = await http.get(url);
    setState(() {
       var dataConvertedToJSON = json.decode(response.body);
       data = dataConvertedToJSON['data'];
       data = data[0]['INCI'];
    });
    return "Successfull";
}

@override
Widget build(BuildContext context) {
    return new MaterialApp( 
      home: new Scaffold( 
        appBar: new AppBar( title: new Text('List Test'), ), 
        body: new Center( 
          child: data != null ? Column(
            mainAxisAlignment: MainAxisAlignment.center, 
            children: <Widget>[
              for (var name in data) Text(name)
            ], 
          ) : new CircularProgressIndicator(), 
        ), 
      )
    ); 
} 

当我运行代码时,它显示错误1秒,然后给我结果如果我不能这样做,我能做什么?显示什么错误?方法“[]”在null上被调用。如果我删除:对于数据[0]['INCI']Textname中的var name,不再出现错误,您想要什么?打印INCI或其他文件中的所有值?但当我进行另一次搜索时,没有找到任何结果,它会给出最后一个结果,我想显示“未找到”,只需更改新的CircularProgressIndicator,如果我再次干扰,则发送新文本Not Foundbro Sry,但当我使用AlertDialog时,它会在何时何地向我发送类似此黑屏的信息?我正在使用自定义对话框giffy import'package:giffy_dialog/giffy_dialog.dart';