Java8:行位置引用,当应用过滤器时,流,foreach
我不知道是否可能: 我想知道某个文件中某个单词所在的数字行Java8:行位置引用,当应用过滤器时,流,foreach,foreach,java-8,location,java-stream,lines,Foreach,Java 8,Location,Java Stream,Lines,我不知道是否可能: 我想知道某个文件中某个单词所在的数字行 try { CharsetDecoder dec = StandardCharsets.UTF_8.newDecoder() .onMalformedInput(CodingErrorAction.IGNORE); try (Reader r = Channels.newReader(FileChannel.open("path"), dec, -1); Buffer
try {
CharsetDecoder dec = StandardCharsets.UTF_8.newDecoder()
.onMalformedInput(CodingErrorAction.IGNORE);
try (Reader r = Channels.newReader(FileChannel.open("path"), dec, -1);
BufferedReader br = new BufferedReader(r)) {
br.lines().filter(line -> line.contains("SomeWord"))
.forEach(line -> System.out.println("location:" + line.????)); //Location where line has the "SomeWord"
}
} catch (IOException |java.io.UncheckedIOException ex) {
Logger.getLogger(RecursiveFolderAndFiles.class.getName())
.log(Level.SEVERE, null, ex);
}
如何执行此操作?您可以在
br.lines()
上收集到一个列表,然后利用IntStream.range
进行如下操作:
...
...
List<String> resultSet = br.lines().collect(Collectors.toList());
IntStream.range(0, resultSet.size())
.filter(index -> resultSet.get(index).contains("SomeWord"))
.forEach(index -> System.out.println("location:" + index));
...
...
。。。
...
List resultSet=br.lines().collect(Collectors.toList());
IntStream.range(0,resultSet.size())
.filter(index->resultSet.get(index).contains(“SomeWord”))
.forEach(index->System.out.println(“位置:+index”);
...
...
现在,您应该可以同时访问索引和行。您不一定需要流来处理这个或java-8。。。有一个
LineNumberReader
扩展了BufferedReader
,因此您可以执行以下操作:
LineNumberReader lnr = new LineNumberReader(r)) {
String line;
while ((line = lnr.readLine()) != null) {
if(line.contains("SomeWord")) {
System.out.println("location:" + lnr.getLineNumber())
}
}