什么';在golang中声明一个空map[string]接口{}的内存成本/开销是多少?
只是为了好奇,从 所以它至少是:5个字+8个字节 但是为什么会这样呢-什么';在golang中声明一个空map[string]接口{}的内存成本/开销是多少?,go,data-structures,hashtable,Go,Data Structures,Hashtable,只是为了好奇,从 所以它至少是:5个字+8个字节 但是为什么会这样呢- 为什么会这样 Go堆栈分配在堆上分配零字节 mp := map[byte]byte{} main map[byte]byte literal does not escape 很好,我也找到了第一个问题的答案:(每个地图大约170字节) package main import ( "fmt" "runtime" ) func main() { var m1, m2 runtime.MemSt
为什么会这样 Go堆栈分配在堆上分配零字节
mp := map[byte]byte{}
main map[byte]byte literal does not escape
很好,我也找到了第一个问题的答案:(每个地图大约170字节)
package main
import (
"fmt"
"runtime"
)
func main() {
var m1, m2 runtime.MemStats
var i byte
runtime.ReadMemStats(&m1)
mp := map[byte]byte{}
runtime.ReadMemStats(&m2)
fmt.Println("Bytes allocated on creation:", m2.Alloc-m1.Alloc)
for i = 0; i < 100; i++ {
runtime.ReadMemStats(&m1)
mp[i] = i
runtime.ReadMemStats(&m2)
fmt.Printf("Bytes allocated on assignment %d: %d\n", i, m2.Alloc-m1.Alloc)
}
}
Bytes allocated on creation: 0
mp := map[byte]byte{}
main map[byte]byte literal does not escape
package main
import (
"fmt"
"runtime"
)
func main() {
var m1, m2 runtime.MemStats
var i byte
runtime.ReadMemStats(&m1)
mp := map[byte]byte{}
runtime.ReadMemStats(&m2)
fmt.Println("Bytes allocated on creation:", m2.Alloc-m1.Alloc)
for i = 0; i < 100; i++ {
runtime.ReadMemStats(&m1)
mp[i] = i
runtime.ReadMemStats(&m2)
fmt.Printf("Bytes allocated on assignment %d: %d\n", i, m2.Alloc-m1.Alloc)
}
}
Bytes allocated on creation: 0