Go 如何用单引号转义字符串

我试图在Go中取消引用使用单引号的字符串（语法与Go字符串文字语法相同，但使用单引号而不是双引号）：

应该成为

'"Hello,
world!
@CeriseLimón came up with this answer, and I just put it into a function with more shenanigans to support 
\n
s. First, this swaps 
'
 and 
"
, and changes 
\n
s to actual newlines. Then it 
strconv.Unquote
s each line, since 
strconv.Unquote
 cannot handle newlines, and then reswaps 
'
 and 
"
 and pieces them together.

func unquote(s string) string {
        replaced := strings.NewReplacer(
            `'`,
            `"`,
            `"`,
            `'`,
            `\n`,
            "\n",
        ).Replace(s[1:len(s)-1])
        unquoted := ""
        for _, line := range strings.Split(replaced, "\n") {
            tmp, err := strconv.Unquote(`"` + line + `"`)
            repr.Println(line, tmp, err)
            if err != nil {
                return nil, NewInvalidAST(obj.In.Text.LexerInfo, "*Obj.In.Text.Text")
            }
            unquoted += tmp + "\n"
        }
        return strings.NewReplacer(
            `"`,
            `'`,
            `'`,
            `"`,
        ).Replace(unquoted[:len(unquoted)-1])
}

“你好，
世界！
@CeriseLimón提出了这个答案，我只是把它放在一个有更多诡计的函数中，以支持
\n
s。首先，这个函数交换
'
和
“
，并将
\n
s更改为实际的换行符。然后，它将
strconv.Unquote
s每一行，因为
strconv.Unquote
无法处理换行符，然后将
“
和
”
重新交换并将它们分割在一起

我不熟悉Go，但是你能用JSON解析器反序列化它吗？谢谢，@Matthew！它有效：Go或JSON中不使用单引号作为字符串分隔符。编辑问题以说明使用的语法。是来自Javascript、Vimscript吗？问题中的示例使用单引号。你链接的文章使用反引号。哪一个是字符串不是一段符文。如果语法是Go语法，用
“
替换为
”
，则使用
strconv.Unquote（strings.ReplaceAll（s，“”，“\”）
。此外，编辑问题以说明语法。字符串是字节序列，而不是字节片段。
'"Hello,
world!
@CeriseLimón came up with this answer, and I just put it into a function with more shenanigans to support 
\n
s. First, this swaps 
'
 and 
"
, and changes 
\n
s to actual newlines. Then it 
strconv.Unquote
s each line, since 
strconv.Unquote
 cannot handle newlines, and then reswaps 
'
 and 
"
 and pieces them together.

func unquote(s string) string {
        replaced := strings.NewReplacer(
            `'`,
            `"`,
            `"`,
            `'`,
            `\n`,
            "\n",
        ).Replace(s[1:len(s)-1])
        unquoted := ""
        for _, line := range strings.Split(replaced, "\n") {
            tmp, err := strconv.Unquote(`"` + line + `"`)
            repr.Println(line, tmp, err)
            if err != nil {
                return nil, NewInvalidAST(obj.In.Text.LexerInfo, "*Obj.In.Text.Text")
            }
            unquoted += tmp + "\n"
        }
        return strings.NewReplacer(
            `"`,
            `'`,
            `'`,
            `"`,
        ).Replace(unquoted[:len(unquoted)-1])
}