Google bigquery 在Bigquery中使用struct数组删除重复项并选择不同的值

我开始使用BigQuery。我有一个数据库，看起来像 它可以生成为

    WITH T AS (
  SELECT 0 AS id, 'red' AS colour, ARRAY<STRUCT<count INT64, shape STRING>>[(2, "dot"), (2, "dot"), (1, "string")] AS arr, DATE(2020,01,31) AS date UNION ALL
  SELECT 0 AS id, 'red' AS colour, ARRAY<STRUCT<count INT64, shape STRING>>[(2, "dot"), (2, "dot"), (1, "string")] AS arr, DATE(2020,01,31) AS date UNION ALL
  SELECT 0 AS id, 'red' AS colour, ARRAY<STRUCT<count INT64, shape STRING>>[(20, "dot"), (20, "dot"), (1, "string")] AS arr, DATE(2020,01,30) AS date UNION ALL
  SELECT 0 AS id, 'black' AS colour, ARRAY<STRUCT<count INT64, shape STRING>>[(296, "dot"), (212, "plane"), (156, "cube")] AS arr, DATE(2020,01,31) AS date UNION ALL
  SELECT 0 AS id, 'black' AS colour, ARRAY<STRUCT<count INT64, shape STRING>>[(296, "dot"), (212, "plane"), (156, "cube")] AS arr, DATE(2020,01,31) AS date UNION ALL
  SELECT 0 AS id, 'black' AS colour, ARRAY<STRUCT<count INT64, shape STRING>>[(296, "dot"), (21, "plane"), (156, "cube")] AS arr, DATE(2020,01,30) AS date UNION ALL
  SELECT 0 AS id, 'black' AS colour, ARRAY<STRUCT<count INT64, shape STRING>>[(296, "dot"), (2, "plane"), (156, "cube")] AS arr, DATE(2020,01,30) AS date UNION ALL
  SELECT 1 AS id, 'blue' AS colour, ARRAY<STRUCT<count INT64, shape STRING>>[(4, "cube"), (4, "cube"), (4, "cube")], DATE(2020, 01, 31) AS date UNION ALL
  SELECT 2 AS id, 'orange' AS colour, ARRAY<STRUCT<count INT64, shape STRING>>[(5, "string")], DATE(2020,01,31) AS date UNION ALL
  SELECT 2 AS id, 'orange' AS colour, ARRAY<STRUCT<count INT64, shape STRING>>[(5, "string")], DATE(2020,01,30) AS date
)
SELECT *
FROM T;

将副本返回给我。然后我需要为每个嵌套行指定id和颜色。如有任何建议，将不胜感激

---

谢谢

哦，我真傻，我在交叉加入！谢谢你的回答

with T AS (),
unnested_and_unique as (
  select distinct id, colour, count, shape, date
  from T left join unnest(arr) x
)
select date,array_agg(struct(count,shape,id,colour)) as res
from unnested_and_unique
group by 1

SELECT date, ARRAY_CONCAT_AGG(ARRAY((SELECT AS STRUCT MAX(count), shape FROM UNNEST(arr) GROUP BY shape)))
FROM T
GROUP BY date

with T AS (),
unnested_and_unique as (
  select distinct id, colour, count, shape, date
  from T left join unnest(arr) x
)
select date,array_agg(struct(count,shape,id,colour)) as res
from unnested_and_unique
group by 1