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Google maps 关于地址查询的谷歌地图/融合表信息窗口_Google Maps_Search_Google Fusion Tables - Fatal编程技术网

Google maps 关于地址查询的谷歌地图/融合表信息窗口

Google maps 关于地址查询的谷歌地图/融合表信息窗口,google-maps,search,google-fusion-tables,Google Maps,Search,Google Fusion Tables,我已经创建了一个融合地图,显示了一个区域的多边形区域。我想做的是让用户输入一个地址,该地址将在我的地图上显示该位置,并显示一个信息窗口,该窗口的信息与用户单击该区域时的信息相同。基本上,我想要这样的东西,但我的地图/数据 我已经找到了一些旧的代码示例,但我似乎无法使它与我创建的地图一起工作。这是我目前的代码: <!DOCTYPE html> <html> <head> <meta name="viewport"></m

我已经创建了一个融合地图,显示了一个区域的多边形区域。我想做的是让用户输入一个地址,该地址将在我的地图上显示该位置,并显示一个信息窗口,该窗口的信息与用户单击该区域时的信息相同。基本上,我想要这样的东西,但我的地图/数据

我已经找到了一些旧的代码示例,但我似乎无法使它与我创建的地图一起工作。这是我目前的代码:

<!DOCTYPE html>
    <html>
    <head>
    <meta name="viewport"></meta>
    <title>SCV Sheriff Reporting Districts - Google Fusion Tables</title>
    <style type="text/css">
    html, body, #googft-mapCanvas {
      height: 500px;
      margin: 0;
      padding: 0;
      width: 500px;
    }
    </style>

    <script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=false"></script>

    <script type="text/javascript">
      function initialize() {
        google.maps.visualRefresh = true;
        var isMobile = (navigator.userAgent.toLowerCase().indexOf('android') > -1) ||
          (navigator.userAgent.match(/(iPod|iPhone|iPad|BlackBerry|Windows Phone|iemobile)/));
        if (isMobile) {
          var viewport = document.querySelector("meta[name=viewport]");
          viewport.setAttribute('content', 'initial-scale=1.0, user-scalable=no');
        }
        var mapDiv = document.getElementById('googft-mapCanvas');
        mapDiv.style.width = isMobile ? '100%' : '500px';
        mapDiv.style.height = isMobile ? '100%' : '500px';
        var map = new google.maps.Map(mapDiv, {
          center: new google.maps.LatLng(34.41269001087864, -118.55340000000001),
          zoom: 11,
          mapTypeId: google.maps.MapTypeId.ROADMAP
        });
        map.controls[google.maps.ControlPosition.RIGHT_BOTTOM].push(document.getElementById('googft-legend-open'));
        map.controls[google.maps.ControlPosition.RIGHT_BOTTOM].push(document.getElementById('googft-legend'));

        layer = new google.maps.FusionTablesLayer({
          map: map,
          heatmap: { enabled: false },
          query: {
            select: "col2",
            from: "1uSGM1yPMJBlu74Znm4fPqdCsJjteB_kQ_nGz3tk",
            where: ""
          },
          options: {
            styleId: 2,
            templateId: 2
          }
        });

        if (isMobile) {
          var legend = document.getElementById('googft-legend');
          var legendOpenButton = document.getElementById('googft-legend-open');
          var legendCloseButton = document.getElementById('googft-legend-close');
          legend.style.display = 'none';
          legendOpenButton.style.display = 'block';
          legendCloseButton.style.display = 'block';
          legendOpenButton.onclick = function() {
            legend.style.display = 'block';
            legendOpenButton.style.display = 'none';
          }
          legendCloseButton.onclick = function() {
            legend.style.display = 'none';
            legendOpenButton.style.display = 'block';
          }
        }
      }

      google.maps.event.addDomListener(window, 'load', initialize);
    </script>
    </head>

<body>
  <div id="googft-mapCanvas"></div>
</body>
</html>

从中的代码开始

将FusionTableID更改为表的FusionTableID

var FusionTableID = '1uSGM1yPMJBlu74Znm4fPqdCsJjteB_kQ_nGz3tk';
更改表的GViz查询以使用正确的列名

var queryText ="SELECT 'name', 'Zone Area'  FROM "+FusionTableID+" WHERE ST_INTERSECTS(\'Zone Area\', CIRCLE(LATLNG(" + point.toUrlValue(6) + "),0.5));";
更改FusionTables层以使用加密ID的新语法

layer = new google.maps.FusionTablesLayer({query:{from:FusionTableID},suppressInfoWindows:true});
也可能是相关的。你试过什么?每个FusionTable贴图取决于FusionTable中的数据和所需的结果,除非您将数据以所用示例的格式放置,否则不可能找到可以剪切和粘贴的解决方案。