有没有一种方法可以；“合并”；gradle任务以避免许多dependsOn声明

假设这个gradle脚本：

task copyGroovyScript(dependsOn: prepare, type: Copy) {
    from "${scriptSrcLocation}/${scriptSrcName}"
    into buildFolderZipSource
}

task copyDependenciesForGroovyScript(dependsOn: copyGroovyScript, type: Copy) {
     from configurations.groovyScript.resolve()
     into "${buildFolderZipSource}/groovy-plugin-lib"
}

task copyTestScripts(dependsOn: copyDependenciesForGroovyScript, type: Copy ) {
    from "${scriptSrcLocation}/ReadClient.groovy"
    into "${buildFolderZipSource}/test"
}

task copyTestScriptsBin(dependsOn: copyTestScripts, type: Copy ) {
    from "${scriptSrcLocation}/bin"
    into "${buildFolderZipSource}/test/bin"
}

task copyDependenciesForTestScripts(dependsOn: copyTestScriptsBin, type: Copy) {
    from configurations.testScripts.resolve()
    into "${buildFolderZipSource}/test/lib"
}

task packageAll(dependsOn: copyDependenciesForTestScripts, type:Zip) {
    archiveName "output-${buildTime()}.zip"
    excludes ['*.zip']
    destinationDir buildFolder
    from buildFolder
}

我需要不同的

复制

任务，然后它们才会有不同的输出文件夹

---

有没有办法避免所有那些

dependsOn

语句，让gradle以某种方式按照文件中声明的顺序执行事情？

没有办法按照声明的方式执行。但你为什么不走这条路：

task packageAll(dependsOn: copyDependenciesForTestScripts, type:Zip) {
    doFirst {
       copy {
          from "${scriptSrcLocation}/${scriptSrcName}"
          into buildFolderZipSource
       }
    }
    //following doFirst and so on..
    archiveName "output-${buildTime()}.zip"
    excludes ['*.zip']
    destinationDir buildFolder
    from buildFolder
}

编辑

在评论中讨论之后，结果是下面的代码应该可以完成这项工作

task prepare {
   doFirst {
       copy {
          from "${scriptSrcLocation}/${scriptSrcName}"
          into buildFolderZipSource
       }
    }
    //following doFirst and so on..
}

task packageAll(dependsOn: prepare, type:Zip) {
    archiveName "output-${buildTime()}.zip"
    excludes ['*.zip']
    destinationDir buildFolder
    from buildFolder
}

---

或者，类似于

[taskA，taskB，taskC]*。每个{/*共享任务配置*/}

都可以让他做更多的自定义行为。谢谢你，看起来已经更好了。如果您可以执行：

doAllFirst

，您将传递一个任务列表，以避免每次重复

doFirst

。您可以配置单个

doFirst

。我怀疑您是否需要这么多独立的任务。如果按照声明任务的顺序执行脚本，它将变成简单的shell脚本：/n刚刚测试过，但似乎不起作用。我得到“跳过任务”：packageAll，因为它没有源文件