Grails Spring安全核心:获取具有特定角色的用户
我正在尝试获取所有遵循特定标准且具有Grails Spring安全核心:获取具有特定角色的用户,grails,spring-security,Grails,Spring Security,我正在尝试获取所有遵循特定标准且具有角色的用户 标准: ArrayList<User> users = User.createCriteria().list() { inList("gender", whichGenderList) ne("uid", uid) profile { inList("age", whichAge) } firstResult(usersPerPage * currentPage) maxResults(usersPerP
角色的用户
标准:
ArrayList<User> users = User.createCriteria().list() {
inList("gender", whichGenderList)
ne("uid", uid)
profile {
inList("age", whichAge)
}
firstResult(usersPerPage * currentPage)
maxResults(usersPerPage)
}
ArrayList<User> users = User.createCriteria().list() {
inList("gender", whichGenderList)
ne("uid", uid)
role {
eq("authority","ROLE_USER")
}
profile {
inList("age", whichAge)
}
firstResult(usersPerPage * currentPage)
maxResults(usersPerPage)
}
ArrayList users=User.createCriteria().list(){
inList(“性别”,whichGenderList)
东北(“uid”,uid)
侧面图{
inList(“年龄”,whichAge)
}
第一个结果(usersPerPage*currentPage)
maxResults(usersPerPage)
}
问题:
是否可以在此条件中添加一个条件,仅选择具有角色的用户\u USER
我正在使用:
ArrayList<User> users = User.createCriteria().list() {
inList("gender", whichGenderList)
ne("uid", uid)
profile {
inList("age", whichAge)
}
firstResult(usersPerPage * currentPage)
maxResults(usersPerPage)
}
ArrayList<User> users = User.createCriteria().list() {
inList("gender", whichGenderList)
ne("uid", uid)
role {
eq("authority","ROLE_USER")
}
profile {
inList("age", whichAge)
}
firstResult(usersPerPage * currentPage)
maxResults(usersPerPage)
}
- Grails2.4.4
更新:
ArrayList<User> users = User.createCriteria().list() {
inList("gender", whichGenderList)
ne("uid", uid)
profile {
inList("age", whichAge)
}
firstResult(usersPerPage * currentPage)
maxResults(usersPerPage)
}
ArrayList<User> users = User.createCriteria().list() {
inList("gender", whichGenderList)
ne("uid", uid)
role {
eq("authority","ROLE_USER")
}
profile {
inList("age", whichAge)
}
firstResult(usersPerPage * currentPage)
maxResults(usersPerPage)
}
最小用户
表格:
角色
表格:
ArrayList<User> users = User.createCriteria().list() {
inList("gender", whichGenderList)
ne("uid", uid)
profile {
inList("age", whichAge)
}
firstResult(usersPerPage * currentPage)
maxResults(usersPerPage)
}
ArrayList<User> users = User.createCriteria().list() {
inList("gender", whichGenderList)
ne("uid", uid)
role {
eq("authority","ROLE_USER")
}
profile {
inList("age", whichAge)
}
firstResult(usersPerPage * currentPage)
maxResults(usersPerPage)
}
用户角色
表格:
ArrayList<User> users = User.createCriteria().list() {
inList("gender", whichGenderList)
ne("uid", uid)
profile {
inList("age", whichAge)
}
firstResult(usersPerPage * currentPage)
maxResults(usersPerPage)
}
ArrayList<User> users = User.createCriteria().list() {
inList("gender", whichGenderList)
ne("uid", uid)
role {
eq("authority","ROLE_USER")
}
profile {
inList("age", whichAge)
}
firstResult(usersPerPage * currentPage)
maxResults(usersPerPage)
}
ArrayList users=User.createCriteria().list(){
inList(“性别”,whichGenderList)
东北(“uid”,uid)
角色{
eq(“权限”、“角色\用户”)
}
侧面图{
inList(“年龄”,whichAge)
}
第一个结果(usersPerPage*currentPage)
maxResults(usersPerPage)
}
为什么您觉得这很难?它拥有所有标准的结构。你只需再添加一行eq(“角色”、“角色用户”)
@Suganthan我认为你不理解这个问题。:)根据您的建议,我得到的无法解析属性:角色:foo.User
。您能否发布您的域模型
,我认为只有映射是足够的,还有一点是永远不要在公共系统中共享原始数据。.我的用户
类上没有角色
属性。您可以看到域类。